Bundle: Physics for Scientists and Engineers with Modern Physics, Loose-leaf Version, 9th + WebAssign Printed Access Card, Multi-Term
9th Edition
ISBN: 9781305932302
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
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Chapter 29, Problem 72AP
(a)
To determine
The speed of blood for the given magnetic field.
(b)
To determine
The reason for the electrode
(c)
To determine
Whether the sign of the emf depends on the sign of the mobile ions in the blood.
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Using an electromagnetic flowmeter (Fig. P19.69), aheart surgeon monitors the flow rate of blood through anartery. Electrodes A and B make contact with the outer surfaceof the blood vessel, which has interior diameter 3.00 mm.
(a) For a magnetic field magnitude of 0.040 0 T, a potentialdifference of 160 µV appears between the electrodes. Calculatethe speed of the blood. (b) Verify that electrode A is positive,as shown. Does the sign of the emf depend on whetherthe mobile ions in the blood are predominantly positively ornegatively charged? Explain.
Figure P19.14a is a diagram of a device called a velocity selector,in which particles of a specific velocity pass throughundeflected while those with greater or lesser velocities aredeflected either upwards or downwards. An electric field is
directed perpendicular to a magnetic field, producing anelectric force and a magnetic force on the charged particlethat can be equal in magnitude and opposite in direction(Fig. P19.14b) and hence cancel. Show that particles witha speed of v = E/B will pass through the velocity selectorundeflected.
(a) Find the direction of the force on a proton moving through the magnetic fields in Figure P19.2, as shown. (b) Repeat part (a), assuming the moving particle is an electron.
Chapter 29 Solutions
Bundle: Physics for Scientists and Engineers with Modern Physics, Loose-leaf Version, 9th + WebAssign Printed Access Card, Multi-Term
Ch. 29.1 - An electron moves in the plane of this paper...Ch. 29.2 - Prob. 29.2QQCh. 29.4 - A wire carries current in the plane of this paper...Ch. 29.5 - (i) Rank the magnitudes of the torques acting on...Ch. 29 - Prob. 1OQCh. 29 - Prob. 2OQCh. 29 - Prob. 3OQCh. 29 - Prob. 4OQCh. 29 - Prob. 5OQCh. 29 - Prob. 6OQ
Ch. 29 - Prob. 7OQCh. 29 - Prob. 8OQCh. 29 - Prob. 9OQCh. 29 - Prob. 10OQCh. 29 - Prob. 11OQCh. 29 - Prob. 12OQCh. 29 - Prob. 13OQCh. 29 - Prob. 1CQCh. 29 - Prob. 2CQCh. 29 - Prob. 3CQCh. 29 - Prob. 4CQCh. 29 - Prob. 5CQCh. 29 - Prob. 6CQCh. 29 - Prob. 7CQCh. 29 - At the equator, near the surface of the Earth, the...Ch. 29 - Prob. 2PCh. 29 - Prob. 3PCh. 29 - Consider an electron near the Earths equator. In...Ch. 29 - Prob. 5PCh. 29 - A proton moving at 4.00 106 m/s through a...Ch. 29 - Prob. 7PCh. 29 - Prob. 8PCh. 29 - A proton travels with a speed of 5.02 106 m/s in...Ch. 29 - Prob. 10PCh. 29 - Prob. 11PCh. 29 - Prob. 12PCh. 29 - Prob. 13PCh. 29 - An accelerating voltage of 2.50103 V is applied to...Ch. 29 - A proton (charge + e, mass mp), a deuteron (charge...Ch. 29 - Prob. 16PCh. 29 - Review. One electron collides elastically with a...Ch. 29 - Review. One electron collides elastically with a...Ch. 29 - Review. An electron moves in a circular path...Ch. 29 - Prob. 20PCh. 29 - Prob. 21PCh. 29 - Prob. 22PCh. 29 - Prob. 23PCh. 29 - A cyclotron designed to accelerate protons has a...Ch. 29 - Prob. 25PCh. 29 - Prob. 26PCh. 29 - A cyclotron (Fig. 28.16) designed to accelerate...Ch. 29 - Prob. 28PCh. 29 - Prob. 29PCh. 29 - Prob. 30PCh. 29 - Prob. 31PCh. 29 - Prob. 32PCh. 29 - Prob. 33PCh. 29 - Prob. 34PCh. 29 - A wire carries a steady current of 2.40 A. A...Ch. 29 - Prob. 36PCh. 29 - Prob. 37PCh. 29 - Prob. 38PCh. 29 - Prob. 39PCh. 29 - Consider the system pictured in Figure P28.26. A...Ch. 29 - Prob. 41PCh. 29 - Prob. 42PCh. 29 - Prob. 43PCh. 29 - Prob. 44PCh. 29 - Prob. 45PCh. 29 - A 50.0-turn circular coil of radius 5.00 cm can be...Ch. 29 - Prob. 47PCh. 29 - Prob. 48PCh. 29 - Prob. 49PCh. 29 - Prob. 50PCh. 29 - Prob. 51PCh. 29 - Prob. 52PCh. 29 - Prob. 53PCh. 29 - A Hall-effect probe operates with a 120-mA...Ch. 29 - Prob. 55PCh. 29 - Prob. 56APCh. 29 - Prob. 57APCh. 29 - Prob. 58APCh. 29 - Prob. 59APCh. 29 - Prob. 60APCh. 29 - Prob. 61APCh. 29 - Prob. 62APCh. 29 - Prob. 63APCh. 29 - Prob. 64APCh. 29 - Prob. 65APCh. 29 - Prob. 66APCh. 29 - A proton having an initial velocity of 20.0iMm/s...Ch. 29 - Prob. 68APCh. 29 - Prob. 69APCh. 29 - Prob. 70APCh. 29 - Prob. 71APCh. 29 - Prob. 72APCh. 29 - Prob. 73APCh. 29 - Prob. 74APCh. 29 - Prob. 75APCh. 29 - Prob. 76APCh. 29 - Prob. 77CPCh. 29 - Prob. 78CPCh. 29 - Review. A wire having a linear mass density of...Ch. 29 - Prob. 80CP
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- A proton moving in the plane of the page has a kinetic energy of 6.00 MeV. A magnetic field of magnitude H = 1.00 T is directed into the page. The proton enters the magnetic field with its velocity vector at an angle = 45.0 to the linear boundary of' the field as shown in Figure P29.80. (a) Find x, the distance from the point of entry to where the proton will leave the field. (b) Determine . the angle between the boundary and the protons velocity vector as it leaves the field.arrow_forwardUnreasonable results Frustrated by the small Hall voltage obtained in blood flow measurements, a medical physicist decides to increase the applied magnetic field strength to get a 0.500-V output for blood moving at 30.0 cm/s in a 1.50-cm-diameter vessel. (a) What magnetic field strength is needed? (b) What is unreasonable about this result? (C) Which premise is responsible?arrow_forwardAn electron in a TV CRT moves with a speed of 6.0107 m/s, in a direction perpendicular to Earth's field, which has a strength of 5.0105 T. (a) What strength electric field must be applied perpendicular to the Earth’s field to make the election moves in a straight line? (b) If this is done between plates separated by 1.00 cm, what is the voltage applied? (Note that TVs are usually surrounded by a ferromagnetic material to shield against external magnetic fields and avoid the need for such a collection,)arrow_forward
- A piece of insulated wire is shaped into a figure eight as shown in Figure P23.12. For simplicity, model the two halves of the figure eight as circles. The radius of the upper circle is 5.00 cm and that of the lower circle is 9.00 cm. The wire has a uniform resistance per unit length of 3.00 Ω/m. A uniform magnetic field is applied perpendicular to the plane of the two circles, in the direction shown. The magnetic field is increasing at a constant rate of 2.00 T/s. Find (a) the magnitude and (b) the direction of the induced current in the wire. Figure P23.12arrow_forwardDetermine the initial direction of the deflection of charged particles as they enter the magnetic fields as shown in Figure P22.2. Figure P22.2.arrow_forwardUsing an electromagnetic flowmeter (Fig. P19.69), a heart surgeon monitors the flow rate of blood through an artery. Electrodes A and B make contact with the outer surface of the blood vessel, which has interior diameter 3.00 mm. (a) For a magnetic field magnitude of 0.040 0 T, a potential difference of 160 V appears between the electrodes. Calculate the speed of the blood. (b) Verify that electrode A is positive, as shown. Does the sign of the emf depend on whether the mobile ions in the blood are predominantly positively or negatively charged? Explain. Figure P19.69arrow_forward
