CHEMICAL PRINCIPLES PKG W/SAPLING
7th Edition
ISBN: 9781319086411
Author: ATKINS
Publisher: MAC HIGHER
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 3, Problem 3H.15E
(a)
Interpretation Introduction
Interpretation:
Mass of each unit cell in silicon has to be determined.
Concept Introduction:
Unit cell represents lattice structure if it stacked together repeatedly with no gaps and rotations. This can also produce whole crystals by stacking method. Basic type of unit cells is as follows:
1. Simple cubic (SC).
2. Body centered cubic (BCC).
3. Face centered cubic (FCC).
(b)
Interpretation Introduction
Interpretation:
Atoms of silicon in each unit cell have to be determined.
Concept Introduction:
Refer to part (a).
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
A cubic unit cell contains manganese ions at the corners and fluoride ions at the center of each edge.(a) What is the empirical formula of this compound? Explain your answer.(b) What is the coordination number of the Mn3+ ion?(c) Calculate the edge length of the unit cell if the radius of a Mn3+ ion is 0.65 A.(d) Calculate the density of the compound.
A metal crystallizes in the face-cente red cubic crystal structure with a unit cell edge of 4.08 x 10 -8 cm. The density of the metal is 19.3 g/cc. (a) What is the mass, in grams, of a single atom of this element? (b) What is the atomic weight of the element (g/mol). (c) What is the radius, in cm, of an atom of the element?
At room temperature, the edge length of the cubic unit cell in elemental silicon is 5.431 Å, and the density of silicon at the same temperature is 2.328 g cm-3 . Each cubic unit cell contains eight silicon atoms. Using only these facts, perform the following operations.(a) Calculate the volume (in cubic centimeters) of one unit cell.(b) Calculate the mass (in grams) of silicon present in a unit cell.(c) Calculate the mass (in grams) of an atom of silicon.(d) The mass of an atom of silicon is 28.0855 u. Estimate Avogadro’s number to four significant figures.
Chapter 3 Solutions
CHEMICAL PRINCIPLES PKG W/SAPLING
Ch. 3 - Prob. 3A.1ASTCh. 3 - Prob. 3A.1BSTCh. 3 - Prob. 3A.2ASTCh. 3 - Prob. 3A.2BSTCh. 3 - Prob. 3A.3ASTCh. 3 - Prob. 3A.3BSTCh. 3 - Prob. 3A.1ECh. 3 - Prob. 3A.2ECh. 3 - Prob. 3A.3ECh. 3 - Prob. 3A.4E
