Chapter 3, Problem 36PP

Interpretation Introduction

Interpretation: The more acidic compound should be identified between the two given compounds using their pKa values.

Concept introduction:

Value of ${\text{k}}_{\text{a}}$ measures the strength of acids. Higher the value of ${\text{k}}_{\text{a}}$ more is the acidic nature. The acidic strengths of two acids are compared by taking the ratio of ${\text{k}}_{\text{a}}$ values of higher to lower.

${\text{pk}}_{\text{a}}$ and ${\text{k}}_{\text{a}}$ values are interrelated as shown below.

$\begin{array}{l}{\text{pk}}_{\text{a}}\text{=}\text{-}\text{log}{\text{k}}_{\text{a}}\\ \text{or}\\ \text{Ka}\text{=}{\text{10}}^{\text{-pKa}}\end{array}$