Chapter 3, Problem 3B.41E

Interpretation Introduction

Interpretation:

Molar mass of the gaseous compound with density $0.943\text{g}\cdot {\text{L}}^{-1}$ has to be determined.

Concept Introduction:

The density of any object is obtained when the mass of object in grams is divided by volume of an object in milliliters. So it is denoted by unit: gram per milliliter.

Density is directly associated to the mass of an object. Higher the mass of the substance higher will be its density. Density is inversely associated with the volume of a substance. Lower the volume of the substance higher will be its density.

Expression that relates density, molar mass, pressure, temperature, and gas constant for an ideal gas is as follows:

  $d=\frac{MP}{RT}$

Here,

$d$ is density of object.

$M$ is molar mass.

$P$ is pressure.

$R$ is gas constant.

$T$ is the temperature.