Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN: 9780133594140
Author: James Kurose, Keith Ross
Publisher: PEARSON
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Expert Solution & Answer
Chapter 3, Problem R1RQ
a)
Explanation of Solution
Step-by-step process of designing the simplest possible transport-layer protocol:
The STP (Simple Transport Protocol) takes for the process. The protocol takes the data not exceeding 1196 bytes at the sender side.
- The protocol accepts the four byte destination port number, host address, and a destination port address as a chunk which is not exceeding 1196 bytes.
- STP adds a four-byte header to each chunk and puts the port number of the destination in this header.
- The protocol then gives the destination host address and the resulting segment to the network layer.
- After receiving the address and segment, the network layer send the segment to STP at the destination host.
- STP then examines the segment and observes its port number and then the protocol extracts the data from the segment.
- The extracted data passes to the process of identified port number.
b)
Explanation of Solution
Modification:
Consider the segment has two header fields: one is “source port field” and another one is “destination port field”.
- At the source side, STP accepts the chunk of data which is not exceeding 1192 bytes. The data has destination host address, source port number, and a destination port number.
- Then, STP creates a segment which has application data, source port number, and destination port number.
- After creating segment, STP gives the two values to the network layer. They are: segment and destination port number.
- Then the STP receives host address and provides the process the source port number and the application data.
c)
Explanation of Solution
“No”, the transport layer does not do anything in the core of the
Explanation:
The reason is that the transport layer “lives” in the end systems.
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EXPLORER
OPEN EDITORS
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com.py...
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xcom.py
2
✓ DB
com.py
com.sql
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com.py
db
class Rectangle:
def _init_(self, length, width):
self.length-length
self.width-width
def area(self):
return
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def perimeter(self):
return
2+self.width*self.length
y=Rectangle(5,1)
print(y.area)
Why does an error appear in the
code
print(y.perimeter)
PROBLEMS
OUTPUT
TERMINAL
DEBUG CONSOLE
PORTS
I
> OUTLINE
> TIMELINE
0A4 0
self.width *self.length
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NameError: name 'self' is not defined
PS C:\Users\hp\Desktop\db> & C:/Users/hp/AppData/Local/Microsoft/WindowsApps/python3.12.exe c:/Users/hp/Desktop/db/com.py
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File "c:\Users\hp\Desktop\db\com.py", line 1, in
class Rectangle:
File "c:\Users\hp\Desktop\db\com.py", line 7, in Rectangle
self.width *self.length
^^^^^
NameError: name 'self' is not defined
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Ln 17, Col 1 Spaces: 4 UTF-8 CRLF (Python 3
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ENG
Refer to page 30 for problems on image edge detection.
Instructions:
Implement an edge detection algorithm (e.g., Sobel or Canny) for the given image.
• Explain the preprocessing steps (grayscale conversion, noise reduction) and calculate gradient
intensities.
• Visualize and compare the results with manual edge annotations.
Link: [https://drive.google.com/file/d/1wKSrun-GlxirS31Z9qoHazb9tC440 AZ F/view?usp=sharing]
Refer to page 100 for problems on 2D and 3D transformations.
Instructions:
Compute the result of applying a sequence of transformations (e.g., translation, rotation, scaling)
to a given shape.
Use homogeneous coordinates for matrix representation.
• Show all intermediate matrices and verify the final position of the shape.
Link: [https://drive.google.com/file/d/1wKSrun-GlxirS3IZ9qoHazb9tC440 AZF/view?usp=sharing]
Chapter 3 Solutions
Computer Networking: A Top-Down Approach (7th Edition)
Ch. 3 - Prob. R1RQCh. 3 - Prob. R2RQCh. 3 - Consider a TCP connection between Host A and Host...Ch. 3 - Prob. R4RQCh. 3 - Prob. R5RQCh. 3 - Prob. R6RQCh. 3 - Suppose a process in Host C has a UDP socket with...Ch. 3 - Prob. R8RQCh. 3 - Prob. R9RQCh. 3 - In our rdt protocols, why did we need to introduce...
Ch. 3 - Prob. R11RQCh. 3 - Prob. R12RQCh. 3 - Prob. R13RQCh. 3 - Prob. R14RQCh. 3 - Suppose Host A sends two TCP segments back to back...Ch. 3 - Prob. R16RQCh. 3 - Prob. R17RQCh. 3 - Prob. R18RQCh. 3 - Prob. R19RQCh. 3 - Prob. P1PCh. 3 - Prob. P2PCh. 3 - UDP and TCP use 1s complement for their checksums....Ch. 3 - Prob. P4PCh. 3 - Prob. P5PCh. 3 - Prob. P6PCh. 3 - Prob. P7PCh. 3 - Prob. P8PCh. 3 - Prob. P9PCh. 3 - Prob. P10PCh. 3 - Prob. P11PCh. 3 - Prob. P12PCh. 3 - Prob. P13PCh. 3 - Prob. P14PCh. 3 - Prob. P15PCh. 3 - Prob. P16PCh. 3 - Prob. P17PCh. 3 - Prob. P21PCh. 3 - Prob. P22PCh. 3 - Prob. P25PCh. 3 - Prob. P26PCh. 3 - Prob. P27PCh. 3 - Host A and B are directly connected with a 100...Ch. 3 - Prob. P29PCh. 3 - Prob. P30PCh. 3 - Prob. P31PCh. 3 - Prob. P33PCh. 3 - Prob. P34PCh. 3 - Prob. P35PCh. 3 - Prob. P37PCh. 3 - Prob. P38PCh. 3 - Prob. P39PCh. 3 - Prob. P41PCh. 3 - Prob. P42PCh. 3 - Prob. P43PCh. 3 - Prob. P44PCh. 3 - Prob. P45PCh. 3 - Prob. P46PCh. 3 - Prob. P47PCh. 3 - Prob. P48PCh. 3 - Prob. P49PCh. 3 - Prob. P51PCh. 3 - Prob. P53PCh. 3 - Prob. P55P
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