(a)
The activity immediately after 782 µg of was ingested by a patient.
Answer to Problem 42P
Solution:
The activityimmediately after 782 µg of was ingested by a patient is 3.59×1012 decays/s.
Explanation of Solution
Given info:
782 µg of are ingested by a patient.
Formula used:
The activity ()is defined as:
(1)
Where:
• is called the decay constant
• is called the number of parent nuclei present at time t=0
• is the time elapsed
The decay ( )constant can be obtained using:
(2)
Where, is called the half-life of isotope. In this problem, the half-life ()for iodine isotope is 8.0207 days.
Calculation:
Convert the half-life()in seconds:
(3)
Replacing (3)into equation (2)we get:
(4)
Now, the atomic mass for is 131 g, therefore the initial number of parent nuclei ()is:
(5)
(b)
The activity 1.50 h later when the thyroid is being tested.
Answer to Problem 42P
Solution:
The activity 1.50 h later when the thyroid is being tested is 3.57x1012 decays/s.
Explanation of Solution
Calculation:
Convert the time elapsed in seconds as follows:
(8)
(c) To determine:
The activity 3.0 months later.
Answer to Problem 42P
Solution:
The activity 3.0 months later is 1.16×109 decays/s.
Explanation of Solution
Calculation:
Convert the time elapsed in seconds as follows:
(11)
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Physics: Principles with Applications
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