Explanation Given information: The diameter of the pipe is 36 in , carries oil of specific gravity 0.89 at 1000000 bbl / day with a friction loss of 13 ft / 1000 ft . The pumping stations are planned at every 10 mi along the pipe. The Figure-(1) shows the sections at the pipe. Figure-(1) Here, the section (1) and section (2) represent the distance between two pumping stations. Write the expression for the net head loss. h f = h n e t n .... (I) Here, the net head loss is h n e t , the lead loss is h f and the distance of the pumping stations at n . Write the expression for the Bernoulli’s equation between two pumps. p 1 ρ + V 1 2 2 + z 1 g = p 2 ρ + V 2 2 2 + z 2 g + h f g ( p 1 ρ − p 2 ρ ) + ( V 1 2 2 − V 2 2 2 ) + ( z 1 g − z 2 g ) = h f g h f g = ( p 1 ρ − p 2 ρ ) + 1 2 { ( V 1 − V 2 ) ( V 1 + V 2 ) } + ( z 1 − z 2 ) g .... (II) Here, the pressure at section (1) is p 1 , the velocity at section (1) is V 1 , the height of the section (1) from the datum is z 1 , the pressure at section (2) is p 2 , the velocity at section (2) is V 2 , the height of the section (2) from the datum is z 2 , the density of oil is ρ , the head loss due to friction is h f and the acceleration due to gravity is g . Since the area of the pipe is constant; so the velocity difference at both the section is zero. V 1 − V 2 = 0 Since both the section are at the same level from the datum plane, so the difference between the datum height is zero. z 1 − z 2 = 0 Substitute 0 for V 1 − V 2 and 0 for z 1 − z 2 in Equation (II). h f g = ( p 1 ρ − p 2 ρ ) + 1 2 { 0 × ( V 1 + V 2 ) } + ( 0 ) g h f = ( p 1 ρ g − p 2 ρ g ) = p 1 − p 2 ρ g .... (III) Write the expression for the density of oil. ρ = S G ρ w a t e r Here, the specific gravity of oil is S G and the density of water is ρ w a t e r . Substitute S G ρ w a t e r for ρ in Equation (II). h f = p 1 − p 2 S G ρ w a t e r g p 1 − p 2 = S G ρ w a t e r g h f

8th Edition

ISBN: 9780073398273

Author: Frank M. White

Publisher: McGraw-Hill Education

See similar textbooks

Question

Chapter 3, Problem 3.173P

To determine

The horsepower delivered to the oil by each pump.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 3, Problem 3.172P

Chapter 3, Problem 3.174P

Students have asked these similar questions

motor supplies 200 kW at 6 Hz to flange A of the shaft shown in Figure. Gear B transfers 125 W of power to operating machinery in the factory, and the remaining power in the shaft is mansferred by gear D. Shafts (1) and (2) are solid aluminum (G = 28 GPa) shafts that have the same diameter and an allowable shear stress of t= 40 MPa. Shaft (3) is a solid steel (G = 80 GPa) shaft with an allowable shear stress of t = 55 MPa. Determine: a) the minimum permissible diameter for aluminum shafts (1) and (2) b) the minimum permissible diameter for steel shaft (3). c) the rotation angle of gear D with respect to flange A if the shafts have the minimum permissible diameters as determined in (a) and (b).

First monthly exam Gas dynamics Third stage Q1/Water at 15° C flow through a 300 mm diameter riveted steel pipe, E-3 mm with a head loss of 6 m in 300 m length. Determine the flow rate in pipe. Use moody chart. Q2/ Assume a car's exhaust system can be approximated as 14 ft long and 0.125 ft-diameter cast-iron pipe ( = 0.00085 ft) with the equivalent of (6) regular 90° flanged elbows (KL = 0.3) and a muffler. The muffler acts as a resistor with a loss coefficient of KL= 8.5. Determine the pressure at the beginning of the exhaust system (pl) if the flowrate is 0.10 cfs, and the exhaust has the same properties as air.(p = 1.74 × 10-3 slug/ft³, u= 4.7 x 10-7 lb.s/ft²) Use moody chart (1) MIDAS Kel=0.3 Q3/Liquid ammonia at -20°C is flowing through a 30 m long section of a 5 mm diameter copper tube(e = 1.5 × 10-6 m) at a rate of 0.15 kg/s. Determine the pressure drop and the head losses. .μ= 2.36 × 10-4 kg/m.s)p = 665.1 kg/m³

2/Y Y+1 2Cp Q1/ Show that Cda Az x P1 mactual Cdf Af R/T₁ 2pf(P1-P2-zxgxpf) Q2/ A simple jet carburetor has to supply 5 Kg of air per minute. The air is at a pressure of 1.013 bar and a temperature of 27 °C. Calculate the throat diameter of the choke for air flow velocity of 90 m/sec. Take velocity coefficient to be 0.8. Assume isentropic flow and the flow to be compressible. Quiz/ Determine the air-fuel ratio supplied at 5000 m altitude by a carburetor which is adjusted to give an air-fuel ratio of 14:1 at sea level where air temperature is 27 °C and pressure is 1.013 bar. The temperature of air decreases with altitude as given by the expression The air pressure decreases with altitude as per relation h = 19200 log10 (1.013), where P is in bar. State any assumptions made. t = ts P 0.0065h

Chapter 3 Solutions

Fluid Mechanics

Ch. 3 - Prob. 3.1P Ch. 3 - Consider the angular momentum relation in the form...Ch. 3 - For steady low-Reynolds-number (laminar) flow...Ch. 3 - Water at 20°C flows through a long elliptical duct...Ch. 3 - Water at 20°C flows through a 5-in-diameter smooth...Ch. 3 - Water fills a cylindrical tank to depth h. The...Ch. 3 - A spherical tank, of diameter 35 cm, is leaking...Ch. 3 - Three pipes steadily deliver water at 20°C to a...Ch. 3 - A laboratory test tank contains seawater of...Ch. 3 - Water flowing through an 8-cm-diameter pipe enters...

Knowledge Booster