Explanation Introduction: The electron can be move from lower energy state to higher energy state by giving them some external energy. The external energy is gained by absorption of photons of required energy. This process of moving the electron to higher energy state is known as excitation of electrons. The electrons transit from lower energy state to higher energy state by absorbing energy in the form of photons. The materials emit various wavelengths of light which relates with the energy levels. In excitation process, the electrons excite from ground to higher state by absorption of photons in this florescence the electron the material. These excited atoms can be de-excited by several ways such as transition of electron to ground state by re-emits the same energy photons. This process is known as de-excitation. The fluorescence is a process in which excitation of molecules and atoms of given energy photon and de-excites by emission of a lower-energy photon. In de-excitation process if the photons emits in smaller steps by emitting energy of different from that excited it. Conclusion: Here, the electron excited from energy level 1 to energy level 8 . For the fluorescence effect by the electron it should be de-exited in smaller steps with lower energy from that excited it

OER 2016 Edition

ISBN: 9781947172173

Author: OpenStax

Publisher: OpenStax College

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The Bohr model

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Chapter 30, Problem 11TP

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The correct electron behavior represents the fluorescence effect by the atom.

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An electron is excited from the ground state of an atom (energy level 1) into a highly excited state (energy level 8). Which of the following electron behaviors represents the fluorescence effect by the atom? a. The electron remains at level 8 for a very long time, then transitions up to level 9. b. The electron transitions directly down from level 8 to level 1. c. The electron transitions from level 8 to level 1 and then returns quickly to level 8. d. The electron transitions from level 8 to level 6, then to level 5, then to level 3, then to level 1.

What happens when excited electrons return to the base state? A.There is emission of electrons which will be converted into photons by the photoelectric effect. B.There is a loss of heat and therefore a change in the color from fluorescence to cold colors (more to blue). C.There is a loss of vibrational energy and photon emission. D.There is a photon emission at the same wavelength as the excitatory photons.

1. An atom or molecule in the ground state of energy E1 can absorb a photon of energy hv and go the higher energy state E2, then the process is known as option : a. Stimulated absorption b. Spontaneous absorption c. Stimulated emission d. Stimulated radiation 2. Below are the techniques that usually used to measure optical losses in waveguides, except: a. Surface Plasmon b. Scattered light Measurement using Prism Coupler C. Sliding-Prism Method d. Cutback Method e. Fabry-Perot Resonances 3. What is the procedure in Top-down fabrication method? option : a. Powder -> Bulk-> Nanoparticles b. Nanoparticles -> Bulk -> Powder C.Bulk -> Powder -> Nanoparticles d. Nanoparticles -> Powder -> Bulk

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The correct electron behavior represents the fluorescence effect by the atom.

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