Pressure of gas in a full cylinder at 20 ° C when it empty cylinder weighs 0.74 kg has to be determined. Concept Introduction: An ideal gas contains a large number of randomly moving particles that are supposed to have perfectly elastic collisions among themselves. It is a theoretical concept. Gases that show perfect elastic collision are practically not possible. At higher T and lower P gases behave almost ideally. Ideal gas law is an equation of state for any hypothetical gas. Expression for ideal gas equation is as follows: P V = n R T Here, P is pressure of the gas. V is volume of gas. n denotes moles of gas. R is gas constant. T is temperature of gas.

Question

Want to see more full solutions like this?

Answer 1

Question

Chapter 3, Problem 3B.22E

(a)

Interpretation Introduction

Interpretation:

Pressure of gas in a full cylinder at 20 °C when it empty cylinder weighs 0.74 kg has to be determined.

Concept Introduction:

An ideal gas contains a large number of randomly moving particles that are supposed to have perfectly elastic collisions among themselves. It is a theoretical concept. Gases that show perfect elastic collision are practically not possible. At higher T and lower P gases behave almost ideally.

Ideal gas law is an equation of state for any hypothetical gas. Expression for ideal gas equation is as follows:

PV=nRT

Here,

P is pressure of the gas.

V is volume of gas.

n denotes moles of gas.

R is gas constant.

T is temperature of gas.

(a)

Expert Solution

Answer to Problem 3B.22E

Pressure of gas in a full cylinder at 20 °C is 664.5868 bar.

Explanation of Solution

Mass of CO2 in cylinder is calculated as follows:

weight of CO2=(weight of full cylinder)−(weight of empty cylinder)=(1.04 kg)−(0.74 kg)=0.3 kg(103 g1 kg)=300 g

Expression to calculate moles of CO2 is as follows:

(moles of CO2)=(mass of CO2molar mass of CO2) (1)

Substitute 300 g for mass of CO2 and 44.01 g/mol for molar mass of CO2 in equation (1) to calculate moles of CO2.

(moles of CO2)=(300 g44.01 g/mol)=6.8166 mol

The conversion factor to convert 20 °C to Kelvin is as follows:

temperature in Kelvin=temperature in celsius+273.15=20 °C+273.15=293.15 K

Ideal gas equation is as follows:

PV=nRT (2)

Rearrange equation (2) to calculate P.

P=nRTV (3)

Substitute 250 mL for V, 8.31446×10−2 L⋅bar⋅K−1⋅mol−1 for R, 6.8166 mol for n and 293.15 K for T in equation (3) to calculate P.

P=(6.8166 mol)(8.31446×10−2 L⋅bar⋅K−1⋅mol−1 )(293.15 K)(250 mL)(0.001 L1 mL)=664.5868 bar

Hence, pressure of gas in a full cylinder at 20 °C is 664.5868 bar.

(b)

Interpretation Introduction

Interpretation:

Pressure of gas in a full cylinder at 20 °C when it weighs 0.87 g has to be determined.

Concept Introduction:

Refer to part (a)

(b)

Expert Solution

Answer to Problem 3B.22E

Pressure of gas in a full cylinder at 20 °C when it weighs 0.87 g is 376.6010 bar.

Explanation of Solution

Mass of CO2 in cylinder is calculated as follows:

weight of CO2=(weight of full cylinder)−(weight of empty cylinder)=(1.04 kg)−(0.87 kg)=0.17 kg(103 g1 kg)=170 g

Substitute 170 g for mass of CO2 and 44.01 g/mol for molar mass of CO2 in equation (1) to calculate moles of CO2.

(moles of CO2)=(170 g44.01 g/mol)=3.8627 mol

Substitute 250 mL for V, 8.31446×10−2 L⋅bar⋅K−1⋅mol−1 for R, 3.8627 mol for n and 293.15 K for T in equation (3) to calculate P.