Ch. 3 - Prob. 3A.5ECh. 3 - Prob. 3A.6ECh. 3 - Prob. 3A.7ECh. 3 - Prob. 3A.8ECh. 3 - Prob. 3A.9ECh. 3 - Prob. 3A.10ECh. 3 - Prob. 3B.1ASTCh. 3 - Prob. 3B.1BSTCh. 3 - Prob. 3B.2ASTCh. 3 - Prob. 3B.2BSTCh. 3 - Prob. 3B.3ASTCh. 3 - Prob. 3B.3BSTCh. 3 - Prob. 3B.4ASTCh. 3 - Prob. 3B.4BSTCh. 3 - Prob. 3B.5ASTCh. 3 - Prob. 3B.5BSTCh. 3 - Prob. 3B.6ASTCh. 3 - Prob. 3B.6BSTCh. 3 - Prob. 3B.7ASTCh. 3 - Prob. 3B.7BSTCh. 3 - Prob. 3B.8ASTCh. 3 - Prob. 3B.8BSTCh. 3 - Prob. 3B.1ECh. 3 - Prob. 3B.2ECh. 3 - Prob. 3B.5ECh. 3 - Prob. 3B.6ECh. 3 - Prob. 3B.9ECh. 3 - Prob. 3B.10ECh. 3 - Prob. 3B.11ECh. 3 - Prob. 3B.12ECh. 3 - Prob. 3B.13ECh. 3 - Prob. 3B.14ECh. 3 - Prob. 3B.15ECh. 3 - Prob. 3B.16ECh. 3 - Prob. 3B.17ECh. 3 - Prob. 3B.18ECh. 3 - Prob. 3B.19ECh. 3 - Prob. 3B.20ECh. 3 - Prob. 3B.21ECh. 3 - Prob. 3B.22ECh. 3 - Prob. 3B.23ECh. 3 - Prob. 3B.24ECh. 3 - Prob. 3B.25ECh. 3 - Prob. 3B.26ECh. 3 - Prob. 3B.27ECh. 3 - Prob. 3B.28ECh. 3 - Prob. 3B.29ECh. 3 - Prob. 3B.30ECh. 3 - Prob. 3B.31ECh. 3 - Prob. 3B.32ECh. 3 - Prob. 3B.33ECh. 3 - Prob. 3B.34ECh. 3 - Prob. 3B.35ECh. 3 - Prob. 3B.36ECh. 3 - Prob. 3B.37ECh. 3 - Prob. 3B.38ECh. 3 - Prob. 3B.39ECh. 3 - Prob. 3B.40ECh. 3 - Prob. 3B.41ECh. 3 - Prob. 3B.42ECh. 3 - Prob. 3C.1ASTCh. 3 - Prob. 3C.1BSTCh. 3 - Prob. 3C.2ASTCh. 3 - Prob. 3C.2BSTCh. 3 - Prob. 3C.3ASTCh. 3 - Prob. 3C.3BSTCh. 3 - Prob. 3C.1ECh. 3 - Prob. 3C.2ECh. 3 - Prob. 3C.3ECh. 3 - Prob. 3C.4ECh. 3 - Prob. 3C.5ECh. 3 - Prob. 3C.6ECh. 3 - Prob. 3C.7ECh. 3 - Prob. 3C.8ECh. 3 - Prob. 3C.9ECh. 3 - Prob. 3C.10ECh. 3 - Prob. 3C.11ECh. 3 - Prob. 3C.12ECh. 3 - Prob. 3C.13ECh. 3 - Prob. 3C.14ECh. 3 - Prob. 3C.15ECh. 3 - Prob. 3C.16ECh. 3 - Prob. 3D.1ASTCh. 3 - Prob. 3D.1BSTCh. 3 - Prob. 3D.2ASTCh. 3 - Prob. 3D.2BSTCh. 3 - Prob. 3D.1ECh. 3 - Prob. 3D.2ECh. 3 - Prob. 3D.3ECh. 3 - Prob. 3D.4ECh. 3 - Prob. 3D.5ECh. 3 - Prob. 3D.6ECh. 3 - Prob. 3D.7ECh. 3 - Prob. 3D.8ECh. 3 - Prob. 3D.9ECh. 3 - Prob. 3D.10ECh. 3 - Prob. 3D.11ECh. 3 - Prob. 3D.12ECh. 3 - Prob. 3D.13ECh. 3 - Prob. 3D.14ECh. 3 - Prob. 3D.15ECh. 3 - Prob. 3D.16ECh. 3 - Prob. 3D.17ECh. 3 - Prob. 3D.18ECh. 3 - Prob. 3E.1ASTCh. 3 - Prob. 3E.1BSTCh. 3 - Prob. 3E.1ECh. 3 - Prob. 3E.2ECh. 3 - Prob. 3E.3ECh. 3 - Prob. 3E.4ECh. 3 - Prob. 3E.5ECh. 3 - Prob. 3E.6ECh. 3 - Prob. 3E.7ECh. 3 - Prob. 3E.8ECh. 3 - Prob. 3E.9ECh. 3 - Prob. 3E.10ECh. 3 - Prob. 3E.13ECh. 3 - Prob. 3E.14ECh. 3 - Prob. 3F.1ASTCh. 3 - Prob. 3F.1BSTCh. 3 - Prob. 3F.2ASTCh. 3 - Prob. 3F.2BSTCh. 3 - Prob. 3F.3ASTCh. 3 - Prob. 3F.3BSTCh. 3 - Prob. 3F.1ECh. 3 - Prob. 3F.2ECh. 3 - Prob. 3F.3ECh. 3 - Prob. 3F.4ECh. 3 - Prob. 3F.5ECh. 3 - Prob. 3F.6ECh. 3 - Prob. 3F.7ECh. 3 - Prob. 3F.8ECh. 3 - Prob. 3F.9ECh. 3 - Prob. 3F.10ECh. 3 - Prob. 3F.11ECh. 3 - Prob. 3F.12ECh. 3 - Prob. 3F.13ECh. 3 - Prob. 3F.14ECh. 3 - Prob. 3F.15ECh. 3 - Prob. 3F.16ECh. 3 - Prob. 3F.17ECh. 3 - Prob. 3F.18ECh. 3 - Prob. 3F.19ECh. 3 - Prob. 3F.20ECh. 3 - Prob. 3F.21ECh. 3 - Prob. 3F.22ECh. 3 - Prob. 3G.1ECh. 3 - Prob. 3G.2ECh. 3 - Prob. 3G.3ECh. 3 - Prob. 3G.4ECh. 3 - Prob. 3G.5ECh. 3 - Prob. 3G.6ECh. 3 - Prob. 3G.7ECh. 3 - Prob. 3G.8ECh. 3 - Prob. 3G.9ECh. 3 - Prob. 3G.10ECh. 3 - Prob. 3G.11ECh. 3 - Prob. 3G.12ECh. 3 - Prob. 3G.13ECh. 3 - Prob. 3G.14ECh. 3 - Prob. 3G.15ECh. 3 - Prob. 3G.16ECh. 3 - Prob. 3G.17ECh. 3 - Prob. 3G.18ECh. 3 - Prob. 3H.1ASTCh. 