Database Systems: Design, Implementation, & Management
12th Edition
ISBN: 9781305627482
Author: Carlos Coronel, Steven Morris
Publisher: Cengage Learning
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Chapter 3, Problem 12RQ
Program Plan Intro
A database is a structure that is used to hold data and it referred as a systematic collection of data.
Table:
A table is a logical structure that represents an entity state. It is one of the components of database.
One to Many Relationship:
When one record in a database table is associated with more than one record in another table, the relationship between the two tables is referred as one to many relationship. It is also represented as1: M relationship. This is the opposite of many to one relationship.
RELATIONAL DIAGRAM:
Relational Diagram is also known as Entity Relational Diagram. It is used to define the conceptual view of the database as viewed by the end user. It is used to depict the database’s main components: entities, relationships and attributes. It describes how data is related to each other.
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2. In database lab01, create 4 tables: course, advisor, student, and department (Note: The order of tables below is not proper for creating tables. Please think about which table should be created first)
course (course_id varchar(8), title varchar(50), dept_name varchar(20), credits numeric(2,0), primary key (course_id), foreign key (dept_name) references department (dept_name))
advisor (s_ID varchar(5), i_ID varchar(5), primary key (s_ID), foreign key (s_ID) references student (ID))
student (ID varchar(5), name varchar(20) not null, dept_name varchar(20), tot_cred numeric(3,0), primary key (ID), foreign key (dept_name) references department (dept_name))
department (dept_name varchar(20), building varchar(15), budget numeric(12,2), primary key (dept_name))
. Populate tables (Note: The order of populating table below is not proper. Please think about which table should be populated first)
Populate the table "student" with the data below: ('23121', 'Chavez',…
Create the table that would result from Tstu_code (student).
FIGURE Q3.8 THE CH03_COLLEGEQUE DATABASE TABLES
Database name: Ch03_CollegeQue
Table name: STUDENT
STU CODE PROF_CODE
100278
128569
512272
531235
531268
2
553427
1
Table name: PROFESSOR
PROF CODE DEPT CODE
12
26
36
44
For table EP, the attribute is a foreign key referencing target table For table EP, the attribute is a foreign key referencing target table For table ER the attribute is a foreign key referencing target table For table ER the attribute is a foreign key referencing target table
Chapter 3 Solutions
Database Systems: Design, Implementation, & Management
Ch. 3 - What is the difference between a database and a...Ch. 3 - Prob. 2RQCh. 3 - Prob. 3RQCh. 3 - What are the requirements that two relations must...Ch. 3 - Which relational algebra operators can be applied...Ch. 3 - Explain why the data dictionary is sometimes...Ch. 3 - A database user manually notes that The file...Ch. 3 - Prob. 8RQCh. 3 - Prob. 9RQCh. 3 - Prob. 10RQ
Ch. 3 - Prob. 11RQCh. 3 - Prob. 12RQCh. 3 - Use Figure Q3.13 to answer Questions 1317. FIGURE...Ch. 3 - Create the table that results from applying a...Ch. 3 - Write the relational algebra formula to apply an...Ch. 3 - Create the table that results from applying an...Ch. 3 - Using the tables in Figure Q3.13, create the table...Ch. 3 - Prob. 18RQCh. 3 - Prob. 19RQCh. 3 - Prob. 20RQCh. 3 - Identify and describe the components of the table...Ch. 3 - Identify the primary keys. FIGURE Q3.22 THE...Ch. 3 - Identify the foreign keys. FIGURE Q3.22 THE...Ch. 3 - Create the ERM. FIGURE Q3.22 THE CH03_THEATER...Ch. 3 - Create the relational diagram to show the...Ch. 3 - Prob. 26RQCh. 3 - What would be the conceptual view of the INDEX...Ch. 3 - Prob. 1PCh. 3 - Prob. 2PCh. 3 - Do the tables exhibit referential integrity?...Ch. 3 - Describe the type(s) of relationship(s) between...Ch. 3 - Prob. 5PCh. 3 - Prob. 6PCh. 3 - Prob. 7PCh. 3 - Prob. 8PCh. 3 - Create the relational diagram to show the...Ch. 3 - Prob. 10PCh. 3 - Prob. 11PCh. 3 - Create the relational diagram to show the...Ch. 3 - Prob. 13PCh. 3 - Do the tables exhibit referential integrity?...Ch. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - For each table, identify the primary key and the...Ch. 3 - Prob. 18PCh. 3 - Do the tables exhibit referential integrity?...Ch. 3 - Identify the TRUCK tables candidate key(s). FIGURE...Ch. 3 - For each table, identify a superkey and a...Ch. 3 - Prob. 22PCh. 3 - Prob. 23PCh. 3 - Prob. 24PCh. 3 - Create the ERD. (Hint: Look at the table contents....Ch. 3 - Prob. 26PCh. 3 - Prob. 27PCh. 3 - Prob. 28PCh. 3 - Create the table that would result from applying...Ch. 3 - Create the table that would result from applying...Ch. 3 - Create the table that would result from applying a...