- A particle moving downward at a speed of 6.0106 m/s enters a uniform magnetic field that is horizontal and directed from east to west. (a) If the particle is deflected initially to the north in a circular arc, is its charge positive or negative? (b) If B = 0.25 T and the charge-to-mass ratio (q/m) of the particle is 40107 C/kg. what is ±e radius at the path? (c) What is the speed of the particle after c has moved in the field for 1.0105s ? for 2.0s?arrow_forwardA magnetic field directed into the page changes with time according to B = 0.030 0t2 + 1.40, where B is in teslas and t is in seconds. The field has a circular cross section of radius R = 2.50 cm (see Fig. P23.28). When t = 3.00 s and r2 = 0.020 0 m, what are (a) the magnitude and (b) the direction of the electric field at point P2?arrow_forwardWhy is the following situation impossible? Figure P28.46 shows an experimental technique for altering the direction of travel for a charged particle. A particle of charge q = 1.00 C and mass m = 2.00 1015 kg enters the bottom of the region of uniform magnetic field at speed = 2.00 105 m/s, with a velocity vector perpendicular to the field lines. The magnetic force on the particle causes its direction of travel to change so that it leaves the region of the magnetic field at the top traveling at an angle from its original direction. The magnetic field has magnitude B = 0.400 T and is directed out of the page. The length h of the magnetic field region is 0.110 m. An experimenter performs the technique and measures the angle at which the particles exit the top of the field. She finds that the angles of deviation are exactly as predicted. Figure P28.46arrow_forward
- In Figure P22.43, the current in the long, straight wire is I1 = 5.00 A and the wire lies in the plane of the rectangular loop, which carries a current I2 = 10.0 A. The dimensions in the figure are c = 0.100 m, a = 0.150 m, and = 0.450 m. Find the magnitude and direction of the net force exerted on the loop by the magnetic field created by the wire. Figure P22.43 Problems 43 and 44.arrow_forwardThe Hall effect finds important application in the electronics industry. It is used to find the sign and density of the carriers of electric current in semiconductor chips. The arrangement is shown in Figure P22.66. A semiconducting block of thickness t and width d carries a current I in the x direction. A uniform magnetic field B is applied in the y direction. If the charge carriers are positive, the magnetic force deflects them in the z direction. Positive charge accumulates on the top surface of the sample and negative charge on the bottom surface, creating a downward electric field. In equilibrium, the downward electric force on the charge carriers balances the upward magnetic force and the carriers move through the sample without deflection. The Hall voltage ΔVH = Vc − Va between the top and bottom surfaces is measured, and the density of the charge carriers can be calculated from it. (a) Demonstrate that if the charge carriers are negative the Hall voltage will be negative. Hence, the Hall effect reveals the sign of the charge carriers, so the sample can be classified as p-type (with positive majority charge carriers) or n-type (with negative). (b) Determine the number of charge carriers per unit volume n in terms of I, t, B, ΔVH, and the magnitude q of the carrier charge. Figure P22.66arrow_forwardDetermine the initial direction of the deflection of charged particles as they enter the magnetic fields shown in Figure P29.2.arrow_forward
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