P=(3.8627 mol)(8.31446×10−2 L⋅bar⋅K−1⋅mol−1 )(293.15 K)(250 mL)(0.001 L1 mL)=376.6010 bar

Hence, pressure of gas in a full cylinder when it weighs 0.87 g is 376.6010 bar.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Students have asked these similar questions

option choice: Isoleucine Histidine Threonine Alanine Lysine Aspartate Tryptophan Tyrosine Leucine Arginine Cysteine Asparagine Valine Glutamine Glycine Methionine Serine Proline Phenylalanine Glutamate

sketch the nature of the metal-alkylidene bonding interactions.

Part C The perspective formula of isoleucine, an amino acid, is provided below. HOOC H₂NIC H 川 CH3 CH,CH3 Draw the Newman projection in staggered conformation for isoleucine by viewing the molecule along the C-2-C-3 bond. 1. Edit the Newman projection on the canvas. 2. Replace the appropriate hydrogens with the appropriate -CH3 or other groups. 3. If you need to start over, Undo or choose a Newman projection from the Templates toolbar (bottom). Important: Never delete the hydrogen atoms or bonds directly attached to the template, and do not move them by dragging or dropping them. That will break the projections structures. Only replace them! ▸ View Available Hint(s) 0 2 H± 3D EXP. L ד י CONT. 2 H 0 N о

Answer 2

Question

Chapter 3, Problem 3B.22E

(a)

Interpretation Introduction

Interpretation:

Pressure of gas in a full cylinder at 20 °C when it empty cylinder weighs 0.74 kg has to be determined.

Concept Introduction:

An ideal gas contains a large number of randomly moving particles that are supposed to have perfectly elastic collisions among themselves. It is a theoretical concept. Gases that show perfect elastic collision are practically not possible. At higher T and lower P gases behave almost ideally.

Ideal gas law is an equation of state for any hypothetical gas. Expression for ideal gas equation is as follows:

PV=nRT

Here,

P is pressure of the gas.

V is volume of gas.

n denotes moles of gas.

R is gas constant.

T is temperature of gas.

(a)

Expert Solution

Answer to Problem 3B.22E

Pressure of gas in a full cylinder at 20 °C is 664.5868 bar.

Explanation of Solution

Mass of CO2 in cylinder is calculated as follows:

weight of CO2=(weight of full cylinder)−(weight of empty cylinder)=(1.04 kg)−(0.74 kg)=0.3 kg(103 g1 kg)=300 g

Expression to calculate moles of CO2 is as follows:

(moles of CO2)=(mass of CO2molar mass of CO2) (1)

Substitute 300 g for mass of CO2 and 44.01 g/mol for molar mass of CO2 in equation (1) to calculate moles of CO2.

(moles of CO2)=(300 g44.01 g/mol)=6.8166 mol

The conversion factor to convert 20 °C to Kelvin is as follows:

temperature in Kelvin=temperature in celsius+273.15=20 °C+273.15=293.15 K

Ideal gas equation is as follows:

PV=nRT (2)

Rearrange equation (2) to calculate P.

P=nRTV (3)

Substitute 250 mL for V, 8.31446×10−2 L⋅bar⋅K−1⋅mol−1 for R, 6.8166 mol for n and 293.15 K for T in equation (3) to calculate P.

P=(6.8166 mol)(8.31446×10−2 L⋅bar⋅K−1⋅mol−1 )(293.15 K)(250 mL)(0.001 L1 mL)=664.5868 bar

Hence, pressure of gas in a full cylinder at 20 °C is 664.5868 bar.

(b)

Interpretation Introduction

Interpretation:

Pressure of gas in a full cylinder at 20 °C when it weighs 0.87 g has to be determined.

Concept Introduction:

Refer to part (a)

(b)

Expert Solution

Answer to Problem 3B.22E

Pressure of gas in a full cylinder at 20 °C when it weighs 0.87 g is 376.6010 bar.

