Sequence numbers inside the sender’s window: Given: Window size = Size = 4 Range = 1024 Case 1: Let’s consider the receiver is “K” and acknowledged all the “k-1” data packets. The sender side window’s range will be of [ k , k+ Size - 1 ] sequence numbers

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Answer 1

Expert Solution & Answer

Chapter 3, Problem P22P

a.

Explanation of Solution

Sequence numbers inside the sender’s window:

Given:

Window size = Size = 4

Range = 1024

Case 1:

Let’s consider the receiver is “K” and acknowledged all the “k-1” data packets. The sender side window’s range will be of [ k , k+ Size - 1 ] sequence numbers

b.

Explanation of Solution

Values of ACK field:

Suppose the receiver is waiting for the packet “k”, then it has been received and acknowledged “k-1” packet and the “Size-1” packets before that. If NACKs of those packets have not been received by the sender, then the values of ACK field is [ k - size , k - 1 ] may propagate back.

Because the sender has sent packets k - 1, it states that the sender had already received an acknowledgement for k - Size -1

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EXPLORER OPEN EDITORS Welcome com.py... Welcome xcom.py 2 ✓ DB com.py com.sql 6 8 9 10 11 12 13 14 15 16 17 com.py db class Rectangle: def _init_(self, length, width): self.length-length self.width-width def area(self): return self.width *self.length def perimeter(self): return 2+self.width*self.length y=Rectangle(5,1) print(y.area) Why does an error appear in the code print(y.perimeter) PROBLEMS OUTPUT TERMINAL DEBUG CONSOLE PORTS I > OUTLINE > TIMELINE 0A4 0 self.width *self.length AAAA NameError: name 'self' is not defined PS C:\Users\hp\Desktop\db> & C:/Users/hp/AppData/Local/Microsoft/WindowsApps/python3.12.exe c:/Users/hp/Desktop/db/com.py Traceback (most recent call last): File "c:\Users\hp\Desktop\db\com.py", line 1, in class Rectangle: File "c:\Users\hp\Desktop\db\com.py", line 7, in Rectangle self.width *self.length ^^^^^ NameError: name 'self' is not defined PS C:\Users\hp\Desktop\db> Ln 17, Col 1 Spaces: 4 UTF-8 CRLF (Python 3 A ENG

Refer to page 30 for problems on image edge detection. Instructions: Implement an edge detection algorithm (e.g., Sobel or Canny) for the given image. • Explain the preprocessing steps (grayscale conversion, noise reduction) and calculate gradient intensities. • Visualize and compare the results with manual edge annotations. Link: [https://drive.google.com/file/d/1wKSrun-GlxirS31Z9qoHazb9tC440 AZ F/view?usp=sharing]

Refer to page 100 for problems on 2D and 3D transformations. Instructions: Compute the result of applying a sequence of transformations (e.g., translation, rotation, scaling) to a given shape. Use homogeneous coordinates for matrix representation. • Show all intermediate matrices and verify the final position of the shape. Link: [https://drive.google.com/file/d/1wKSrun-GlxirS3IZ9qoHazb9tC440 AZF/view?usp=sharing]

Answer 2

Expert Solution & Answer

Chapter 3, Problem P22P

a.

Explanation of Solution

Sequence numbers inside the sender’s window:

Given:

Window size = Size = 4

Range = 1024

Case 1:

Let’s consider the receiver is “K” and acknowledged all the “k-1” data packets. The sender side window’s range will be of [ k , k+ Size - 1 ] sequence numbers

b.

Explanation of Solution

Values of ACK field:

Suppose the receiver is waiting for the packet “k”, then it has been received and acknowledged “k-1” packet and the “Size-1” packets before that. If NACKs of those packets have not been received by the sender, then the values of ACK field is [ k - size , k - 1 ] may propagate back.

Because the sender has sent packets k - 1, it states that the sender had already received an acknowledgement for k - Size -1

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 3

Expert Solution & Answer

Chapter 3, Problem P22P

a.

Explanation of Solution

Sequence numbers inside the sender’s window:

Given:

Window size = Size = 4

Range = 1024

Case 1:

Let’s consider the receiver is “K” and acknowledged all the “k-1” data packets. The sender side window’s range will be of [ k , k+ Size - 1 ] sequence numbers

b.

