Principles of Physics: A Calculus-Based Text, Hybrid (with Enhanced WebAssign Printed Access Card)
5th Edition
ISBN: 9781305586871
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 28.5, Problem 28.5QQ
To determine
The quantity which is same for both the electron and the proton.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
A quantum particle of mass m is placed in a one-dimensional box of length L. Assume the box is so small that the particle’s motion is relativistic and K = p2/2m is not valid. (a) Derive an expression for the kinetic energy levels of theparticle. (b) Assume the particle is an electron in a box of length L = 1.00 × 10-12 m. Find its lowest possible kinetic energy. (c) By what percent is the nonrelativistic equation in error?
During a certain experiment, the de Broglie wavelength of an electron is 440 nm = 4.4 x 10-7 m, which is the same as the wavelength of violet light. How fast (in m/s) is the electron moving?
m/s
An electron with a mass of 9.11 x 10–31 kg is accelerated to 25% the speed of light (c = 3.00 x 108 m/s). What is the de Broglie wavelength in picometers (pm) for this electron?
Chapter 28 Solutions
Principles of Physics: A Calculus-Based Text, Hybrid (with Enhanced WebAssign Printed Access Card)
Ch. 28.1 - Prob. 28.1QQCh. 28.2 - Prob. 28.2QQCh. 28.2 - Prob. 28.3QQCh. 28.2 - Prob. 28.4QQCh. 28.5 - Prob. 28.5QQCh. 28.5 - Prob. 28.6QQCh. 28.6 - Prob. 28.7QQCh. 28.10 - Prob. 28.8QQCh. 28.10 - Prob. 28.9QQCh. 28.13 - Prob. 28.10QQ
Ch. 28 - Prob. 1OQCh. 28 - Prob. 2OQCh. 28 - Prob. 3OQCh. 28 - Prob. 4OQCh. 28 - Prob. 5OQCh. 28 - Prob. 6OQCh. 28 - Prob. 7OQCh. 28 - Prob. 8OQCh. 28 - Prob. 9OQCh. 28 - Prob. 10OQCh. 28 - Prob. 11OQCh. 28 - Prob. 12OQCh. 28 - Prob. 13OQCh. 28 - Prob. 14OQCh. 28 - Prob. 15OQCh. 28 - Prob. 16OQCh. 28 - Prob. 17OQCh. 28 - Prob. 18OQCh. 28 - Prob. 1CQCh. 28 - Prob. 2CQCh. 28 - Prob. 3CQCh. 28 - Prob. 4CQCh. 28 - Prob. 5CQCh. 28 - Prob. 6CQCh. 28 - Prob. 7CQCh. 28 - Prob. 8CQCh. 28 - Prob. 9CQCh. 28 - Prob. 10CQCh. 28 - Prob. 11CQCh. 28 - Prob. 12CQCh. 28 - Prob. 13CQCh. 28 - Prob. 14CQCh. 28 - Prob. 15CQCh. 28 - Prob. 16CQCh. 28 - Prob. 17CQCh. 28 - Prob. 18CQCh. 28 - Prob. 19CQCh. 28 - Prob. 20CQCh. 28 - Prob. 1PCh. 28 - Prob. 2PCh. 28 - Prob. 3PCh. 28 - Prob. 4PCh. 28 - Prob. 6PCh. 28 - Prob. 7PCh. 28 - Prob. 8PCh. 28 - Prob. 9PCh. 28 - Prob. 10PCh. 28 - Prob. 11PCh. 28 - Prob. 13PCh. 28 - Prob. 14PCh. 28 - Prob. 15PCh. 28 - Prob. 16PCh. 28 - Prob. 17PCh. 28 - Prob. 18PCh. 28 - Prob. 19PCh. 28 - Prob. 20PCh. 28 - Prob. 21PCh. 28 - Prob. 22PCh. 28 - Prob. 23PCh. 28 - Prob. 24PCh. 28 - Prob. 25PCh. 28 - Prob. 26PCh. 28 - Prob. 27PCh. 28 - Prob. 29PCh. 28 - Prob. 30PCh. 28 - Prob. 31PCh. 28 - Prob. 32PCh. 28 - Prob. 33PCh. 28 - Prob. 34PCh. 28 - Prob. 35PCh. 28 - Prob. 36PCh. 28 - Prob. 37PCh. 28 - Prob. 38PCh. 28 - Prob. 39PCh. 28 - Prob. 40PCh. 28 - Prob. 41PCh. 28 - Prob. 42PCh. 28 - Prob. 43PCh. 28 - Prob. 44PCh. 28 - Prob. 45PCh. 28 - Prob. 46PCh. 28 - Prob. 47PCh. 28 - Prob. 48PCh. 28 - Prob. 49PCh. 28 - Prob. 50PCh. 28 - Prob. 51PCh. 28 - Prob. 52PCh. 28 - Prob. 53PCh. 28 - Prob. 54PCh. 28 - Prob. 55PCh. 28 - Prob. 56PCh. 28 - Prob. 57PCh. 28 - Prob. 58PCh. 28 - Prob. 59PCh. 28 - Prob. 60PCh. 28 - Prob. 61PCh. 28 - Prob. 62PCh. 28 - Prob. 63PCh. 28 - Prob. 64PCh. 28 - Prob. 65PCh. 28 - Prob. 66PCh. 28 - Prob. 67PCh. 28 - Prob. 68PCh. 28 - Prob. 69PCh. 28 - Prob. 70PCh. 28 - Prob. 71PCh. 28 - Prob. 72PCh. 28 - Prob. 73PCh. 28 - Prob. 74P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- An electron is moving at 6.0 x 10^6 m/s. A photon of what wavelength would have the same (relativistic) momentum as the electron?arrow_forwardA proton in a linear accelerator has a de Broglie wavelength of 117 pm. What is the speed of the proton? Express your answer with the appropriate units.arrow_forwardA relativistic electron has a de Broglie wavelength of 2.45 pm2.45 pm (1 pm=10−12 m).(1 pm=10−12 m). Determine its velocity, expressed as a fraction of the speed of light ?.arrow_forward