Explanation of Solution

Mass of CO2 in cylinder is calculated as follows:

weight of CO2=(weight of full cylinder)−(weight of empty cylinder)=(1.04 kg)−(0.87 kg)=0.17 kg(103 g1 kg)=170 g

Substitute 170 g for mass of CO2 and 44.01 g/mol for molar mass of CO2 in equation (1) to calculate moles of CO2.

(moles of CO2)=(170 g44.01 g/mol)=3.8627 mol

Substitute 250 mL for V, 8.31446×10−2 L⋅bar⋅K−1⋅mol−1 for R, 3.8627 mol for n and 293.15 K for T in equation (3) to calculate P.

P=(3.8627 mol)(8.31446×10−2 L⋅bar⋅K−1⋅mol−1 )(293.15 K)(250 mL)(0.001 L1 mL)=376.6010 bar

Hence, pressure of gas in a full cylinder when it weighs 0.87 g is 376.6010 bar.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Question

Chapter 3, Problem 3B.22E

(a)

Interpretation Introduction

Interpretation:

Pressure of gas in a full cylinder at 20 °C when it empty cylinder weighs 0.74 kg has to be determined.

Concept Introduction:

An ideal gas contains a large number of randomly moving particles that are supposed to have perfectly elastic collisions among themselves. It is a theoretical concept. Gases that show perfect elastic collision are practically not possible. At higher T and lower P gases behave almost ideally.

Ideal gas law is an equation of state for any hypothetical gas. Expression for ideal gas equation is as follows:

PV=nRT

Here,

P is pressure of the gas.

V is volume of gas.

n denotes moles of gas.

R is gas constant.

T is temperature of gas.

(a)

Expert Solution

Answer to Problem 3B.22E

Pressure of gas in a full cylinder at 20 °C is 664.5868 bar.

Explanation of Solution

Mass of CO2 in cylinder is calculated as follows:

weight of CO2=(weight of full cylinder)−(weight of empty cylinder)=(1.04 kg)−(0.74 kg)=0.3 kg(103 g1 kg)=300 g

Expression to calculate moles of CO2 is as follows:

(moles of CO2)=(mass of CO2molar mass of CO2) (1)

Substitute 300 g for mass of CO2 and 44.01 g/mol for molar mass of CO2 in equation (1) to calculate moles of CO2.

(moles of CO2)=(300 g44.01 g/mol)=6.8166 mol

The conversion factor to convert 20 °C to Kelvin is as follows:

temperature in Kelvin=temperature in celsius+273.15=20 °C+273.15=293.15 K

Ideal gas equation is as follows:

PV=nRT (2)

Rearrange equation (2) to calculate P.

P=nRTV (3)

Substitute 250 mL for V, 8.31446×10−2 L⋅bar⋅K−1⋅mol−1 for R, 6.8166 mol for n and 293.15 K for T in equation (3) to calculate P.

P=(6.8166 mol)(8.31446×10−2 L⋅bar⋅K−1⋅mol−1 )(293.15 K)(250 mL)(0.001 L1 mL)=664.5868 bar

Hence, pressure of gas in a full cylinder at 20 °C is 664.5868 bar.

(b)

Interpretation Introduction

Interpretation:

Pressure of gas in a full cylinder at 20 °C when it weighs 0.87 g has to be determined.

Concept Introduction:

Refer to part (a)

(b)

Expert Solution

Answer to Problem 3B.22E

Pressure of gas in a full cylinder at 20 °C when it weighs 0.87 g is 376.6010 bar.

Explanation of Solution

Mass of CO2 in cylinder is calculated as follows:

weight of CO2=(weight of full cylinder)−(weight of empty cylinder)=(1.04 kg)−(0.87 kg)=0.17 kg(103 g1 kg)=170 g

Substitute 170 g for mass of CO2 and 44.01 g/mol for molar mass of CO2 in equation (1) to calculate moles of CO2.

(moles of CO2)=(170 g44.01 g/mol)=3.8627 mol

Substitute 250 mL for V, 8.31446×10−2 L⋅bar⋅K−1⋅mol−1 for R, 3.8627 mol for n and 293.15 K for T in equation (3) to calculate P.

