BASIC BIOMECHANICS
8th Edition
ISBN: 9781259913877
Author: Hall
Publisher: RENT MCG
expand_more
expand_more
format_list_bulleted
Concept explainers
Textbook Question
Chapter 3, Problem 3AP
A football player is contacted by two tacklers simultaneously. Tackler A exerts a force of 400 N, and tackler B exerts a force of 375 N. If the forces are coplanar and directed perpendicular to each other, what is the magnitude and direction of the resultant force acting on the player? (Answer 548 N at an angle of 43° to the line of action of tackler A)
Expert Solution & Answer
Trending nowThis is a popular solution!
Students have asked these similar questions
A) Describe the difference between strength and power during a squat. Provide a quantitative example that illustrates the difference.
B) During a squat, the weight you have on your shoulders has a certain amount of gravitational potential energy. As you squat down and come to a stop at the bottom of the squat, some of that energy is lost. Where does it go?
2. a) Label the system provided below, including the reference frame, moment arms and vector forces
with the information provided.
Internal moment arm = 4cm +0.04m
External moment arm relative
to the segment weight = 25cm 0.25m
External moment arm relative
to the load weight = 45cm 40.45m
Segment weight = 50 N
Load weight = 100 N
Lower leg segment angle relative
to horizontal plane = 45°
Quadriceps tendon angle = 45°
Axis of
rotation
MF
SW
LW
2b) Using the figure in 2a., calculate the external torque of the system relative to the normal
component of segment and load weights listed above.
2c) Calculate the amount of both the tangential component of the muscle force and the muscle force
itself required to keep this system in a state of static equilibrium.
The adjacent diagram displays the joint reaction force between the acetabulum and femoral head for the right leg during single leg stance. Also shown are the abductor muscle force (AMF), the weight of the body above the level of the stance hip (W) and their corresponding moment arms with respect to the joint centre (D and D1). If the right leg weighs 1/6 of total body weight, the ratio of D1 to D is 2.4, and AMF is angled at 30 degrees relative to the vertical, calculate the:
Abductor muscle force (2 marks).
Hip joint reaction force (2 marks).
Express both answers as multiples of total body weight
Chapter 3 Solutions
BASIC BIOMECHANICS
Ch. 3 - Prob. 1IPCh. 3 - How much force must be applied to a 0.5-kg hockey...Ch. 3 - A rugby player is contacted simultaneously by...Ch. 3 - Prob. 4IPCh. 3 - Draw the horizontal and vertical components of the...Ch. 3 - A gymnastics floor mat weighing 220 N has...Ch. 3 - What is the volume of a milk crate with sides of...Ch. 3 - Prob. 8IPCh. 3 - If the contents of the crate described in Problem...Ch. 3 - Two children sit on opposite sides of a playground...
Ch. 3 - Prob. 1APCh. 3 - Gravitational force on planet X is 40% of that...Ch. 3 - A football player is contacted by two tacklers...Ch. 3 - A 75-kg skydiver in free fall is subjected to a...Ch. 3 - Use a trigonometric solution to find the magnitude...Ch. 3 - Prob. 6APCh. 3 - In the nucleus pulposus of an intervertebral disc,...Ch. 3 - Prob. 9APCh. 3 - Two muscles develop tension simultaneously on...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, bioengineering and related others by exploring similar questions and additional content below.Similar questions
- With the shoulder flexed at 30°, the moment arm of the deltoid muscle is 2.0 cm. Solve for the force exerted by the deltoid muscle at the glenohumeral joint give the following assumptions: The deltoid is the only active muscle at the glenohumeral joint The weight of the humerus is 48 N. The center of gravity of the humerus is located 30 cm from the shoulder center of rotation STATIC EQUILIBRIUM EQUATIONS CONSIDERING ONLY THE DELTOID MUSCLE Fo MA = 18 Cn COR B=55". 0-30° RaF 30 cm FG = 24 Narrow_forwardGiven the following ankle and knee coordinates calculate the partial internal knee angle to 1 decimal place Ankle z 0.129 m Ankle x 0.37 m Knee z 0.409 m Knee x 0.522 m Answer: re to search 8: T G B N W 8 M 9 O Pa P 4 3°C℃ Partly cloudyarrow_forwardAccording to the free-body diagram, which forces act on both teams and rope before motion begins and in which directions?arrow_forwardTwo lifter's knees are of interest at a specific moment in their lifts. In both lifts, the knee extensor torque is 100 Nm, requiring quadriceps tendon/patella ligament forces of 1000 N (about 220 Ibs). Despite equivalent knee torques and quadriceps forces, patellofemoral joint forces are higher on the knees of lifter A. Briefly explain why. Edit View Insert Format Tools Table 12pt v Paragraph v BIUAarrow_forwardWhat is the relationship between Net force, mass and acceleration. Newton’s second law of motion?arrow_forwardHow much force must be produced by the biceps brachii, attaching at 90? to the radius at 3 cm from the center of rotation at the elbow joint, to support a weight of 200 N held in the hand at a distance of 30 cm from the elbow joint? (Neglect the weight of the forearm and hand, and neglect any action of other muscles)arrow_forwardDetermine the angle of the shoulder if the torso angle is 88\deg and the upper-arm angle is -125\deg. This answer is this 33\deg BUT how do you calculate this to get that answer??arrow_forwardIf an individual does training with only the right knee extensor muscles, it is common to see increase in strength in knee extension force for the right leg and an increase in strength in the knee extension force of the left leg (although the increase in force is typically not to the same extent as the force increase in the right leg) a.) True b.) Falsearrow_forwardList the three types of van der Waals forces in decreasing order of strength.arrow_forward< The three main forces that act on the patella are shown on the diagram of the knee joint below. These forces are the quadriceps muscle force (FQ), the patella ligament force (FPL), and the patellofemoral joint reaction force (FPF). The angles a and ẞ are with respect to a line that is perpendicular to FPF. Assuming a = 15°, ẞ = 20°, and FQ = 3725 N, use equations for static equilibrium to calculate (a) FPL, and (b) FPF. (Hint: To solve this problem consider using a coordinate system that is aligned with the principal axes of the patella instead of the usual vertical and horizontal axes). (c) Many people assume FQ and FPL are always equal in magnitude but this is only true under certain circumstances. Under what conditions are FQ and FPL equal in magnitude? Fo FPF FP B GriffithUNIVERSITY Queensland Australiaarrow_forwardDefine the following parameters that can be assessed via isokinetic dynamometry (attempt to use your own words after reviewing data sheet): Peak Torque Time to peak torque Angle of peak torque Torque at 0.2 seconds Peak torque/body weight Total work Work fatigue (Fatigue Index) Average powerarrow_forwardGive two example of 'curvature' movement?arrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
Recommended textbooks for you
- Basic BiomechanicsBioengineeringISBN:9780073522760Author:Susan J HallPublisher:McGraw-Hill Education
Basic Biomechanics
Bioengineering
ISBN:9780073522760
Author:Susan J Hall
Publisher:McGraw-Hill Education
Chapter 7 - Human Movement Science; Author: Dr. Jeff Williams;https://www.youtube.com/watch?v=LlqElkn4PA4;License: Standard youtube license