Explanation of Solution

Values of ACK field:

Suppose the receiver is waiting for the packet “k”, then it has been received and acknowledged “k-1” packet and the “Size-1” packets before that. If NACKs of those packets have not been received by the sender, then the values of ACK field is [ k - size , k - 1 ] may propagate back.

Because the sender has sent packets k - 1, it states that the sender had already received an acknowledgement for k - Size -1

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 4

Expert Solution & Answer

Chapter 3, Problem P22P

a.

Explanation of Solution

Sequence numbers inside the sender’s window:

Given:

Window size = Size = 4

Range = 1024

Case 1:

Let’s consider the receiver is “K” and acknowledged all the “k-1” data packets. The sender side window’s range will be of [ k , k+ Size - 1 ] sequence numbers

b.

Explanation of Solution

Values of ACK field:

Suppose the receiver is waiting for the packet “k”, then it has been received and acknowledged “k-1” packet and the “Size-1” packets before that. If NACKs of those packets have not been received by the sender, then the values of ACK field is [ k - size , k - 1 ] may propagate back.

Because the sender has sent packets k - 1, it states that the sender had already received an acknowledgement for k - Size -1

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 5

Expert Solution & Answer

Answer 6

Expert Solution & Answer

Answer 7

Chapter 3, Problem P22P

a.

Explanation of Solution

Sequence numbers inside the sender’s window:

Given:

Window size = Size = 4

Range = 1024

Case 1:

Let’s consider the receiver is “K” and acknowledged all the “k-1” data packets. The sender side window’s range will be of [ k , k+ Size - 1 ] sequence numbers

b.

Explanation of Solution

Values of ACK field:

Suppose the receiver is waiting for the packet “k”, then it has been received and acknowledged “k-1” packet and the “Size-1” packets before that. If NACKs of those packets have not been received by the sender, then the values of ACK field is [ k - size , k - 1 ] may propagate back.

Because the sender has sent packets k - 1, it states that the sender had already received an acknowledgement for k - Size -1

Answer 8

Chapter 3, Problem P22P

a.

Explanation of Solution

Sequence numbers inside the sender’s window:

Given:

Window size = Size = 4

Range = 1024

Case 1:

Let’s consider the receiver is “K” and acknowledged all the “k-1” data packets. The sender side window’s range will be of [ k , k+ Size - 1 ] sequence numbers

Answer 9

Chapter 3, Problem P22P

a.

Explanation of Solution

Sequence numbers inside the sender’s window:

Given:

Window size = Size = 4

Range = 1024

Case 1:

Let’s consider the receiver is “K” and acknowledged all the “k-1” data packets. The sender side window’s range will be of [ k , k+ Size - 1 ] sequence numbers

Answer 10

b.

Explanation of Solution

Values of ACK field:

Suppose the receiver is waiting for the packet “k”, then it has been received and acknowledged “k-1” packet and the “Size-1” packets before that. If NACKs of those packets have not been received by the sender, then the values of ACK field is [ k - size , k - 1 ] may propagate back.

Because the sender has sent packets k - 1, it states that the sender had already received an acknowledgement for k - Size -1

Answer 11

b.

Explanation of Solution

Values of ACK field:

Suppose the receiver is waiting for the packet “k”, then it has been received and acknowledged “k-1” packet and the “Size-1” packets before that. If NACKs of those packets have not been received by the sender, then the values of ACK field is [ k - size , k - 1 ] may propagate back.

Because the sender has sent packets k - 1, it states that the sender had already received an acknowledgement for k - Size -1

Answer 12

Expert Solution & Answer

Answer 13

Expert Solution & Answer

Answer 14

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Answer 15

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Sequence numbers inside the sender’s window: Given: Window size = Size = 4 Range = 1024 Case 1: Let’s consider the receiver is “K” and acknowledged all the “k-1” data packets. The sender side window’s range will be of [ k , k+ Size - 1 ] sequence numbers

Solution Summary: The author explains the range of sequence numbers inside the sender's window.

Explanation of Solution

Sequence numbers inside the sender’s window:

Given:

Window size = Size = 4

Range = 1024

Case 1:

Let’s consider the receiver is “K” and acknowledged all the “k-1” data packets. The sender side window’s range will be of [ k , k+ Size - 1 ] sequence numbers

Explanation of Solution

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Chapter 3 Solutions