P=(3.8627 mol)(8.31446×10−2 L⋅bar⋅K−1⋅mol−1 )(293.15 K)(250 mL)(0.001 L1 mL)=376.6010 bar

Hence, pressure of gas in a full cylinder when it weighs 0.87 g is 376.6010 bar.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Chapter 3, Problem 3B.22E

(a)

Interpretation Introduction

Interpretation:

Pressure of gas in a full cylinder at 20 °C when it empty cylinder weighs 0.74 kg has to be determined.

Concept Introduction:

An ideal gas contains a large number of randomly moving particles that are supposed to have perfectly elastic collisions among themselves. It is a theoretical concept. Gases that show perfect elastic collision are practically not possible. At higher T and lower P gases behave almost ideally.

Ideal gas law is an equation of state for any hypothetical gas. Expression for ideal gas equation is as follows:

PV=nRT

Here,

P is pressure of the gas.

V is volume of gas.

n denotes moles of gas.

R is gas constant.

T is temperature of gas.

(a)

Expert Solution

Answer to Problem 3B.22E

Pressure of gas in a full cylinder at 20 °C is 664.5868 bar.

Explanation of Solution

Mass of CO2 in cylinder is calculated as follows:

weight of CO2=(weight of full cylinder)−(weight of empty cylinder)=(1.04 kg)−(0.74 kg)=0.3 kg(103 g1 kg)=300 g

Expression to calculate moles of CO2 is as follows:

(moles of CO2)=(mass of CO2molar mass of CO2) (1)

Substitute 300 g for mass of CO2 and 44.01 g/mol for molar mass of CO2 in equation (1) to calculate moles of CO2.

(moles of CO2)=(300 g44.01 g/mol)=6.8166 mol

The conversion factor to convert 20 °C to Kelvin is as follows:

temperature in Kelvin=temperature in celsius+273.15=20 °C+273.15=293.15 K

Ideal gas equation is as follows:

PV=nRT (2)

Rearrange equation (2) to calculate P.

P=nRTV (3)

Substitute 250 mL for V, 8.31446×10−2 L⋅bar⋅K−1⋅mol−1 for R, 6.8166 mol for n and 293.15 K for T in equation (3) to calculate P.

P=(6.8166 mol)(8.31446×10−2 L⋅bar⋅K−1⋅mol−1 )(293.15 K)(250 mL)(0.001 L1 mL)=664.5868 bar

Hence, pressure of gas in a full cylinder at 20 °C is 664.5868 bar.

(b)

Interpretation Introduction

Interpretation:

Pressure of gas in a full cylinder at 20 °C when it weighs 0.87 g has to be determined.

Concept Introduction:

Refer to part (a)

(b)

Expert Solution

Answer to Problem 3B.22E

Pressure of gas in a full cylinder at 20 °C when it weighs 0.87 g is 376.6010 bar.

Explanation of Solution

Mass of CO2 in cylinder is calculated as follows:

weight of CO2=(weight of full cylinder)−(weight of empty cylinder)=(1.04 kg)−(0.87 kg)=0.17 kg(103 g1 kg)=170 g

Substitute 170 g for mass of CO2 and 44.01 g/mol for molar mass of CO2 in equation (1) to calculate moles of CO2.

(moles of CO2)=(170 g44.01 g/mol)=3.8627 mol

Substitute 250 mL for V, 8.31446×10−2 L⋅bar⋅K−1⋅mol−1 for R, 3.8627 mol for n and 293.15 K for T in equation (3) to calculate P.

P=(3.8627 mol)(8.31446×10−2 L⋅bar⋅K−1⋅mol−1 )(293.15 K)(250 mL)(0.001 L1 mL)=376.6010 bar

Hence, pressure of gas in a full cylinder when it weighs 0.87 g is 376.6010 bar.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 3, Problem 3B.22E

(a)

Interpretation Introduction

Interpretation:

Pressure of gas in a full cylinder at 20 °C when it empty cylinder weighs 0.74 kg has to be determined.

