Chapter 3, Problem 3.86AQAP

Interpretation Introduction

(a)

Interpretation:

The temperature change ( $\Delta \text{T}$ ) for 0.650 kg of water that loses 5.48 kJ heat should be calculated.

Concept Introduction:

The mathematical expression for amount of heat needed to change the temperature is given by:

  $\mathrm{q}=mc\Delta T$

Where, q = amount of heat absorbed

m= mass of substance

c= specific heat capacity

  $\Delta \text{T}$ = temperature change

Interpretation Introduction

(b)

Interpretation:

The temperature change ( $\Delta \text{T}$ ) for 35.0 g of silver ( $\text{Ag}$ ) that loses 472 J heat should be calculated.

Concept Introduction:

The mathematical expression for amount of heat needed to change the temperature is given by:

  $\mathrm{q}=mc\Delta T$

Where, q = amount of heat absorbed

m= mass of substance

c= specific heat capacity

  $\Delta \text{T}$ = temperature change