Glencoe Physical Science 2012 Student Edition (Glencoe Science) (McGraw-Hill Education)
1st Edition
ISBN: 9780078945830
Author: Charles William McLaughlin, Marilyn Thompson, Dinah Zike
Publisher: Glencoe Mcgraw-Hill
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
Chapter 3, Problem 45R
To determine
The object that wasaggeted the most by the air resistance.
Expert Solution & Answer
Explanation of Solution
Introduction:
When a body moves, the kind of force that acts opposite direction of the motion of the body is known as air resistance.It decreases the velocity of the object every moment and increases the time of fall.
From the given objects A, B, C and D, the object A has the maximum value of time of fall because during the fall, the air resistance acts opposite to the direction of motion. Lager amount of air resistance will act means the body will take more time to fall. Therefore, the object A is aggeted the most by the air resistance.
Conclusion:
Therefore, object A is aggeted the most by the air resistance.
Chapter 3 Solutions
Glencoe Physical Science 2012 Student Edition (Glencoe Science) (McGraw-Hill Education)
Ch. 3.1 - Prob. 1PPCh. 3.1 - Prob. 2PPCh. 3.1 - Prob. 3PPCh. 3.1 - Prob. 4RCh. 3.1 - Prob. 5RCh. 3.1 - Prob. 6RCh. 3.1 - Prob. 7RCh. 3.1 - Prob. 8RCh. 3.1 - Prob. 9RCh. 3.1 - Prob. 10R
Ch. 3.2 - Prob. 11PPCh. 3.2 - Prob. 12PPCh. 3.2 - Prob. 13PPCh. 3.2 - Prob. 14PPCh. 3.2 - Prob. 15RCh. 3.2 - Prob. 16RCh. 3.2 - Prob. 17RCh. 3.2 - Prob. 18RCh. 3.2 - Prob. 19RCh. 3.2 - Prob. 20RCh. 3.2 - Prob. 21RCh. 3.3 - Prob. 22RCh. 3.3 - Prob. 23RCh. 3.3 - Prob. 24RCh. 3.3 - Prob. 25RCh. 3.3 - Prob. 26RCh. 3.3 - Prob. 27RCh. 3.3 - Prob. 28RCh. 3 - Prob. 29RCh. 3 - Prob. 30RCh. 3 - Prob. 31RCh. 3 - Prob. 32RCh. 3 - Prob. 33RCh. 3 - Prob. 34RCh. 3 - Prob. 35RCh. 3 - Prob. 36RCh. 3 - Prob. 37RCh. 3 - Prob. 38RCh. 3 - Prob. 39RCh. 3 - Prob. 40RCh. 3 - Prob. 41RCh. 3 - Prob. 42RCh. 3 - Prob. 43RCh. 3 - Prob. 44RCh. 3 - Prob. 45RCh. 3 - Prob. 46RCh. 3 - Prob. 47RCh. 3 - Prob. 48RCh. 3 - Prob. 49RCh. 3 - Prob. 50RCh. 3 - Prob. 51RCh. 3 - Prob. 52RCh. 3 - Prob. 53RCh. 3 - Prob. 54RCh. 3 - Prob. 55RCh. 3 - Prob. 56RCh. 3 - Prob. 1STPCh. 3 - Prob. 2STPCh. 3 - Prob. 3STPCh. 3 - Prob. 4STPCh. 3 - Prob. 5STPCh. 3 - Prob. 6STPCh. 3 - Prob. 7STPCh. 3 - Prob. 8STPCh. 3 - Prob. 9STPCh. 3 - Prob. 10STPCh. 3 - Prob. 11STPCh. 3 - Prob. 12STPCh. 3 - Prob. 13STPCh. 3 - Prob. 14STPCh. 3 - Prob. 15STPCh. 3 - Prob. 16STPCh. 3 - Prob. 17STPCh. 3 - Prob. 18STP
Additional Science Textbook Solutions
Find more solutions based on key concepts
Calculate the lattice energy of CaCl2 using a Born-Haber cycle and data from Appendices F and L and Table 7.5. ...
Chemistry & Chemical Reactivity
Why was Whler astonished to find he had made urea?
Campbell Biology (11th Edition)
10.71 Identify each of the following as an acid or a base: (10.1)
H2SO4
RbOH
Ca(OH)2
HI
...
Chemistry: An Introduction to General, Organic, and Biological Chemistry (13th Edition)
Answer the following questions for each compound: a. How many signals are in its 13C NMR spectrum? b. Which sig...
Organic Chemistry (8th Edition)
26. You want to estimate the diameter of a very small circular pinhole that you’ve made in a piece of aluminum ...
College Physics: A Strategic Approach (3rd Edition)
Which one of the following is not a fuel produced by microorganisms? a. algal oil b. ethanol c. hydrogen d. met...
Microbiology: An Introduction
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- Example Two charges, one with +10 μC of charge, and another with - 7.0 μC of charge are placed in line with each other and held at a fixed distance of 0.45 m. Where can you put a 3rd charge of +5 μC, so that the net force on the 3rd charge is zero?arrow_forward* Coulomb's Law Example Three charges are positioned as seen below. Charge 1 is +2.0 μC and charge 2 is +8.0μC, and charge 3 is - 6.0MC. What is the magnitude and the direction of the force on charge 2 due to charges 1 and 3? 93 kq92 F == 2 r13 = 0.090m 91 r12 = 0.12m 92 Coulomb's Constant: k = 8.99x10+9 Nm²/C² ✓arrow_forwardMake sure to draw a Free Body Diagram as wellarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
University Physics (14th Edition)PhysicsISBN:9780133969290Author:Hugh D. Young, Roger A. FreedmanPublisher:PEARSON
Introduction To Quantum MechanicsPhysicsISBN:9781107189638Author:Griffiths, David J., Schroeter, Darrell F.Publisher:Cambridge University Press
Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Lecture- Tutorials for Introductory AstronomyPhysicsISBN:9780321820464Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina BrissendenPublisher:Addison-Wesley
College Physics: A Strategic Approach (4th Editio...PhysicsISBN:9780134609034Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart FieldPublisher:PEARSON
College Physics
Physics
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
University Physics (14th Edition)
Physics
ISBN:9780133969290
Author:Hugh D. Young, Roger A. Freedman
Publisher:PEARSON
Introduction To Quantum Mechanics
Physics
ISBN:9781107189638
Author:Griffiths, David J., Schroeter, Darrell F.
Publisher:Cambridge University Press
Physics for Scientists and Engineers
Physics
ISBN:9781337553278
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:9780321820464
Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:Addison-Wesley
College Physics: A Strategic Approach (4th Editio...
Physics
ISBN:9780134609034
Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:PEARSON
General Relativity: The Curvature of Spacetime; Author: Professor Dave Explains;https://www.youtube.com/watch?v=R7V3koyL7Mc;License: Standard YouTube License, CC-BY