Concept Introduction:

An ideal gas contains a large number of randomly moving particles that are supposed to have perfectly elastic collisions among themselves. It is a theoretical concept. Gases that show perfect elastic collision are practically not possible. At higher T and lower P gases behave almost ideally.

Ideal gas law is an equation of state for any hypothetical gas. Expression for ideal gas equation is as follows:

PV=nRT

Here,

P is pressure of the gas.

V is volume of gas.

n denotes moles of gas.

R is gas constant.

T is temperature of gas.

(a)

Expert Solution

Answer to Problem 3B.22E

Pressure of gas in a full cylinder at 20 °C is 664.5868 bar.

Explanation of Solution

Mass of CO2 in cylinder is calculated as follows:

weight of CO2=(weight of full cylinder)−(weight of empty cylinder)=(1.04 kg)−(0.74 kg)=0.3 kg(103 g1 kg)=300 g

Expression to calculate moles of CO2 is as follows:

(moles of CO2)=(mass of CO2molar mass of CO2) (1)

Substitute 300 g for mass of CO2 and 44.01 g/mol for molar mass of CO2 in equation (1) to calculate moles of CO2.

(moles of CO2)=(300 g44.01 g/mol)=6.8166 mol

The conversion factor to convert 20 °C to Kelvin is as follows:

temperature in Kelvin=temperature in celsius+273.15=20 °C+273.15=293.15 K

Ideal gas equation is as follows:

PV=nRT (2)

Rearrange equation (2) to calculate P.

P=nRTV (3)

Substitute 250 mL for V, 8.31446×10−2 L⋅bar⋅K−1⋅mol−1 for R, 6.8166 mol for n and 293.15 K for T in equation (3) to calculate P.

P=(6.8166 mol)(8.31446×10−2 L⋅bar⋅K−1⋅mol−1 )(293.15 K)(250 mL)(0.001 L1 mL)=664.5868 bar

Hence, pressure of gas in a full cylinder at 20 °C is 664.5868 bar.

(b)

Interpretation Introduction

Interpretation:

Pressure of gas in a full cylinder at 20 °C when it weighs 0.87 g has to be determined.

Concept Introduction:

Refer to part (a)

(b)

Expert Solution

Answer to Problem 3B.22E

Pressure of gas in a full cylinder at 20 °C when it weighs 0.87 g is 376.6010 bar.

Explanation of Solution

Mass of CO2 in cylinder is calculated as follows:

weight of CO2=(weight of full cylinder)−(weight of empty cylinder)=(1.04 kg)−(0.87 kg)=0.17 kg(103 g1 kg)=170 g

Substitute 170 g for mass of CO2 and 44.01 g/mol for molar mass of CO2 in equation (1) to calculate moles of CO2.

(moles of CO2)=(170 g44.01 g/mol)=3.8627 mol

Substitute 250 mL for V, 8.31446×10−2 L⋅bar⋅K−1⋅mol−1 for R, 3.8627 mol for n and 293.15 K for T in equation (3) to calculate P.

P=(3.8627 mol)(8.31446×10−2 L⋅bar⋅K−1⋅mol−1 )(293.15 K)(250 mL)(0.001 L1 mL)=376.6010 bar

Hence, pressure of gas in a full cylinder when it weighs 0.87 g is 376.6010 bar.

Answer 6

Chapter 3, Problem 3B.22E

(a)

Interpretation Introduction

Interpretation:

Pressure of gas in a full cylinder at 20 °C when it empty cylinder weighs 0.74 kg has to be determined.

Concept Introduction:

An ideal gas contains a large number of randomly moving particles that are supposed to have perfectly elastic collisions among themselves. It is a theoretical concept. Gases that show perfect elastic collision are practically not possible. At higher T and lower P gases behave almost ideally.

Ideal gas law is an equation of state for any hypothetical gas. Expression for ideal gas equation is as follows:

PV=nRT

Here,

P is pressure of the gas.