3 - Prob. 3H.1BSTCh. 3 - Prob. 3H.2ASTCh. 3 - Prob. 3H.2BSTCh. 3 - Prob. 3H.3ASTCh. 3 - Prob. 3H.3BSTCh. 3 - Prob. 3H.4ASTCh. 3 - Prob. 3H.4BSTCh. 3 - Prob. 3H.5ASTCh. 3 - Prob. 3H.5BSTCh. 3 - Prob. 3H.1ECh. 3 - Prob. 3H.2ECh. 3 - Prob. 3H.3ECh. 3 - Prob. 3H.4ECh. 3 - Prob. 3H.5ECh. 3 - Prob. 3H.6ECh. 3 - Prob. 3H.7ECh. 3 - Prob. 3H.8ECh. 3 - Prob. 3H.9ECh. 3 - Prob. 3H.10ECh. 3 - Prob. 3H.11ECh. 3 - Prob. 3H.12ECh. 3 - Prob. 3H.13ECh. 3 - Prob. 3H.14ECh. 3 - Prob. 3H.15ECh. 3 - Prob. 3H.16ECh. 3 - Prob. 3H.17ECh. 3 - Prob. 3H.19ECh. 3 - Prob. 3H.20ECh. 3 - Prob. 3H.23ECh. 3 - Prob. 3H.24ECh. 3 - Prob. 3H.25ECh. 3 - Prob. 3H.26ECh. 3 - Prob. 3H.27ECh. 3 - Prob. 3H.28ECh. 3 - Prob. 3H.29ECh. 3 - Prob. 3H.30ECh. 3 - Prob. 3H.31ECh. 3 - Prob. 3H.32ECh. 3 - Prob. 3H.33ECh. 3 - Prob. 3H.34ECh. 3 - Prob. 3H.35ECh. 3 - Prob. 3H.36ECh. 3 - Prob. 3I.1ASTCh. 3 - Prob. 3I.1BSTCh. 3 - Prob. 3I.2ASTCh. 3 - Prob. 3I.2BSTCh. 3 - Prob. 3I.3ASTCh. 3 - Prob. 3I.3BSTCh. 3 - Prob. 3I.4ASTCh. 3 - Prob. 3I.4BSTCh. 3 - Prob. 3I.1ECh. 3 - Prob. 3I.2ECh. 3 - Prob. 3I.3ECh. 3 - Prob. 3I.4ECh. 3 - Prob. 3I.5ECh. 3 - Prob. 3I.6ECh. 3 - Prob. 3I.7ECh. 3 - Prob. 3I.8ECh. 3 - Prob. 3I.11ECh. 3 - Prob. 3I.12ECh. 3 - Prob. 3I.13ECh. 3 - Prob. 3I.14ECh. 3 - Prob. 3I.15ECh. 3 - Prob. 3I.16ECh. 3 - Prob. 3J.1ASTCh. 3 - Prob. 3J.1BSTCh. 3 - Prob. 3J.2ASTCh. 3 - Prob. 3J.2BSTCh. 3 - Prob. 3J.3ASTCh. 3 - Prob. 3J.3BSTCh. 3 - Prob. 3J.1ECh. 3 - Prob. 3J.2ECh. 3 - Prob. 3J.3ECh. 3 - Prob. 3J.4ECh. 3 - Prob. 3J.5ECh. 3 - Prob. 3J.6ECh. 3 - Prob. 3J.7ECh. 3 - Prob. 3J.8ECh. 3 - Prob. 3J.9ECh. 3 - Prob. 3J.10ECh. 3 - Prob. 3J.11ECh. 3 - Prob. 3J.12ECh. 3 - Prob. 3J.13ECh. 3 - Prob. 3J.14ECh. 3 - Prob. 3J.15ECh. 3 - Prob. 3J.16ECh. 3 - Prob. 3.1ECh. 3 - Prob. 3.2ECh. 3 - Prob. 3.3ECh. 3 - Prob. 3.4ECh. 3 - Prob. 3.5ECh. 3 - Prob. 3.6ECh. 3 - Prob. 3.7ECh. 3 - Prob. 3.8ECh. 3 - Prob. 3.9ECh. 3 - Prob. 3.10ECh. 3 - Prob. 3.11ECh. 3 - Prob. 3.12ECh. 3 - Prob. 3.13ECh. 3 - Prob. 3.15ECh. 3 - Prob. 3.18ECh. 3 - Prob. 3.19ECh. 3 - Prob. 3.23ECh. 3 - Prob. 3.24ECh. 3 - Prob. 3.25ECh. 3 - Prob. 3.26ECh. 3 - Prob. 3.27ECh. 3 - Prob. 3.29ECh. 3 - Prob. 3.31ECh. 3 - Prob. 3.32ECh. 3 - Prob. 3.35ECh. 3 - Prob. 3.36ECh. 3 - Prob. 3.37ECh. 3 - Prob. 3.38ECh. 3 - Prob. 3.40ECh. 3 - Prob. 3.41ECh. 3 - Prob. 3.42ECh. 3 - Prob. 3.45ECh. 3 - Prob. 3.47ECh. 3 - Prob. 3.49ECh. 3 - Prob. 3.50ECh. 3 - Prob. 3.51ECh. 3 - Prob. 3.53ECh. 3 - Prob. 3.54ECh. 3 - Prob. 3.55ECh. 3 - Prob. 3.56ECh. 3 - Prob. 3.57ECh. 3 - Prob. 3.58ECh. 3 - Prob. 3.59ECh. 3 - Prob. 3.60ECh. 3 - Prob. 3.61ECh. 3 - Prob. 3.62ECh. 3 - Prob. 3.63ECh. 3 - Prob. 3.64ECh. 3 - Prob. 3.65ECh. 3 - Prob. 3.66ECh. 3 - Prob. 3.67ECh. 3 - Prob. 3.68E
