(a) Interpretation: The number of atoms per FCC unit cell needs to be calculated. Concept Introduction: Atoms in FCC structure have radius R. Atoms with R radius consume 74% of total volume of the unit cell and the remaining 26% is empty. Packing fraction of FCC structure is 0.74. Assume that remaining space in the unit cell is required with smaller atoms of radius r = 0.414 R .

Question

The power out of an adiabatic steam turbine is 5 MW and the steam enters turbine at 2 MPa and velocity of 50 m/s, specific enthalpy (h) of 3248 kJ/kg. The elevation of the inlet is 10 m higher than at the datum. The vapor mixture exits at 15 kPa and a velocity of 180 m/s, specific enthalpy (h) of 2361.01 kJ/kg. The elevation of the exit is 6 m higher than at the datum. Let g = 9.81 m/s². Assuming the ideal gas model and R = 0.462 KJ/(kg.K). The steam specific heat ratio is 1.283. Calculate:

Answer 1

Question

Chapter 3, Problem 3.83P

Interpretation Introduction

(a)

Interpretation:

The number of atoms per FCC unit cell needs to be calculated.

Concept Introduction:

Atoms in FCC structure have radius R. Atoms with R radius consume 74% of total volume of the unit cell and the remaining 26% is empty. Packing fraction of FCC structure is 0.74.

Assume that remaining space in the unit cell is required with smaller atoms of radius r = 0.414 R.

Interpretation Introduction

(b)

Interpretation:

The coordinates of smaller atoms with radius r per unit cell is to be determined.

Concept Introduction:

Atoms in FCC structure have radius R. Atoms with R radius consume 74% of total volume of the unit cell and the remaining 26% is empty. Packing fraction of FCC structure is 0.74.

Assume that remaining space in the unit cell is required with smaller atoms of radius r = 0.414 R.

Interpretation Introduction

(c)

Interpretation:

The atomic packing fraction for FCC structure is to be calculated.

Concept Introduction:

Atoms in FCC structure have radius R. Atoms with R radius consume 74% of total volume of the unit cell and the remaining 26% is empty. Packing fraction of FCC structure is 0.74.

Assume that remaining space in the unit cell is required with smaller atoms of radius r = 0.414 R.

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The power out of an adiabatic steam turbine is 5 MW and the steam enters turbine at 2 MPa and velocity of 50 m/s, specific enthalpy (h) of 3248 kJ/kg. The elevation of the inlet is 10 m higher than at the datum. The vapor mixture exits at 15 kPa and a velocity of 180 m/s, specific enthalpy (h) of 2361.01 kJ/kg. The elevation of the exit is 6 m higher than at the datum. Let g = 9.81 m/s². Assuming the ideal gas model and R = 0.462 KJ/(kg.K). The steam specific heat ratio is 1.283. Calculate:

O Consider a 0.8 m high and 0.5 m wide window with thickness of 8 mm and thermal conductivity of k = 0.78 W/m °C. For dry day, the temperature of outdoor is -10 °C and the inner room temperature is 20°C. Take the heat transfer coefficient on the inner and outer surface of the window to be h₁ = 10 W/m² °C and h₂ = 40 W/m² °C which includes the effects of insulation. Determine:

Answer 2

Question

Chapter 3, Problem 3.83P

Interpretation Introduction

(a)

Interpretation:

The number of atoms per FCC unit cell needs to be calculated.

Concept Introduction:

Atoms in FCC structure have radius R. Atoms with R radius consume 74% of total volume of the unit cell and the remaining 26% is empty. Packing fraction of FCC structure is 0.74.

Assume that remaining space in the unit cell is required with smaller atoms of radius r = 0.414 R.

Interpretation Introduction

(b)

Interpretation:

The coordinates of smaller atoms with radius r per unit cell is to be determined.

Concept Introduction:

Atoms in FCC structure have radius R. Atoms with R radius consume 74% of total volume of the unit cell and the remaining 26% is empty. Packing fraction of FCC structure is 0.74.

Assume that remaining space in the unit cell is required with smaller atoms of radius r = 0.414 R.

Interpretation Introduction

(c)

Interpretation:

The atomic packing fraction for FCC structure is to be calculated.

Concept Introduction:

Atoms in FCC structure have radius R. Atoms with R radius consume 74% of total volume of the unit cell and the remaining 26% is empty. Packing fraction of FCC structure is 0.74.

Assume that remaining space in the unit cell is required with smaller atoms of radius r = 0.414 R.

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Answer 3

Question

Chapter 3, Problem 3.83P

Interpretation Introduction

(a)

Interpretation:

The number of atoms per FCC unit cell needs to be calculated.

Concept Introduction:

Atoms in FCC structure have radius R. Atoms with R radius consume 74% of total volume of the unit cell and the remaining 26% is empty. Packing fraction of FCC structure is 0.74.

Assume that remaining space in the unit cell is required with smaller atoms of radius r = 0.414 R.

Interpretation Introduction

(b)

Interpretation:

The coordinates of smaller atoms with radius r per unit cell is to be determined.

Concept Introduction:

Atoms in FCC structure have radius R. Atoms with R radius consume 74% of total volume of the unit cell and the remaining 26% is empty. Packing fraction of FCC structure is 0.74.

Assume that remaining space in the unit cell is required with smaller atoms of radius r = 0.414 R.

Interpretation Introduction

(c)

Interpretation:

The atomic packing fraction for FCC structure is to be calculated.

Concept Introduction:

Atoms in FCC structure have radius R. Atoms with R radius consume 74% of total volume of the unit cell and the remaining 26% is empty. Packing fraction of FCC structure is 0.74.

Assume that remaining space in the unit cell is required with smaller atoms of radius r = 0.414 R.