V is volume of gas.

n denotes moles of gas.

R is gas constant.

T is temperature of gas.

(a)

Expert Solution

Answer to Problem 3B.22E

Pressure of gas in a full cylinder at 20 °C is 664.5868 bar.

Explanation of Solution

Mass of CO2 in cylinder is calculated as follows:

weight of CO2=(weight of full cylinder)−(weight of empty cylinder)=(1.04 kg)−(0.74 kg)=0.3 kg(103 g1 kg)=300 g

Expression to calculate moles of CO2 is as follows:

(moles of CO2)=(mass of CO2molar mass of CO2) (1)

Substitute 300 g for mass of CO2 and 44.01 g/mol for molar mass of CO2 in equation (1) to calculate moles of CO2.

(moles of CO2)=(300 g44.01 g/mol)=6.8166 mol

The conversion factor to convert 20 °C to Kelvin is as follows:

temperature in Kelvin=temperature in celsius+273.15=20 °C+273.15=293.15 K

Ideal gas equation is as follows:

PV=nRT (2)

Rearrange equation (2) to calculate P.

P=nRTV (3)

Substitute 250 mL for V, 8.31446×10−2 L⋅bar⋅K−1⋅mol−1 for R, 6.8166 mol for n and 293.15 K for T in equation (3) to calculate P.

P=(6.8166 mol)(8.31446×10−2 L⋅bar⋅K−1⋅mol−1 )(293.15 K)(250 mL)(0.001 L1 mL)=664.5868 bar

Hence, pressure of gas in a full cylinder at 20 °C is 664.5868 bar.

Answer 7

Chapter 3, Problem 3B.22E

(a)

Interpretation Introduction

Interpretation:

Pressure of gas in a full cylinder at 20 °C when it empty cylinder weighs 0.74 kg has to be determined.

Concept Introduction:

An ideal gas contains a large number of randomly moving particles that are supposed to have perfectly elastic collisions among themselves. It is a theoretical concept. Gases that show perfect elastic collision are practically not possible. At higher T and lower P gases behave almost ideally.

Ideal gas law is an equation of state for any hypothetical gas. Expression for ideal gas equation is as follows:

PV=nRT

Here,

P is pressure of the gas.

V is volume of gas.

n denotes moles of gas.

R is gas constant.

T is temperature of gas.

Answer 8

(a)

Expert Solution

Answer to Problem 3B.22E

Pressure of gas in a full cylinder at 20 °C is 664.5868 bar.

Answer 9

(a)

Expert Solution

Answer 10

(a)

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

Mass of CO2 in cylinder is calculated as follows:

weight of CO2=(weight of full cylinder)−(weight of empty cylinder)=(1.04 kg)−(0.74 kg)=0.3 kg(103 g1 kg)=300 g

Expression to calculate moles of CO2 is as follows:

(moles of CO2)=(mass of CO2molar mass of CO2) (1)

Substitute 300 g for mass of CO2 and 44.01 g/mol for molar mass of CO2 in equation (1) to calculate moles of CO2.

(moles of CO2)=(300 g44.01 g/mol)=6.8166 mol

The conversion factor to convert 20 °C to Kelvin is as follows:

temperature in Kelvin=temperature in celsius+273.15=20 °C+273.15=293.15 K

Ideal gas equation is as follows:

PV=nRT (2)

Rearrange equation (2) to calculate P.

P=nRTV (3)

Substitute 250 mL for V, 8.31446×10−2 L⋅bar⋅K−1⋅mol−1 for R, 6.8166 mol for n and 293.15 K for T in equation (3) to calculate P.

P=(6.8166 mol)(8.31446×10−2 L⋅bar⋅K−1⋅mol−1 )(293.15 K)(250 mL)(0.001 L1 mL)=664.5868 bar

Hence, pressure of gas in a full cylinder at 20 °C is 664.5868 bar.

