Loose Leaf For Introduction To Chemical Engineering Thermodynamics
8th Edition
ISBN: 9781259878084
Author: Smith Termodinamica En Ingenieria Quimica, J.m.; Van Ness, Hendrick C; Abbott, Michael; Swihart, Mark
Publisher: McGraw-Hill Education
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Chapter 3, Problem 3.37P
Interpretation Introduction
Interpretation:
The internal volume of the gas cylinder should be calculated based on the given conditions
Concept Introduction:
- An equation of state in
thermodynamics is an equation that relates state defining parameters such as pressure (P), volume (V) and temperature (T). - The ideal gas equation is a thermodynamic equation of state given as follows:
- Under constant temperature conditions:
PV = nRT -----(1)
n = number of moles of the gas i.e.
R = gas constant = 0.08314 L.bar.K-1.mol-1
P1V1 = P2V2 ------(2)
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Assignment 2.
Example. The diffusivity of the vapour of a volatile liquid in air can be conveniently
determined by Winkelmann's method in which liquid is contained in a narrow diameter
vertical tube, maintained at a constant temperature, and an air stream is passed over
the top of the tube sufficiently rapidly to ensure that the partial pressure of the vapour
there remains approximately zero. On the assumption that the vapour is transferred
from the surface of the liquid to the air stream by molecular diffusion, calculate the
diffusivity of carbon tetrachloride vapour in air at 321 K and atmospheric pressure from
the following experimental data:
Time from commencement
of experiment, (t x1 03 s)
Liquid level (mm)
0.0
0.0
1.6
2.5
11.1
12.9
27.4
23-2
80-2
43.9
117.5
54-7
168.6
67.0
199.7
73-8
289-3
90-3
383-1
104.8
The vapour pressure of carbon tetrachloride at 321 K is 37.6 kN/m² and the density of
the liquid is 1540 kg/m³. Take the kilogram molecular volume as 22.4 m³.
Please.... please, provide me with full calculation (more details) because this question I sent it previously but I did not receive a good result yet.
Chapter 3 Solutions
Loose Leaf For Introduction To Chemical Engineering Thermodynamics
Ch. 3 - Prob. 3.1PCh. 3 - Prob. 3.2PCh. 3 - A closed, nonreactive system contains species 1...Ch. 3 - Prob. 3.4PCh. 3 - For the system described in Prob. 3.4: (a) How...Ch. 3 - Prob. 3.6PCh. 3 - Prob. 3.7PCh. 3 - Prob. 3.8PCh. 3 - Prob. 3.9PCh. 3 - Prob. 3.10P
Ch. 3 - Prob. 3.11PCh. 3 - Prob. 3.12PCh. 3 - Prob. 3.13PCh. 3 - Prob. 3.14PCh. 3 - Prob. 3.15PCh. 3 - Prob. 3.16PCh. 3 - Prob. 3.17PCh. 3 - Prob. 3.18PCh. 3 - Prob. 3.19PCh. 3 - Prob. 3.20PCh. 3 - Prob. 3.21PCh. 3 - Prob. 3.22PCh. 3 - Prob. 3.23PCh. 3 - Prob. 3.24PCh. 3 - Prob. 3.25PCh. 3 - Prob. 3.26PCh. 3 - Prob. 3.27PCh. 3 - Prob. 3.28PCh. 3 - Prob. 3.29PCh. 3 - Prob. 3.30PCh. 3 - Prob. 3.31PCh. 3 - Prob. 3.32PCh. 3 - Prob. 3.33PCh. 3 - Prob. 3.34PCh. 3 - Prob. 3.35PCh. 3 - Prob. 3.36PCh. 3 - Prob. 3.37PCh. 3 - Prob. 3.38PCh. 3 - Prob. 3.39PCh. 3 - Prob. 3.40PCh. 3 - Prob. 3.41PCh. 3 - Prob. 3.42PCh. 3 - Prob. 3.43PCh. 3 - Prob. 3.44PCh. 3 - Prob. 3.45PCh. 3 - Prob. 3.46PCh. 3 - Prob. 3.47PCh. 3 - Prob. 3.48PCh. 3 - Prob. 3.49PCh. 3 - Prob. 3.50PCh. 3 - Prob. 3.51PCh. 3 - Prob. 3.52PCh. 3 - Prob. 3.53PCh. 3 - Prob. 3.54PCh. 3 - Prob. 3.55PCh. 3 - Prob. 3.56PCh. 3 - Prob. 3.57PCh. 3 - Prob. 3.58PCh. 3 - Prob. 3.59PCh. 3 - Prob. 3.60PCh. 3 - Prob. 3.61PCh. 3 - Prob. 3.62PCh. 3 - Prob. 3.63PCh. 3 - Prob. 3.64PCh. 3 - Prob. 3.65PCh. 3 - Prob. 3.66PCh. 3 - Prob. 3.67PCh. 3 - Prob. 3.68PCh. 3 - Prob. 3.69PCh. 3 - Prob. 3.70PCh. 3 - Prob. 3.71PCh. 3 - Prob. 3.72PCh. 3 - Prob. 3.73PCh. 3 - Prob. 3.74PCh. 3 - Prob. 3.75PCh. 3 - Prob. 3.76PCh. 3 - Prob. 3.77PCh. 3 - Prob. 3.78PCh. 3 - Prob. 3.79PCh. 3 - Prob. 3.80PCh. 3 - Prob. 3.81PCh. 3 - Prob. 3.82PCh. 3 - Prob. 3.83PCh. 3 - Prob. 3.84PCh. 3 - Prob. 3.85PCh. 3 - Prob. 3.86PCh. 3 - Prob. 3.87PCh. 3 - Prob. 3.88PCh. 3 - Prob. 3.89PCh. 3 - Prob. 3.90PCh. 3 - Prob. 3.91PCh. 3 - Prob. 3.92PCh. 3 - Prob. 3.93PCh. 3 - Prob. 3.94PCh. 3 - Prob. 3.95P
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