Chapter 3, Problem 10STP

To determine

The acceleration of the sky diver five second after the jumping.

Answer to Problem 10STP

The acceleration of the sky diver five second after the jumping is $50{\text{m/s}}^{\text{2}}$ .

Explanation of Solution

Given info:

Mass of sky diver, $m=60\text{kg}$

Force of air resistance on the sky diver, $F=300\text{N}$

Formula used:

The formulae used for acceleration is given by,

  $a=\frac{F}{m}$

Calculation:

Write the equation to calculate the acceleration of sky diver.

  $a=\frac{F}{m}$

Here,

• $a$ is the acceleration of the sky diver.
• $F$ is the resistance force of the air.
• $m$ is the mass of the sky diver.

Substitute the given values in the above equation.

  $\begin{array}{c}a=\frac{F}{m}\\ =\frac{300}{60}\\ =50{\text{m/s}}^{\text{2}}\end{array}$

Conclusion:

Hence, the acceleration of the sky diver five second after the jumpingis $50{\text{m/s}}^{\text{2}}$ .