The interplanar spacing between the thickness of the sheet needs to be calculated. Concept introduction: FCC rhodium has 1 mm thickness and plane (111) is parallel to the sheet surface. Interplanner spacing can be calculated as follows: d h k l = a 0 ( h 2 + k 2 + l 2 ) Here, h, k and l are dimensions of the plane and a 0 is edge length.

Question

One thousand kg/h of a (50-50 wt%) acetone-in-water solution is to be extracted at 25C in a continuous, countercurrent system with pure 1,1,2-trichloroethane to obtain a raffinate containing 10 wt% acetone. Using the following equilibrium data, determine with an equilateral-triangle diagram: a- the minimum flow rate of solvent; b- the number of stages required for a solvent rate equal to 1.5 times minimum, and composition of each streamleaving each stage. c- Repeat the calculation of (a) and (b) if the solvent used has purity 93wt% (4wr% acetone, 3wt% water impurities) acetone water 1,1,2-trichloroethane Raffinate. Weight Extract. Weight 0.6 0.13 0.27 Fraction Acetone Fraction Acetone 0.5 0.04 0.46 0.44 0.56 0.4 0.03 0.57 0.29 0.40 0.3 0.02 0.68 0.12 0.18 0.2 0.015 0.785 0.0 0.0 0.1 0.01 0.89 0.55 0.35 0.1 0.5 0.43 0.07 0.4 0.57 0.03 0.3 0.68 0.02 0.2 0.79 0.01 0.1 0.895 0.005

Answer 1

Question

Chapter 3, Problem 3.78P

Interpretation Introduction

Interpretation:

The interplanar spacing between the thickness of the sheet needs to be calculated.

Concept introduction:

FCC rhodium has 1 mm thickness and plane (111) is parallel to the sheet surface.

Interplanner spacing can be calculated as follows:

dhkl= a0( h 2 + k 2 + l 2 )

Here, h, k and l are dimensions of the plane and a0 is edge length.

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