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- Create the table that results from applying an INTERSECT relational operator to the tables shown in Figure Q3.13. FIGURE Q3.13 THE CH03_VENDINGCO DATABASE TABLESarrow_forwardUse Figure Q3.13 to answer Questions 1317. FIGURE Q3.13 THE CH03_VENDINGCO DATABASE TABLES Write the relational algebra formula to apply a UNION relational operator to the tables shown in Figure Q3.13.arrow_forwardFor each table, identify the primary key and the foreign key(s). If a table does not have a foreign key, write None. FIGURE P3.17 THE CH03_TRANSCO DATABASE TABLESarrow_forward
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- Write a database description for each of the relations shown, using SQL DDL (shorten, abbreviate, or change any data names, as needed for your SQL version). Assume the following attribute data types:arrow_forwardThe relational database below contains two related tables - “Supplier” and “Product”: “Product” table: Primary key = Prod-code, Foreign key = Supp-code Prod-code Prod -name Prod -desript Prod -stocktype Prod -stocklevel Prod -expireDate Supp-code 10010 aaa qwert 615 123445677 2017-11-14 501 10011 bbb asdfgg 615 234567899 2017-11-16 501 10012 ccc zxxcvv 234 345678900 2017-11-13 502 10013 eee ytuytu 234 454577777 2017-10-13 503 10014 jjj werewr 231 436436885 2017-10-23 503 10015 sdg rtyrtyry 275 676446322 2017-10-30 504 10016 ewt erterter 789 232317879 2017-12-30 501 “Supplier” table: Primary key = Supp -code, No Foreign key Supp -code Supp -lname Supp -fname Supp -Initial Supp -areacode Supp -phone 501 xxx qwert F 615 123445678 502 yyy asdfgg B 615 234567890 503 zzz zxxcvv X 234 345678901…arrow_forwardThe relational database below contains two related tables - “Supplier” and “Product”: “Product” table: Primary key = Prod-code, Foreign key = Supp-code Prod-code Prod -name Prod -desript Prod -stocktype Prod -stocklevel Prod -expireDate Supp-code 10010 aaa qwert 615 123445677 2017-11-14 501 10011 bbb asdfgg 615 234567899 2017-11-16 501 10012 ccc zxxcvv 234 345678900 2017-11-13 502 10013 eee ytuytu 234 454577777 2017-10-13 503 10014 jjj werewr 231 436436885 2017-10-23 503 10015 sdg rtyrtyry 275 676446322 2017-10-30 504 10016 ewt erterter 789 232317879 2017-12-30 501 “Supplier” table: Primary key = Supp -code, No Foreign key Supp -code Supp -lname Supp -fname Supp -Initial Supp -areacode Supp -phone 501 xxx qwert F 615 123445678 502 yyy asdfgg B 615 234567890 503 zzz zxxcvv X 234 345678901…arrow_forward
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