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Answer 4

Question

Chapter 3, Problem 3.83P

Interpretation Introduction

(a)

Interpretation:

The number of atoms per FCC unit cell needs to be calculated.

Concept Introduction:

Atoms in FCC structure have radius R. Atoms with R radius consume 74% of total volume of the unit cell and the remaining 26% is empty. Packing fraction of FCC structure is 0.74.

Assume that remaining space in the unit cell is required with smaller atoms of radius r = 0.414 R.

Interpretation Introduction

(b)

Interpretation:

The coordinates of smaller atoms with radius r per unit cell is to be determined.

Concept Introduction:

Atoms in FCC structure have radius R. Atoms with R radius consume 74% of total volume of the unit cell and the remaining 26% is empty. Packing fraction of FCC structure is 0.74.

Assume that remaining space in the unit cell is required with smaller atoms of radius r = 0.414 R.

Interpretation Introduction

(c)

Interpretation:

The atomic packing fraction for FCC structure is to be calculated.

Concept Introduction:

Atoms in FCC structure have radius R. Atoms with R radius consume 74% of total volume of the unit cell and the remaining 26% is empty. Packing fraction of FCC structure is 0.74.

Assume that remaining space in the unit cell is required with smaller atoms of radius r = 0.414 R.

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Answer 5

Chapter 3, Problem 3.83P

Interpretation Introduction

(a)

Interpretation:

The number of atoms per FCC unit cell needs to be calculated.

Concept Introduction:

Atoms in FCC structure have radius R. Atoms with R radius consume 74% of total volume of the unit cell and the remaining 26% is empty. Packing fraction of FCC structure is 0.74.

Assume that remaining space in the unit cell is required with smaller atoms of radius r = 0.414 R.

Interpretation Introduction

(b)

Interpretation:

The coordinates of smaller atoms with radius r per unit cell is to be determined.

Concept Introduction:

Atoms in FCC structure have radius R. Atoms with R radius consume 74% of total volume of the unit cell and the remaining 26% is empty. Packing fraction of FCC structure is 0.74.

Assume that remaining space in the unit cell is required with smaller atoms of radius r = 0.414 R.

Interpretation Introduction

(c)

Interpretation:

The atomic packing fraction for FCC structure is to be calculated.

Concept Introduction:

Atoms in FCC structure have radius R. Atoms with R radius consume 74% of total volume of the unit cell and the remaining 26% is empty. Packing fraction of FCC structure is 0.74.

Assume that remaining space in the unit cell is required with smaller atoms of radius r = 0.414 R.

Answer 6

Chapter 3, Problem 3.83P

Interpretation Introduction

(a)

Interpretation:

The number of atoms per FCC unit cell needs to be calculated.

Concept Introduction:

Atoms in FCC structure have radius R. Atoms with R radius consume 74% of total volume of the unit cell and the remaining 26% is empty. Packing fraction of FCC structure is 0.74.

Assume that remaining space in the unit cell is required with smaller atoms of radius r = 0.414 R.

Answer 7

Chapter 3, Problem 3.83P

Interpretation Introduction

(a)

Interpretation:

The number of atoms per FCC unit cell needs to be calculated.

Concept Introduction:

Atoms in FCC structure have radius R. Atoms with R radius consume 74% of total volume of the unit cell and the remaining 26% is empty. Packing fraction of FCC structure is 0.74.

Assume that remaining space in the unit cell is required with smaller atoms of radius r = 0.414 R.

Answer 8

Interpretation Introduction

(b)

Interpretation:

The coordinates of smaller atoms with radius r per unit cell is to be determined.

Concept Introduction:

Atoms in FCC structure have radius R. Atoms with R radius consume 74% of total volume of the unit cell and the remaining 26% is empty. Packing fraction of FCC structure is 0.74.

Assume that remaining space in the unit cell is required with smaller atoms of radius r = 0.414 R.

Answer 9

Interpretation Introduction

(b)

Interpretation:

The coordinates of smaller atoms with radius r per unit cell is to be determined.

Concept Introduction:

Atoms in FCC structure have radius R. Atoms with R radius consume 74% of total volume of the unit cell and the remaining 26% is empty. Packing fraction of FCC structure is 0.74.

Assume that remaining space in the unit cell is required with smaller atoms of radius r = 0.414 R.

Answer 10

Interpretation Introduction

(c)

Interpretation:

The atomic packing fraction for FCC structure is to be calculated.

Concept Introduction:

Atoms in FCC structure have radius R. Atoms with R radius consume 74% of total volume of the unit cell and the remaining 26% is empty. Packing fraction of FCC structure is 0.74.

Assume that remaining space in the unit cell is required with smaller atoms of radius r = 0.414 R.

Answer 11

Interpretation Introduction

(c)

Interpretation:

The atomic packing fraction for FCC structure is to be calculated.

Concept Introduction:

Atoms in FCC structure have radius R. Atoms with R radius consume 74% of total volume of the unit cell and the remaining 26% is empty. Packing fraction of FCC structure is 0.74.

Assume that remaining space in the unit cell is required with smaller atoms of radius r = 0.414 R.

Answer 12

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Answer 23

Ch. 3 - Prob. 3.1P Ch. 3 - Prob. 3.2P Ch. 3 - Prob. 3.3P Ch. 3 - Prob. 3.4P Ch. 3 - Prob. 3.5P Ch. 3 - Prob. 3.6P Ch. 3 - Prob. 3.7P Ch. 3 - Prob. 3.8P Ch. 3 - Prob. 3.9P Ch. 3 - Prob. 3.10P

Solution Summary: The author calculates the number of atoms per FCC unit cell. Atoms with R radius consume 74% of total volume and the remaining 26% is empty.

Chapter 3 Solutions