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- (a) Magnesium (Mg) has a hexagonal close-packed (HCP) crystal structure with the lattice parameter of a = 0.321 nm and c= 0.521 nm and the atomic radius is 0.173 nm. (i) What is the number of atoms per unit cell in HCP structure? (ii) Determine the atomic packing factor of the Mg unit cell. (iii) Is Mg containing an ideal atomic packing factor? You may justify your answer by evaluating the HCP c/a ratio. Subsequently, will slip be harder in Mg compared to the ideal HCP structure? Justify your answer.arrow_forwardIodine has an orthorhombic unit cell for which the a, b, and c lattice parameters are 0.479, 0.725, and 0.978 nm, respectively. (a) If the atomic packing factor and atomic radius are 0.547 and 0.177 nm, respectively, determine the number of atoms in each unit cell. (b) The atomic weight of iodine is 126.91 g/mol; compute its theoretical density.arrow_forwardA metal X has an atomic radius of 0.126 nm. If the density and molar mass of X are 7.87 g cm3 and 55.85 g mol1, respectively. 1. (a) (i) Determine the number of atoms per unit cell and the crystal structure of metal X. (ii) Determine the volume of the unit cell. (ii) Determine its planar density in [100], [110] and [111] directions. (iv) Explain which direction would be the most possible slip direction when shear stress is applied. (b) Explain the role of matrix and reinforcement phase in a composite material.arrow_forward
- 1.Indium has a tetragonal unit cell for which the a and c lattice parameters are 0.459 and 0.495 nm, respectively. (a) If the atomic packing factor and atomic radius are 0.693 and 0.1625 nm, respectively, determine the number of atoms in each unit cell. (b) The atomic weight of indium is 114.82 g/mol; compute its theoretical density.arrow_forwardAn element crystallizes in a face-centered cubic lattice and hasa density of 1.45 g/cm³. The edge of its unit cell is 4.52X10⁻⁸cm.(a) How many atoms are in each unit cell?(b) What is the volume of a unit cell?(c) What is the mass of a unit cell?(d) Calculate an approximate atomic mass for the element.arrow_forwardSodium has the body-centered cubic structure, and its lattice parameter is 4.28 Å.(a) How many Na atoms does a unit cell contain?(b) What fraction of the volume of the unit cell is occupied by Na atoms, if they are represented by spheres in contact with one another?arrow_forward
