Chapter 3, Problem P44P

a.

Explanation of Solution

Given:

Let’s consider that “cwnd” will increase by 1 MSS when a collection of ACK’s received and assuming around continuous “round-trip” times.

• Then the transmission rate for TCP = “w” bytes/RTT
• The following steps are taken for “cwnd” to increase from “6 RTT” to “12 MSS”:
  • Takes 1 RTTs to increase “cwnd” to 7 MSS...

b.

Explanation of Solution

Given:

Connection up through time = 6 RTT

The sum of MSS that were sent up to 6 RTT $\text{= 6 + 7 + 8 + 9 + 10 + 11 }$

$\text{= 51}$

The average throughout $\text{= <}$