Chapter 3, Problem 23QAP

Interpretation Introduction

Interpretation:

The molarity of KOH in solution II should be calculated.

Concept introduction:

The number of moles of a substance is related to mass and molar mass as follows:

$n=\frac{m}{M}$

Here, m is mass and M is molar mass of the substance.

Also, according to Avogadro’s law in 1 mol of a substance there are $6.023\times {10}^{23}$ units of that substance. Here, $6.023\times {10}^{23}$ is known as Avogadro’s number and denoted by symbol $N_A$.

The molarity of a solution is defined as number of moles of solute in 1 L of the solution. It is mathematically represented as follows:

$M=\frac{n}{V}$

Here, n is number of moles of solute and V is volume of solution in L. Thus, the unit of molarity is mol/L.