Organic Chemistry Study Guide and Solutions
6th Edition
ISBN: 9781936221868
Author: Marc Loudon, Jim Parise
Publisher: W. H. Freeman
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Question
Chapter 3, Problem 3.39AP
Interpretation Introduction
(a)
Interpretation:
The curved-arrow notation which shows that the outer oxygen atoms of ozone have an equal amount of negative charge is to be shown.
Concept introduction:
Resonance is the phenomena of the delocalization of pi electrons to give extra stability to the molecule. Resonating structures is defined as the structures which have localized electrons. Curved- arrow notation is used to show the transfer of electrons from one atom to another.
Interpretation Introduction
(b)
Interpretation:
The curved-arrow notation which shows that the
Concept introduction:
Resonance is the phenomena of the delocalization of pi electrons to give extra stability to the molecule. Resonating structures is defined as the structures which have localized electrons. Curved- arrow notation is used to show the transfer of electrons from one atom to another.
Interpretation Introduction
(c)
Interpretation:
The curved-arrow notation which shows that the conjugate acid of formaldehyde has substantial positive charge on carbon is to be stated.
Concept introduction:
Resonance is the phenomena of the delocalization of pi electrons to give extra stability to the molecule. Resonating structures is defined as the structures which have localized electrons. Curved- arrow notation is used to show the transfer of electrons from one atom to another.
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6. Consider the following exothermic reaction below.
2Cu2+(aq) +41 (aq)2Cul(s) + 12(aq)
a. If Cul is added, there will be a shift left/shift right/no shift (circle one).
b. If Cu2+ is added, there will be a shift left/shift right/no shift (circle one).
c. If a solution of AgNO3 is added, there will be a shift left/shift right/no shift (circle one).
d. If the solvent hexane (C6H14) is added, there will be a shift left/shift right/no shift (circle
one). Hint: one of the reaction species is more soluble in hexane than in water.
e. If the reaction is cooled, there will be a shift left/shift right/no shift (circle one).
f. Which of the changes above will change the equilibrium constant, K?
Show work. don't give Ai
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Chapter 3 Solutions
Organic Chemistry Study Guide and Solutions
Ch. 3 - Prob. 3.1PCh. 3 - Prob. 3.2PCh. 3 - Prob. 3.3PCh. 3 - Prob. 3.4PCh. 3 - Prob. 3.5PCh. 3 - Prob. 3.6PCh. 3 - Prob. 3.7PCh. 3 - Prob. 3.8PCh. 3 - Prob. 3.9PCh. 3 - Prob. 3.10P
Ch. 3 - Prob. 3.11PCh. 3 - Prob. 3.12PCh. 3 - Prob. 3.13PCh. 3 - Prob. 3.14PCh. 3 - Prob. 3.15PCh. 3 - Prob. 3.16PCh. 3 - Prob. 3.17PCh. 3 - Prob. 3.18PCh. 3 - Prob. 3.19PCh. 3 - Prob. 3.20PCh. 3 - Prob. 3.21PCh. 3 - Prob. 3.22PCh. 3 - Prob. 3.24PCh. 3 - Prob. 3.25PCh. 3 - Prob. 3.26PCh. 3 - Prob. 3.27PCh. 3 - Prob. 3.28PCh. 3 - Prob. 3.29PCh. 3 - Prob. 3.30PCh. 3 - Prob. 3.31PCh. 3 - Prob. 3.32APCh. 3 - Prob. 3.33APCh. 3 - Prob. 3.34APCh. 3 - Prob. 3.35APCh. 3 - Prob. 3.36APCh. 3 - Prob. 3.37APCh. 3 - Prob. 3.38APCh. 3 - Prob. 3.39APCh. 3 - Prob. 3.40APCh. 3 - Prob. 3.41APCh. 3 - Prob. 3.42APCh. 3 - Prob. 3.43APCh. 3 - Prob. 3.44APCh. 3 - Prob. 3.45APCh. 3 - Prob. 3.46APCh. 3 - Prob. 3.47APCh. 3 - Prob. 3.48APCh. 3 - Prob. 3.49APCh. 3 - Prob. 3.50APCh. 3 - Prob. 3.51APCh. 3 - Prob. 3.52APCh. 3 - Prob. 3.53APCh. 3 - Prob. 3.54APCh. 3 - Prob. 3.55APCh. 3 - Prob. 3.56APCh. 3 - Prob. 3.57APCh. 3 - Prob. 3.58APCh. 3 - Prob. 3.59APCh. 3 - Prob. 3.60AP
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- The following mechanism for the gas phase reaction of H2 and ICI that is consistent with the observed rate law is: step 1 step 2 slow: H2(g) +ICI(g) → HCl(g) + HI(g) fast: ICI(g) + HI(g) → HCl(g) + |2(g) (1) What is the equation for the overall reaction? Use the smallest integer coefficients possible. If a box is not needed, leave it blank. + → + (2) Which species acts as a catalyst? Enter formula. If none, leave box blank: (3) Which species acts as a reaction intermediate? Enter formula. If none, leave box blank: (4) Complete the rate law for the overall reaction that is consistent with this mechanism. (Use the form k[A][B]"..., where '1' is understood (so don't write it) for m, n etc.) Rate =arrow_forwardPlease correct answer and don't use hand rating and don't use Ai solutionarrow_forward1. For each of the following statements, indicate whether they are true of false. ⚫ the terms primary, secondary and tertiary have different meanings when applied to amines than they do when applied to alcohols. • a tertiary amine is one that is bonded to a tertiary carbon atom (one with three C atoms bonded to it). • simple five-membered heteroaromatic compounds (e.g. pyrrole) are typically more electron rich than benzene. ⚫ simple six-membered heteroaromatic compounds (e.g. pyridine) are typically more electron rich than benzene. • pyrrole is very weakly basic because protonation anywhere on the ring disrupts the aromaticity. • thiophene is more reactive than benzene toward electrophilic aromatic substitution. • pyridine is more reactive than nitrobenzene toward electrophilic aromatic substitution. • the lone pair on the nitrogen atom of pyridine is part of the pi system.arrow_forward
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