BASIC BIOMECHANICS
BASIC BIOMECHANICS
8th Edition
ISBN: 9781259913877
Author: Hall
Publisher: RENT MCG
Question
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Chapter 3, Problem 9AP
Summary Introduction

To determine: The density of different objects and rank them in the order of their densities.

Expert Solution & Answer
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Answer to Problem 9AP

The density of the object A is 12,244lb/ft3, object B is 212,376lb/ft3, object C is 64lb/ft3, object D is 20lb/ft3, and object E is 93,714lb/ft3. Hence, the objects are arranged in the order of higher densities to lower as DB>DE>DA>DC>DD.

Explanation of Solution

Calculation:

Write an expression to find the density of object A.

DA=MassVolume

Here, DA is the volume of the object A.

Substitute 50 kg for mass and 15.00in3 for volume to find the density of the object A.

DA=50kg15.00in3=50kg(2.20462lb1kg)15.00in3((0.0833ft)3(1in)3)=110.2lb0.009ft312,244lb/ft3

Therefore, the density of the object A is 12,244lb/ft3.

Write an expression to find the density of object B.

DB=MassVolume

Here, DB is the volume of the object B.

Substitute 90 lb for mass and 12.00cm3 for volume to find the density of the object B.

DB=90lb12.00cm3=90lb12.00cm3((0.0328ft)3(1cm)3)=90lb0.004ft3212,376lb/ft3

Therefore, the density of the object B is 212,376lb/ft3.

Write an expression to find the density of object C.

DC=MassVolume

Here, DC is the volume of the object C.

Substitute 3 slugs for mass and 1.50ft3 for volume to find the density of the object C.

DC=3slugs1.50ft3=3slugs(32.174lb1slugs)1.50ft3=96.522lb1.50ft364lb/ft3

Therefore, the density of the object C is 64lb/ft3.

Write an expression to find the density of object D.

DD=MassVolume

Here, DD is the volume of the object D.

Substitute 450 N for mass and 0.14m3 for volume to find the density of the object D.DD=450N0.14m3=450N(0.2248lb1N)0.14m3((3.28084ft)31m3)=101.16lb4.944ft320lb/ft3

Therefore, the density of the object D is 20lb/ft3.

Write an expression to find the density of object E.

DE=MassVolume

Here, DE is the volume of the object E.

Substitute 45 kg for mass and 30.00cm3 for volume to find the density of the object E.

DE=45kg30.00cm3=45kg(2.20462lb1kg)30.00in3((0.0328ft)3(1cm)3)=99.2lb0.001ft393,714lb/ft3

Therefore, the density of the object E is 93,714lb/ft3.

Conclusion

Therefore, the density of the object A is 12,244lb/ft3, object B is 212,376lb/ft3, object C is 64lb/ft3, object D is 20lb/ft3, and object E is 93,714lb/ft3. Hence, the objects are arranged in the order of higher densities to lower as DB>DE>DA>DC>DD.

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