Chapter 29.2, Problem 37SSC

(a)

To determine

To estimate increment in the potential difference across the diode and the resistor for a forward-bias diode connected by a battery with a series resistor so that there is 10 mA of current. The potential difference is always about 0.70 V. The battery potential difference is then increased by 1 V.

Answer to Problem 37SSC

The increase in the potential difference of the diode is 1 V.

Explanation of Solution

Introduction:

The potential difference does not vary if the voltage across the diode is unchanged..

The increase in the potential difference of diode is 1 V because the voltage is unchanged across the diode and remains 0.70 V as given.

Conclusion:

Hence, the increase in the potential difference of the diode is 1 V.

(b)

To determine

About how much the current through the resistor increases for a forward-bias diode connected by a battery with a series resistor so that there is 10 mA of current. The potential difference is always about 0.70 V. The battery potential difference is then increased by 1 V.

Answer to Problem 37SSC

The increase in the current is $\frac{V}{R}$ times.

Explanation of Solution

Introduction:

The increase in current depends on the potential and the value of resistance.

The increase in the current is $\frac{V}{R}$ times, where V is the potential across the resistor and R is the resistance of the resistor.

Conclusion:

Hence, the increase in the current is $\frac{V}{R}$ times.