- When developing a night vision night vision equipment, you need to measure the work function for the surface of a metal, so you perform a photoelectric photoelectric effect experiment. You measure the cutoff potential V0 as a function of of the wavelength À of light striking the surface. The results appear in the following table. In your analysis, you use c = 2.998 X 10^8 m/s and e = 1.602 X 10^-19 C, which are values obtained in other experiments. (a) Select a way to represent your results graphicallyso that the data points are close to a straight line. Using this graph, find the slope and the intercept y of the straight line that best fits the data. (b) Use the results from (a) to calculate the Planck constant h (as a test of your data) and the work function ( in and V) of the surface. ( c) What is the longest wavelength of light that will produce photoelectrons from this surface? (d) What wavelength of wavelength of light is required to produce photoelectrons with a kinetic energy…arrow_forwardAn electron has a de Broglie wavelength λ = 4.5×10−10 m .h=6.626×10−34 J⋅s, e=1.602×10−19 C, me=9.109×10−31 kg. What is its momentum?arrow_forwardAn electron is moving at 3.5 x 106 m/s. A photon of what wavelength would have the same momentum?arrow_forward
- It is stated in the text that special relativity must be used to calculate the de Broglie wavelength of electrons in an electron microscope. Let us discover how much of an effect relativity has. Consider an electron accelerated through a potential difference of 1.00 x 105 V.a. Using the Newtonian (nonrelativistic) expressions for kinetic energy and momentum, what is the electron’s de Broglie wavelength?b. The de Broglie wavelength is λ = h/p, but the momentum of a relativistic particle is not mv. Using the relativistic expressions for kinetic energy and momentum, what is the electron’s de Broglie wavelength?arrow_forwardQ. 22 : The de-Broglie wavelength of waves associated with an a-particle of momentum 52.96 x 10- 21 kg m/s is, (a) . 2.250 × 10-14 m (b) 1.251 x 10 11 m (c) 1.251 x 10-14 m (d) 2.250 x 10-11 marrow_forwardAn electron is accelerated from rest through a potential difference of 3.19 x 102 V. Determine the following for the electron. (a) speed (ignore relativistic effects) m/s (b) de Broglie wavelength marrow_forward
- What is the wavelength of (a) a photon with energy 1.00 eV, (b) an electron with energy 1.00 eV, (c) a photon of energy 1.00 GeV, and (d) an electron with energy 1.00 GeV?arrow_forwardQuestion: The electronic structure of atoms and molecules may be investigated using photoelectron spectroscopy. An electron in a photoelectron spectrometer is accelerated from rest by a uniform electric field to a speed of 420 km s−1 in 10 µs. Determine the kinetic energy of the electron?arrow_forward(a) What is the de Broglie wavelength (in m) of a proton moving at a speed of 3.30 × 104 m/s? m (b) What is the de Broglie wavelength (in m) of a proton moving at a speed of 1.92 × 108 m/s? m m (c) What is the de Broglie wavelength for an electron having a kinetic energy of 3.15 MeV?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
College PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
College Physics
Physics
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
College Physics
Physics
ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning