(a) The components of the vector A → + B →

Question

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Answer 1

Question

Chapter 3, Problem 32QAP

To determine

(a)

The components of the vector A→+B→

Expert Solution

Answer to Problem 32QAP

The x component of the vector A→+B→ is 13 units and its y component is 6 units.

Explanation of Solution

Given:

The components of the vectors A→,B→ and C→

Ax=6Ay=9Bx=7By=−3Cx=0Cy=−6

Formula used:

If A→+B→=P→, then the x component of P→ is given by,

Px=Ax+Bx

And the y component of P→ is given by,

Py=Ay+By

Calculation:

Substitute the given values of the variables in the formula and calculate the x component.

Px=Ax+Bx=6+7=13

Substitute the given values of the variables in the formula and calculate the y component.

Py=Ay+By=9−3=6

Conclusion:

The x component of the vector A→+B→ is 13 units and its y component is 6 units.

To determine

(b)

The components of the vector A→−2C→.

Expert Solution

Answer to Problem 32QAP

The x component of the vector A→−2C→ is 6 units and the y component is 21 units.

Explanation of Solution

Given:

The components of the vectors A→,B→ and C→

Ax=6Ay=9Bx=7By=−3Cx=0Cy=−6

Formula used:

If A→−2C→=Q→, then the x component of the vector Q→ is given by,

Qx=Ax−2Cx

The y component is given by,

Qy=Ay−2Cy

Calculation:

Substitute the given values of the variables in the formula and calculate the x component.

Qx=Ax−2Cx=6−2×0=6

Substitute the given values of the variables in the formula and calculate the y component.

Qy=Ay−2Cy=9−2×−6=21

Conclusion:

The x component of the vector A→−2C→ is 6 units and the y component is 21 units.

To determine

(c)

The components of the vector A→+B→−C→.

Expert Solution

Answer to Problem 32QAP

The x component of the vector A→+B→−C→ is 13 units and the y component is 12 units.

Explanation of Solution

Given:

The components of the vectors A→,B→ and C→

Ax=6Ay=9Bx=7By=−3Cx=0Cy=−6

Formula used:

If A→+B→−C→=R→, then, the x component of the vector R→ is given by,

Rx=Ax+Bx−Cx

The y component is given by,

Ry=Ay+By−Cy

Calculation:

Substitute the given values of the variables in the formula and calculate the x component.

Rx=Ax+Bx−Cx=6+7−0=13

Substitute the given values of the variables in the formula and calculate the y component.

Ry=Ay+By−Cy=9+−3−−6=12

Conclusion:

The x component of the vector A→+B→−C→ is 13 units and the y component is 12 units.

To determine

(d)

The components of the vector A→+12B→−3C→.

Expert Solution

Answer to Problem 32QAP

The x component of the vector A→+12B→−3C→ is 9.5 units and the y component is 25.5 units.

Explanation of Solution

Given:

The components of the vectors A→,B→ and C→

Ax=6Ay=9Bx=7By=−3Cx=0Cy=−6

Formula used:

If A→+12B→−3C→=S→, then its x component is given by,

Sx=Ax+12Bx−3Cx

The y component is given by,

Sy=Ay+12By−3Cy

Calculation:

Substitute the given values of the variables in the formula and calculate the x component of the vector A→+12B→−3C→.

Sx=Ax+12Bx−3Cx=6+12×7−3×0=9.5

Substitute the given values of the variables in the formula and calculate the y component of the vector A→+12B→−3C→.

Sy=Ay+12By−3Cy=9+12−3−3−6=25.5

Conclusion:

The x component of the vector A→+12B→−3C→ is 9.5 units and the y component is 25.5 units.

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The force of the quadriceps (Fq) and force of the patellar tendon (Fp) is identical (i.e., 1000 N each). In the figure below angle in blue is Θ and the in green is half Θ (i.e., Θ/2). A) Calculate the patellar reaction force (i.e., R resultant vector is the sum of the horizontal component of the quadriceps and patellar tendon force) at the following joint angles: you need to provide a diagram showing the vector and its components for each part. a1) Θ = 160 degrees, a2) Θ = 90 degrees. NOTE: USE ONLY TRIGNOMETRIC FUNCTIONS (SIN/TAN/COS, NO LAW OF COSINES, NO COMPLICATED ALGEBRAIC EQUATIONS OR ANYTHING ELSE, ETC. Question A has 2 parts!

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Answer 2

Question

Chapter 3, Problem 32QAP

To determine

(a)

The components of the vector A→+B→

Expert Solution

Answer to Problem 32QAP

The x component of the vector A→+B→ is 13 units and its y component is 6 units.

Explanation of Solution

Given:

The components of the vectors A→,B→ and C→

Ax=6Ay=9Bx=7By=−3Cx=0Cy=−6

Formula used:

If A→+B→=P→, then the x component of P→ is given by,

Px=Ax+Bx

And the y component of P→ is given by,

Py=Ay+By

Calculation:

Substitute the given values of the variables in the formula and calculate the x component.

Px=Ax+Bx=6+7=13

Substitute the given values of the variables in the formula and calculate the y component.

Py=Ay+By=9−3=6

Conclusion:

The x component of the vector A→+B→ is 13 units and its y component is 6 units.

To determine

(b)

The components of the vector A→−2C→.

Expert Solution

Answer to Problem 32QAP

The x component of the vector A→−2C→ is 6 units and the y component is 21 units.

Explanation of Solution

Given:

The components of the vectors A→,B→ and C→

Ax=6Ay=9Bx=7By=−3Cx=0Cy=−6

Formula used:

If A→−2C→=Q→, then the x component of the vector Q→ is given by,

Qx=Ax−2Cx

The y component is given by,

Qy=Ay−2Cy

Calculation:

Substitute the given values of the variables in the formula and calculate the x component.

Qx=Ax−2Cx=6−2×0=6

Substitute the given values of the variables in the formula and calculate the y component.

Qy=Ay−2Cy=9−2×−6=21

Conclusion:

The x component of the vector A→−2C→ is 6 units and the y component is 21 units.

To determine

(c)

The components of the vector A→+B→−C→.

Expert Solution

Answer to Problem 32QAP

The x component of the vector A→+B→−C→ is 13 units and the y component is 12 units.

Explanation of Solution

Given:

The components of the vectors A→,B→ and C→

Ax=6Ay=9Bx=7By=−3Cx=0Cy=−6

Formula used:

If A→+B→−C→=R→, then, the x component of the vector R→ is given by,

Rx=Ax+Bx−Cx

The y component is given by,

Ry=Ay+By−Cy

Calculation:

Substitute the given values of the variables in the formula and calculate the x component.

Rx=Ax+Bx−Cx=6+7−0=13

Substitute the given values of the variables in the formula and calculate the y component.

Ry=Ay+By−Cy=9+−3−−6=12

Conclusion:

The x component of the vector A→+B→−C→ is 13 units and the y component is 12 units.

To determine

(d)

The components of the vector A→+12B→−3C→.

Expert Solution

Answer to Problem 32QAP

The x component of the vector A→+12B→−3C→ is 9.5 units and the y component is 25.5 units.

Explanation of Solution

Given:

The components of the vectors A→,B→ and C→

Ax=6Ay=9Bx=7By=−3Cx=0Cy=−6

Formula used:

If A→+12B→−3C→=S→, then its x component is given by,

Sx=Ax+12Bx−3Cx

The y component is given by,

Sy=Ay+12By−3Cy

Calculation:

Substitute the given values of the variables in the formula and calculate the x component of the vector A→+12B→−3C→.

Sx=Ax+12Bx−3Cx=6+12×7−3×0=9.5

Substitute the given values of the variables in the formula and calculate the y component of the vector A→+12B→−3C→.

Sy=Ay+12By−3Cy=9+12−3−3−6=25.5

Conclusion:

The x component of the vector A→+12B→−3C→ is 9.5 units and the y component is 25.5 units.

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Answer 3

Question

Chapter 3, Problem 32QAP

To determine

(a)

The components of the vector A→+B→

Expert Solution

Answer to Problem 32QAP

The x component of the vector A→+B→ is 13 units and its y component is 6 units.

Explanation of Solution

Given:

The components of the vectors A→,B→ and C→

Ax=6Ay=9Bx=7By=−3Cx=0Cy=−6

Formula used:

If A→+B→=P→, then the x component of P→ is given by,

Px=Ax+Bx

And the y component of P→ is given by,

Py=Ay+By

Calculation:

Substitute the given values of the variables in the formula and calculate the x component.

Px=Ax+Bx=6+7=13

Substitute the given values of the variables in the formula and calculate the y component.

Py=Ay+By=9−3=6

Conclusion:

The x component of the vector A→+B→ is 13 units and its y component is 6 units.

To determine

(b)

The components of the vector A→−2C→.

Expert Solution

Answer to Problem 32QAP

The x component of the vector A→−2C→ is 6 units and the y component is 21 units.

Explanation of Solution

Given:

The components of the vectors A→,B→ and C→

Ax=6Ay=9Bx=7By=−3Cx=0Cy=−6

Formula used:

If A→−2C→=Q→, then the x component of the vector Q→ is given by,

Qx=Ax−2Cx

The y component is given by,

Qy=Ay−2Cy

Calculation:

Substitute the given values of the variables in the formula and calculate the x component.

Qx=Ax−2Cx=6−2×0=6

Substitute the given values of the variables in the formula and calculate the y component.

Qy=Ay−2Cy=9−2×−6=21

Conclusion:

The x component of the vector A→−2C→ is 6 units and the y component is 21 units.

To determine

(c)

The components of the vector A→+B→−C→.

Expert Solution

Answer to Problem 32QAP

The x component of the vector A→+B→−C→ is 13 units and the y component is 12 units.

Explanation of Solution

Given:

The components of the vectors A→,B→ and C→

Ax=6Ay=9Bx=7By=−3Cx=0Cy=−6

Formula used:

If A→+B→−C→=R→, then, the x component of the vector R→ is given by,

Rx=Ax+Bx−Cx

The y component is given by,

Ry=Ay+By−Cy

Calculation:

Substitute the given values of the variables in the formula and calculate the x component.

Rx=Ax+Bx−Cx=6+7−0=13

Substitute the given values of the variables in the formula and calculate the y component.

Ry=Ay+By−Cy=9+−3−−6=12

Conclusion:

The x component of the vector A→+B→−C→ is 13 units and the y component is 12 units.

To determine

(d)

The components of the vector A→+12B→−3C→.

Expert Solution

Answer to Problem 32QAP

The x component of the vector A→+12B→−3C→ is 9.5 units and the y component is 25.5 units.

Explanation of Solution

Given:

The components of the vectors A→,B→ and C→

Ax=6Ay=9Bx=7By=−3Cx=0Cy=−6

Formula used:

If A→+12B→−3C→=S→, then its x component is given by,

Sx=Ax+12Bx−3Cx

The y component is given by,

Sy=Ay+12By−3Cy

Calculation:

Substitute the given values of the variables in the formula and calculate the x component of the vector A→+12B→−3C→.

Sx=Ax+12Bx−3Cx=6+12×7−3×0=9.5

Substitute the given values of the variables in the formula and calculate the y component of the vector A→+12B→−3C→.

Sy=Ay+12By−3Cy=9+12−3−3−6=25.5

Conclusion:

The x component of the vector A→+12B→−3C→ is 9.5 units and the y component is 25.5 units.

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Answer 4

Question

Chapter 3, Problem 32QAP

To determine

(a)

The components of the vector A→+B→

Expert Solution

Answer to Problem 32QAP

The x component of the vector A→+B→ is 13 units and its y component is 6 units.

Explanation of Solution

Given:

The components of the vectors A→,B→ and C→

Ax=6Ay=9Bx=7By=−3Cx=0Cy=−6

Formula used:

If A→+B→=P→, then the x component of P→ is given by,

Px=Ax+Bx

And the y component of P→ is given by,

Py=Ay+By

Calculation:

Substitute the given values of the variables in the formula and calculate the x component.

Px=Ax+Bx=6+7=13

Substitute the given values of the variables in the formula and calculate the y component.

Py=Ay+By=9−3=6

Conclusion:

The x component of the vector A→+B→ is 13 units and its y component is 6 units.

To determine

(b)

The components of the vector A→−2C→.

Expert Solution

Answer to Problem 32QAP

The x component of the vector A→−2C→ is 6 units and the y component is 21 units.

Explanation of Solution

Given:

The components of the vectors A→,B→ and C→

Ax=6Ay=9Bx=7By=−3Cx=0Cy=−6

Formula used:

If A→−2C→=Q→, then the x component of the vector Q→ is given by,

Qx=Ax−2Cx

The y component is given by,

Qy=Ay−2Cy

Calculation:

Substitute the given values of the variables in the formula and calculate the x component.

Qx=Ax−2Cx=6−2×0=6

Substitute the given values of the variables in the formula and calculate the y component.

Qy=Ay−2Cy=9−2×−6=21

Conclusion:

The x component of the vector A→−2C→ is 6 units and the y component is 21 units.

To determine

(c)

The components of the vector A→+B→−C→.

Expert Solution

Answer to Problem 32QAP

The x component of the vector A→+B→−C→ is 13 units and the y component is 12 units.

Explanation of Solution

Given:

The components of the vectors A→,B→ and C→

Ax=6Ay=9Bx=7By=−3Cx=0Cy=−6

Formula used:

If A→+B→−C→=R→, then, the x component of the vector R→ is given by,

Rx=Ax+Bx−Cx

The y component is given by,

Ry=Ay+By−Cy

Calculation:

Substitute the given values of the variables in the formula and calculate the x component.

Rx=Ax+Bx−Cx=6+7−0=13

Substitute the given values of the variables in the formula and calculate the y component.

Ry=Ay+By−Cy=9+−3−−6=12

Conclusion:

The x component of the vector A→+B→−C→ is 13 units and the y component is 12 units.

To determine

(d)

The components of the vector A→+12B→−3C→.

Expert Solution

Answer to Problem 32QAP

The x component of the vector A→+12B→−3C→ is 9.5 units and the y component is 25.5 units.

Explanation of Solution

Given:

The components of the vectors A→,B→ and C→

Ax=6Ay=9Bx=7By=−3Cx=0Cy=−6

Formula used:

If A→+12B→−3C→=S→, then its x component is given by,

Sx=Ax+12Bx−3Cx

The y component is given by,

Sy=Ay+12By−3Cy

Calculation:

Substitute the given values of the variables in the formula and calculate the x component of the vector A→+12B→−3C→.

Sx=Ax+12Bx−3Cx=6+12×7−3×0=9.5

Substitute the given values of the variables in the formula and calculate the y component of the vector A→+12B→−3C→.

Sy=Ay+12By−3Cy=9+12−3−3−6=25.5

Conclusion:

The x component of the vector A→+12B→−3C→ is 9.5 units and the y component is 25.5 units.

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Answer 5

Chapter 3, Problem 32QAP

To determine

(a)

The components of the vector A→+B→

Expert Solution

Answer to Problem 32QAP

The x component of the vector A→+B→ is 13 units and its y component is 6 units.

Explanation of Solution

Given:

The components of the vectors A→,B→ and C→

Ax=6Ay=9Bx=7By=−3Cx=0Cy=−6

Formula used:

If A→+B→=P→, then the x component of P→ is given by,

Px=Ax+Bx

And the y component of P→ is given by,

Py=Ay+By

Calculation:

Substitute the given values of the variables in the formula and calculate the x component.

Px=Ax+Bx=6+7=13

Substitute the given values of the variables in the formula and calculate the y component.

Py=Ay+By=9−3=6

Conclusion:

The x component of the vector A→+B→ is 13 units and its y component is 6 units.

To determine

(b)

The components of the vector A→−2C→.

Expert Solution

Answer to Problem 32QAP

The x component of the vector A→−2C→ is 6 units and the y component is 21 units.

Explanation of Solution

Given:

The components of the vectors A→,B→ and C→

Ax=6Ay=9Bx=7By=−3Cx=0Cy=−6

Formula used:

If A→−2C→=Q→, then the x component of the vector Q→ is given by,

Qx=Ax−2Cx

The y component is given by,

Qy=Ay−2Cy

Calculation:

Substitute the given values of the variables in the formula and calculate the x component.

Qx=Ax−2Cx=6−2×0=6

Substitute the given values of the variables in the formula and calculate the y component.

Qy=Ay−2Cy=9−2×−6=21

Conclusion:

The x component of the vector A→−2C→ is 6 units and the y component is 21 units.

To determine

(c)

The components of the vector A→+B→−C→.

Expert Solution

Answer to Problem 32QAP

The x component of the vector A→+B→−C→ is 13 units and the y component is 12 units.

Explanation of Solution

Given:

The components of the vectors A→,B→ and C→

Ax=6Ay=9Bx=7By=−3Cx=0Cy=−6

Formula used:

If A→+B→−C→=R→, then, the x component of the vector R→ is given by,

Rx=Ax+Bx−Cx

The y component is given by,

Ry=Ay+By−Cy

Calculation:

Substitute the given values of the variables in the formula and calculate the x component.

Rx=Ax+Bx−Cx=6+7−0=13

Substitute the given values of the variables in the formula and calculate the y component.

Ry=Ay+By−Cy=9+−3−−6=12

Conclusion:

The x component of the vector A→+B→−C→ is 13 units and the y component is 12 units.

To determine

(d)

The components of the vector A→+12B→−3C→.

Expert Solution

Answer to Problem 32QAP

The x component of the vector A→+12B→−3C→ is 9.5 units and the y component is 25.5 units.

Explanation of Solution

Given:

The components of the vectors A→,B→ and C→

Ax=6Ay=9Bx=7By=−3Cx=0Cy=−6

Formula used:

If A→+12B→−3C→=S→, then its x component is given by,

Sx=Ax+12Bx−3Cx

The y component is given by,

Sy=Ay+12By−3Cy

Calculation:

Substitute the given values of the variables in the formula and calculate the x component of the vector A→+12B→−3C→.

Sx=Ax+12Bx−3Cx=6+12×7−3×0=9.5

Substitute the given values of the variables in the formula and calculate the y component of the vector A→+12B→−3C→.

Sy=Ay+12By−3Cy=9+12−3−3−6=25.5

Conclusion:

The x component of the vector A→+12B→−3C→ is 9.5 units and the y component is 25.5 units.

Answer 6

Chapter 3, Problem 32QAP

To determine

(a)

The components of the vector A→+B→

Expert Solution

Answer to Problem 32QAP

The x component of the vector A→+B→ is 13 units and its y component is 6 units.

Explanation of Solution

Given:

The components of the vectors A→,B→ and C→

Ax=6Ay=9Bx=7By=−3Cx=0Cy=−6

Formula used:

If A→+B→=P→, then the x component of P→ is given by,

Px=Ax+Bx

And the y component of P→ is given by,

Py=Ay+By

Calculation:

Substitute the given values of the variables in the formula and calculate the x component.

Px=Ax+Bx=6+7=13

Substitute the given values of the variables in the formula and calculate the y component.

Py=Ay+By=9−3=6

Conclusion:

The x component of the vector A→+B→ is 13 units and its y component is 6 units.

Answer 7

Chapter 3, Problem 32QAP

To determine

(a)

The components of the vector A→+B→

Answer 8

Expert Solution

Answer to Problem 32QAP

The x component of the vector A→+B→ is 13 units and its y component is 6 units.

Answer 9

Expert Solution

Answer 10

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

Given:

The components of the vectors A→,B→ and C→

Ax=6Ay=9Bx=7By=−3Cx=0Cy=−6

Formula used:

If A→+B→=P→, then the x component of P→ is given by,

Px=Ax+Bx

And the y component of P→ is given by,

Py=Ay+By

Calculation:

Substitute the given values of the variables in the formula and calculate the x component.

Px=Ax+Bx=6+7=13

Substitute the given values of the variables in the formula and calculate the y component.

Py=Ay+By=9−3=6

Conclusion:

The x component of the vector A→+B→ is 13 units and its y component is 6 units.

Answer 13

To determine

(b)

The components of the vector A→−2C→.

Expert Solution

Answer to Problem 32QAP

The x component of the vector A→−2C→ is 6 units and the y component is 21 units.

Explanation of Solution

Given:

The components of the vectors A→,B→ and C→

Ax=6Ay=9Bx=7By=−3Cx=0Cy=−6

Formula used:

If A→−2C→=Q→, then the x component of the vector Q→ is given by,

Qx=Ax−2Cx

The y component is given by,

Qy=Ay−2Cy

Calculation:

Substitute the given values of the variables in the formula and calculate the x component.

Qx=Ax−2Cx=6−2×0=6

Substitute the given values of the variables in the formula and calculate the y component.

Qy=Ay−2Cy=9−2×−6=21

Conclusion:

The x component of the vector A→−2C→ is 6 units and the y component is 21 units.

Answer 14

To determine

(b)

The components of the vector A→−2C→.

Answer 15

Expert Solution

Answer to Problem 32QAP

The x component of the vector A→−2C→ is 6 units and the y component is 21 units.

Answer 16

Expert Solution

Answer 17

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

Given:

The components of the vectors A→,B→ and C→

Ax=6Ay=9Bx=7By=−3Cx=0Cy=−6

Formula used:

If A→−2C→=Q→, then the x component of the vector Q→ is given by,

Qx=Ax−2Cx

The y component is given by,

Qy=Ay−2Cy

Calculation:

Substitute the given values of the variables in the formula and calculate the x component.

Qx=Ax−2Cx=6−2×0=6

Substitute the given values of the variables in the formula and calculate the y component.

Qy=Ay−2Cy=9−2×−6=21

Conclusion:

The x component of the vector A→−2C→ is 6 units and the y component is 21 units.

Answer 20

To determine

(c)

The components of the vector A→+B→−C→.

Expert Solution

Answer to Problem 32QAP

The x component of the vector A→+B→−C→ is 13 units and the y component is 12 units.

Explanation of Solution

Given:

The components of the vectors A→,B→ and C→

Ax=6Ay=9Bx=7By=−3Cx=0Cy=−6

Formula used:

If A→+B→−C→=R→, then, the x component of the vector R→ is given by,

Rx=Ax+Bx−Cx

The y component is given by,

Ry=Ay+By−Cy

Calculation:

Substitute the given values of the variables in the formula and calculate the x component.

Rx=Ax+Bx−Cx=6+7−0=13

Substitute the given values of the variables in the formula and calculate the y component.

Ry=Ay+By−Cy=9+−3−−6=12

Conclusion:

The x component of the vector A→+B→−C→ is 13 units and the y component is 12 units.

Answer 21

To determine

(c)

The components of the vector A→+B→−C→.

Answer 22

Expert Solution

Answer to Problem 32QAP

The x component of the vector A→+B→−C→ is 13 units and the y component is 12 units.

Answer 23

Expert Solution

Answer 24

Expert Solution

Answer 25

Expert Solution

Answer 26

Explanation of Solution

Given:

The components of the vectors A→,B→ and C→

Ax=6Ay=9Bx=7By=−3Cx=0Cy=−6

Formula used:

If A→+B→−C→=R→, then, the x component of the vector R→ is given by,

Rx=Ax+Bx−Cx

The y component is given by,

Ry=Ay+By−Cy

Calculation:

Substitute the given values of the variables in the formula and calculate the x component.

Rx=Ax+Bx−Cx=6+7−0=13

Substitute the given values of the variables in the formula and calculate the y component.

