Using MIS (9th Edition)
9th Edition
ISBN: 9780134106786
Author: David M. Kroenke, Randall J. Boyle
Publisher: PEARSON
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Chapter 3, Problem 3.10CS3
Program Plan Intro
About Amazon.com:
Amazon.com is aiming to prove that they are one of the leading online retailers by giving the people with fulfilled services and efficient product. They sell their own goods as well as the third party goods. Products like electronic items, software products, hardware products, kitchen items, jewelry, watches, baby product, dress for men, women, and children.
Companies and organizations uses the Amazon.com to save their money, and the things required to run their business. They provide efficient goods and products to run their business profitable. They offer friendly relationship to the suppliers, retailers as well as customers. They attract people by providing the cost efficient goods.
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Exercise 1 Function and Structure [30 pts]
Please debug the following program and answer the following questions. There is a cycle in a linked
list if some node in the list can be reached again by continuously following the next pointer.
#include
typedef struct node {
int value;
struct node *next;
} node;
int 11_has_cycle (node *first)
if (first
==
node *head =
{
NULL) return 0;
first;
while (head->next != NULL) {
}
if (head
first) {
return 1; }
head = head->next;
return 0;
void test ll_has_cycle () {
int i;
node nodes [6];
for (i = 0; i < 6; i++) {
nodes [i] .next = NULL;
nodes [i].value = i;
}
nodes [0] .next
=
&nodes [1];
nodes [1] .next
=
&nodes [2];
nodes [2] .next
=
&nodes [3];
nodes [3] .next
nodes [4] .next
&nodes [4];
NULL;
nodes [5] .next = &nodes [0];
printf("1. Checking first list for cycles. \n Function 11_has_cycle says it
has s cycle\n\n", 11_has_cycle (&nodes [0])?"a":"no");
printf("2. Checking length-zero list for cycles. \n Function 11_has_cycle
says it has %s…
how to read log logs
Discrete Mathematics for Computer Engineering
Chapter 3 Solutions
Using MIS (9th Edition)
Ch. 3.3 - Prob. 1EGDQCh. 3.3 - Prob. 2EGDQCh. 3.3 - Prob. 3EGDQCh. 3.3 - Prob. 4EGDQCh. 3.3 - Prob. 5EGDQCh. 3.3 - Prob. 6EGDQCh. 3.3 - Prob. 7EGDQCh. 3.3 - Prob. 8EGDQCh. 3.7 - Prob. 1DSDQCh. 3.7 - Prob. 2DSDQ
Ch. 3.7 - Prob. 3DSDQCh. 3.7 - Prob. 4DSDQCh. 3.7 - Prob. 5DSDQCh. 3.8 - Prob. 1SGDQCh. 3.8 - Prob. 2SGDQCh. 3.8 - Prob. 3SGDQCh. 3.8 - Prob. 4SGDQCh. 3.8 - Prob. 1YPCACh. 3.8 - Prob. 2YPCACh. 3.8 - Prob. 3YPCACh. 3.8 - Prob. 4YPCACh. 3.8 - Prob. 3.1ARQCh. 3.8 - Prob. 3.2ARQCh. 3.8 - Prob. 3.3ARQCh. 3.8 - Prob. 3.4ARQCh. 3.8 - Prob. 3.5ARQCh. 3.8 - Prob. 3.6ARQCh. 3.8 - Prob. 3.7ARQCh. 3.8 - Prob. 3.8ARQCh. 3 - Prob. 3.1UYKCh. 3 - Prob. 3.2UYKCh. 3 - Prob. 3.3UYKCh. 3 - Prob. 1CE3Ch. 3 - Prob. 3.4CS3Ch. 3 - Prob. 3.5CS3Ch. 3 - Prob. 3.6CS3Ch. 3 - Prob. 3.7CS3Ch. 3 - Prob. 3.8CS3Ch. 3 - Prob. 3.9CS3Ch. 3 - Prob. 3.10CS3Ch. 3 - Prob. 3.11CS3Ch. 3 - Prob. 3.12CS3Ch. 3 - Prob. 3.13MMLCh. 3 - Prob. 3.14MMLCh. 3 - Prob. 3.15MML
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