Essentials Of Materials Science And Engineering
4th Edition
ISBN: 9781337385497
Author: WRIGHT, Wendelin J.
Publisher: Cengage,
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Question
Chapter 3, Problem 3.25P
Interpretation Introduction
(a)
Interpretation:
The unit cell number should be determined.
Concept Introduction:
The arrangement of ions, molecules and atoms is placed in order in the material of crystalline. Intrinsic nature gives the ordered structure of the particles that helps to form the symmetric pattern. This symmetric pattern is repeated with the three principal directions of the dimensional space.
Interpretation Introduction
(b)
Interpretation:
Atom number of iron atoms in the paper clip should be calculated.
Concept Introduction:
The arrangement of ions, molecules and atoms is placed in order in the material of crystalline. Intrinsic nature gives the ordered structure of the particles that helps to form the symmetric pattern. This symmetric pattern is repeated with the three principal directions of the dimensional space.
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Directions: Show your solutions explicitly, i.e., do not just write the final
answer.
1. A wall footing is to be constructed on a clay soil 1.4 below the ground. The footing is to support a wall that
imposes a load of 130 kN per meter of wall length. Considering general shear failure, determine the following:
130 kN/mm
1.4 m
a. Footing width if the factor of safety is 3.
b. Ultimate bearing capacity if B = 0.95 m.
C.
New factor of safety.
y = 17.92 kN/m²
c = 14.5 kPa
$ = 30°
1.5 m and has its hottom 2 m below the ground surface.
2. A square footing shown has a dimension of 1.5 m x 1.5 m and has its bottom 2 m below the ground surface.
The groundwater table is located at a depth of 3 m below the ground surface. Assume a general shear failure.
Determine the following:
2 m
y = 16 kN/m³
c = 14.5 kPa
→ = 28°
3 m
1,5 m
ysat
18.5 kN/m³
a. Ultimate bearing capacity of the soil beneath the footing (in kPa).
b. Allowable bearing capacity if it has a factor of safety of 3 (in kPa).
C.
Allowable load that the footing could carry (in kN).
d.
Allowable net bearing capacity if factor of safety is 3.
Allowable net load if factor of safety is 3.
Problem (11): A pipe discharges an unknown fluid into the
atmosphere from a tank of depth (h) through a pipe of length
(L), and diameter (d).
Given the values of L [m], d [cm], and (h) [cm], calculate the
discharge rate (Q) [lit/s] that would maintain Laminar flow in
the pipe with a Reynolds number of Re-1500. Ignore minor
losses.
Givens:
L =
139.364 m
d = 12.614 cm
h = 76.609 cm
Answers:
( 1 ) 6.911 lit/s
(2) 8.179 lit/s
( 3 ) 4.244 lit/s
(4) 4.987 lit/s
h
d
Chapter 3 Solutions
Essentials Of Materials Science And Engineering
Ch. 3 - Prob. 3.1PCh. 3 - Prob. 3.2PCh. 3 - Prob. 3.3PCh. 3 - Prob. 3.4PCh. 3 - Prob. 3.5PCh. 3 - Prob. 3.6PCh. 3 - Prob. 3.7PCh. 3 - Prob. 3.8PCh. 3 - Prob. 3.9PCh. 3 - Prob. 3.10P
Ch. 3 - Prob. 3.11PCh. 3 - Prob. 3.12PCh. 3 - Prob. 3.13PCh. 3 - Prob. 3.14PCh. 3 - Prob. 3.15PCh. 3 - Prob. 3.16PCh. 3 - Prob. 3.17PCh. 3 - Prob. 3.18PCh. 3 - Prob. 3.19PCh. 3 - Prob. 3.20PCh. 3 - Prob. 3.21PCh. 3 - Prob. 3.22PCh. 3 - Prob. 3.23PCh. 3 - Prob. 3.24PCh. 3 - Prob. 3.25PCh. 3 - Prob. 3.26PCh. 3 - Prob. 3.27PCh. 3 - Prob. 3.28PCh. 3 - Prob. 3.29PCh. 3 - Prob. 3.30PCh. 3 - Prob. 3.31PCh. 3 - Prob. 3.32PCh. 3 - Prob. 3.33PCh. 3 - Prob. 3.34PCh. 3 - Prob. 3.35PCh. 3 - Prob. 3.36PCh. 3 - Prob. 3.37PCh. 3 - Prob. 3.38PCh. 3 - Prob. 3.39PCh. 3 - Prob. 3.40PCh. 3 - Prob. 3.41PCh. 3 - Prob. 3.42PCh. 3 - Prob. 3.43PCh. 3 - Prob. 3.44PCh. 3 - Prob. 3.45PCh. 3 - Prob. 3.46PCh. 3 - Prob. 3.47PCh. 3 - Prob. 3.48PCh. 3 - Prob. 3.49PCh. 3 - Prob. 3.50PCh. 3 - Prob. 3.51PCh. 3 - Prob. 3.52PCh. 3 - Prob. 3.53PCh. 3 - Prob. 3.54PCh. 3 - Prob. 3.55PCh. 3 - Prob. 3.56PCh. 3 - Prob. 3.57PCh. 3 - Prob. 3.58PCh. 3 - Prob. 3.59PCh. 3 - Prob. 3.60PCh. 3 - Prob. 3.61PCh. 3 - Prob. 3.62PCh. 3 - Prob. 3.63PCh. 3 - Prob. 3.64PCh. 3 - Prob. 3.65PCh. 3 - Prob. 3.66PCh. 3 - Prob. 3.67PCh. 3 - Prob. 3.68PCh. 3 - Prob. 3.69PCh. 3 - Prob. 3.70PCh. 3 - Prob. 3.71PCh. 3 - Prob. 3.72PCh. 3 - Prob. 3.73PCh. 3 - Prob. 3.74PCh. 3 - Prob. 3.75PCh. 3 - Prob. 3.76PCh. 3 - Prob. 3.77PCh. 3 - Prob. 3.78PCh. 3 - Prob. 3.79PCh. 3 - Prob. 3.80PCh. 3 - Prob. 3.81PCh. 3 - Prob. 3.82PCh. 3 - Prob. 3.83PCh. 3 - Prob. 3.84PCh. 3 - Prob. 3.85PCh. 3 - Prob. 3.86PCh. 3 - Prob. 3.87PCh. 3 - Prob. 3.88PCh. 3 - Prob. 3.89PCh. 3 - Prob. 3.90PCh. 3 - Prob. 3.91PCh. 3 - Prob. 3.92PCh. 3 - Prob. 3.93PCh. 3 - Prob. 3.94PCh. 3 - Prob. 3.95PCh. 3 - Prob. 3.96PCh. 3 - Prob. 3.97PCh. 3 - Prob. 3.98PCh. 3 - Prob. 3.99PCh. 3 - Prob. 3.100PCh. 3 - Prob. 3.101DPCh. 3 - Prob. 3.102DPCh. 3 - Prob. 3.103CPCh. 3 - Prob. 3.104CP
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