Ry=Ay+By−Cy=9+−3−−6=12

Conclusion:

The x component of the vector A→+B→−C→ is 13 units and the y component is 12 units.

Answer 27

To determine

(d)

The components of the vector A→+12B→−3C→.

Expert Solution

Answer to Problem 32QAP

The x component of the vector A→+12B→−3C→ is 9.5 units and the y component is 25.5 units.

Explanation of Solution

Given:

The components of the vectors A→,B→ and C→

Ax=6Ay=9Bx=7By=−3Cx=0Cy=−6

Formula used:

If A→+12B→−3C→=S→, then its x component is given by,

Sx=Ax+12Bx−3Cx

The y component is given by,

Sy=Ay+12By−3Cy

Calculation:

Substitute the given values of the variables in the formula and calculate the x component of the vector A→+12B→−3C→.

Sx=Ax+12Bx−3Cx=6+12×7−3×0=9.5

Substitute the given values of the variables in the formula and calculate the y component of the vector A→+12B→−3C→.

Sy=Ay+12By−3Cy=9+12−3−3−6=25.5

Conclusion:

The x component of the vector A→+12B→−3C→ is 9.5 units and the y component is 25.5 units.

Answer 28

To determine

(d)

The components of the vector A→+12B→−3C→.

Answer 29

Expert Solution

Answer to Problem 32QAP

The x component of the vector A→+12B→−3C→ is 9.5 units and the y component is 25.5 units.

Answer 30

Expert Solution

Answer 31

Expert Solution

Answer 32

Expert Solution

Answer 33

Explanation of Solution

Given:

The components of the vectors A→,B→ and C→

Ax=6Ay=9Bx=7By=−3Cx=0Cy=−6

Formula used:

If A→+12B→−3C→=S→, then its x component is given by,

Sx=Ax+12Bx−3Cx

The y component is given by,

Sy=Ay+12By−3Cy

Calculation:

Substitute the given values of the variables in the formula and calculate the x component of the vector A→+12B→−3C→.

Sx=Ax+12Bx−3Cx=6+12×7−3×0=9.5

Substitute the given values of the variables in the formula and calculate the y component of the vector A→+12B→−3C→.

Sy=Ay+12By−3Cy=9+12−3−3−6=25.5

Conclusion:

The x component of the vector A→+12B→−3C→ is 9.5 units and the y component is 25.5 units.

Answer 34

Ch. 3 - Prob. 1QAP Ch. 3 - Prob. 2QAP Ch. 3 - Prob. 3QAP Ch. 3 - Prob. 4QAP Ch. 3 - Prob. 5QAP Ch. 3 - Prob. 6QAP Ch. 3 - Prob. 7QAP Ch. 3 - Prob. 8QAP Ch. 3 - Prob. 9QAP Ch. 3 - Prob. 10QAP

(a) The components of the vector A → + B →

Concept explainers

Videos

(a)

The components of the vector A→+B→

Answer to Problem 32QAP

Explanation of Solution

(b)

The components of the vector A→−2C→.

Answer to Problem 32QAP

Explanation of Solution

(c)

The components of the vector A→+B→−C→.

Answer to Problem 32QAP

Explanation of Solution

(d)

The components of the vector A→+12B→−3C→.

Answer to Problem 32QAP

Explanation of Solution

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Chapter 3 Solutions

(a) The components of the vector A → + B →

Concept explainers

Videos

(a) The components of the vector A→+B→

Answer to Problem 32QAP

Explanation of Solution

(b) The components of the vector A→−2C→.

Answer to Problem 32QAP

Explanation of Solution

(c) The components of the vector A→+B→−C→.

Answer to Problem 32QAP

Explanation of Solution

(d) The components of the vector A→+12B→−3C→.

Answer to Problem 32QAP

Explanation of Solution

Want to see more full solutions like this?

Chapter 3 Solutions

(a)

The components of the vector A→+B→

(b)

The components of the vector A→−2C→.

(c)

The components of the vector A→+B→−C→.

(d)

The components of the vector A→+12B→−3C→.