- (a)What is the atomic radius (in nm) of a certain metal particle if it crystallizes with a face-centered cubic unit ceno.38 nm on an edge?(b) What will be its theoretical density if it has an atomic weight of 88.9 g/molarrow_forwardNaH crystallizes with the same crystal structure as NaCl. The edge length of the cubic unit cell of NaH is 4.880 Å.(a) Calculate the ionic radius of H−. (The ionic radius of Li+ is 0.0.95 Å.)(b) Calculate the density of NaH.arrow_forwardGallium has an orthorhombic structure, with a0 = 0.45258 nm, b0 = 0.45186 nm, and c0 = 0.76570 nm. The atomic radius is 0.1218 nm. The density is 5.904 g cm3, and the atomic weight is 69.72 g mol. Determine (a) the number of atoms in each unit cell; and (b) the packing factor in the unit cell.arrow_forward
- 1) Palladium (electron configuration is [Kr]4d¹) crystallizes in a face-centered cubic unit cell. its density is 12.0 g/cm³. (NA = 6.02 x 10²³) (a) What is the total mass of palladium atoms contained within one unit cell? (b) Calculate the atomic radius (r) of Pd.arrow_forwardIron forms a body-centered cubic crystal structure. (a) How many Fe atoms are in a unit cell? (b) What is the mass of a unit cell in grams? (c) If the density of iron is 7.86 g/cm', calculate the volume of unit cell, the edge length of the unit cell in pm, and the atomic radius of iron in pm. (Atomic mass of iron = 55.85 amu; 1 amu = 1.6605 x 10 24 g; 1 pm = 10-10 cm)arrow_forward(b) Using the Crystallographer's formula to determine the density (in g/cm³) of Po: ρ = Σ Ζ * Μ Vell* N You must know that a primitive cubic cell has Z = 1 Since Po is a metal, the value of "i" = 1, since it's the only entity! MM of Po= 208.998 g/mol Vcell (in cm³) = a³ Vcell (3.36 x 10-8 cm)³ = 3.793 x 10-23 cm³ N = 6.022 x 1023 atoms/mol Thus: p = (1 atom/cell) (208.998 g/mol) = 9.16 g/cm³ (3.793 x 10-23 cm³) (6.022 x 1023)arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Chemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage LearningPrinciples of Modern ChemistryChemistryISBN:9781305079113Author:David W. Oxtoby, H. Pat Gillis, Laurie J. ButlerPublisher:Cengage Learning
Chemistry: Principles and Practice
Chemistry
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Cengage Learning
Principles of Modern Chemistry
Chemistry
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:Cengage Learning
Unit Cell Chemistry Simple Cubic, Body Centered Cubic, Face Centered Cubic Crystal Lattice Structu; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=HCWwRh5CXYU;License: Standard YouTube License, CC-BY