Answer 13

(b)

Interpretation Introduction

Interpretation:

Pressure of gas in a full cylinder at 20 °C when it weighs 0.87 g has to be determined.

Concept Introduction:

Refer to part (a)

(b)

Expert Solution

Answer to Problem 3B.22E

Pressure of gas in a full cylinder at 20 °C when it weighs 0.87 g is 376.6010 bar.

Explanation of Solution

Mass of CO2 in cylinder is calculated as follows:

weight of CO2=(weight of full cylinder)−(weight of empty cylinder)=(1.04 kg)−(0.87 kg)=0.17 kg(103 g1 kg)=170 g

Substitute 170 g for mass of CO2 and 44.01 g/mol for molar mass of CO2 in equation (1) to calculate moles of CO2.

(moles of CO2)=(170 g44.01 g/mol)=3.8627 mol

Substitute 250 mL for V, 8.31446×10−2 L⋅bar⋅K−1⋅mol−1 for R, 3.8627 mol for n and 293.15 K for T in equation (3) to calculate P.

P=(3.8627 mol)(8.31446×10−2 L⋅bar⋅K−1⋅mol−1 )(293.15 K)(250 mL)(0.001 L1 mL)=376.6010 bar

Hence, pressure of gas in a full cylinder when it weighs 0.87 g is 376.6010 bar.

Answer 14

(b)

Interpretation Introduction

Interpretation:

Pressure of gas in a full cylinder at 20 °C when it weighs 0.87 g has to be determined.

Concept Introduction:

Refer to part (a)

Answer 15

(b)

Expert Solution

Answer to Problem 3B.22E

Pressure of gas in a full cylinder at 20 °C when it weighs 0.87 g is 376.6010 bar.

Answer 16

(b)

Expert Solution

Answer 17

(b)

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

Mass of CO2 in cylinder is calculated as follows:

weight of CO2=(weight of full cylinder)−(weight of empty cylinder)=(1.04 kg)−(0.87 kg)=0.17 kg(103 g1 kg)=170 g

Substitute 170 g for mass of CO2 and 44.01 g/mol for molar mass of CO2 in equation (1) to calculate moles of CO2.

(moles of CO2)=(170 g44.01 g/mol)=3.8627 mol

Substitute 250 mL for V, 8.31446×10−2 L⋅bar⋅K−1⋅mol−1 for R, 3.8627 mol for n and 293.15 K for T in equation (3) to calculate P.

P=(3.8627 mol)(8.31446×10−2 L⋅bar⋅K−1⋅mol−1 )(293.15 K)(250 mL)(0.001 L1 mL)=376.6010 bar

Hence, pressure of gas in a full cylinder when it weighs 0.87 g is 376.6010 bar.

Answer 20

Ch. 3 - Prob. 3A.1AST Ch. 3 - Prob. 3A.1BST Ch. 3 - Prob. 3A.2AST Ch. 3 - Prob. 3A.2BST Ch. 3 - Prob. 3A.3AST Ch. 3 - Prob. 3A.3BST Ch. 3 - Prob. 3A.1E Ch. 3 - Prob. 3A.2E Ch. 3 - Prob. 3A.3E Ch. 3 - Prob. 3A.4E

Videos

Answer to Problem 3B.22E

Explanation of Solution

Interpretation:

Pressure of gas in a full cylinder at 20 °C when it weighs 0.87 g has to be determined.

Concept Introduction:

Refer to part (a)

Answer to Problem 3B.22E

Explanation of Solution

Want to see more full solutions like this?

Chapter 3 Solutions

Videos

Answer to Problem 3B.22E

Explanation of Solution

Interpretation: Pressure of gas in a full cylinder at 20 °C when it weighs 0.87 g has to be determined. Concept Introduction: Refer to part (a)

Answer to Problem 3B.22E

Explanation of Solution

Want to see more full solutions like this?

Chapter 3 Solutions

Interpretation:

Pressure of gas in a full cylinder at 20 °C when it weighs 0.87 g has to be determined.

Concept Introduction:

Refer to part (a)