Explanation Since the electrons which moving in circular path follow in the magnetic field, the necessary magnetic force is provided by the centripetal force which can be expressed as, e v B = m e v 2 R (I) Here, e is the charge of the electron, v is the speed of the electron, B is the magnetic field, m e is the mass of the electron, R is the radius. Solve equation (I) to find m e v , m e v = e B R (II) Write the expression for the maximum kinetic energy. K max = 1 2 m e v 2 (III) Use equation (II) in equation (III), K max = e 2 B 2 R 2 2 m e (IV) The maximum kinetic energy of the ejected photo electron is given by, K max = h c λ − ϕ (V) Here, K max is the maximum kinetic energy, h is the Planck’s constant, c is the speed of light, ϕ is the work function. Solve equation (V) for ϕ , K max = h c λ − ϕ ϕ = h c λ − K max (VI) Conclusion: Substitute 1.602 × 10 − 19 C for e , 8.00 × 10 − 4 T for B , 1

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN: 9781133104261

Author: Raymond A. Serway, John W. Jewett

Publisher: Cengage Learning

See similar textbooks

Concept explainers

Particle Theory of Light

The particle theory of light was the proposal made by Newton in 1704 in his treatise Opticks. This is the most basic light theory, in which light is thought to be made up of microscopic particles known as "corpuscles" and that's why this particle theory …

Stopping Potential

In an experiment conducted by Heinrich Hertz, an apparatus was made where the incident light was made to fall on the metallic plate, it was discovered that metals emit electrons. The surface electrons are bound to metals with a minimum amount of energy a…

Quantization of Charges

An electron is a negatively charged subatomic particle either attached to an an atom or sticks to the nucleus of the atom. Electrons exert the negative charge that tries to balance the positive charge of the nucleus.

Question

Chapter 28, Problem 69P

To determine

The work function of the metal.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 28, Problem 68P

Chapter 28, Problem 70P

Students have asked these similar questions

No chatgpt pls will upvote

air is pushed steadily though a forced air pipe at a steady speed of 4.0 m/s. the pipe measures 56 cm by 22 cm. how fast will air move though a narrower portion of the pipe that is also rectangular and measures 32 cm by 22 cm

Chapter 28 Solutions

Principles of Physics: A Calculus-Based Text

Ch. 28.1 - Prob. 28.1QQ Ch. 28.2 - Prob. 28.2QQ Ch. 28.2 - Prob. 28.3QQ Ch. 28.2 - Prob. 28.4QQ Ch. 28.5 - Prob. 28.5QQ Ch. 28.5 - Prob. 28.6QQ Ch. 28.6 - Prob. 28.7QQ Ch. 28.10 - Prob. 28.8QQ Ch. 28.10 - Prob. 28.9QQ Ch. 28.13 - Prob. 28.10QQ

Ch. 28 - Prob. 1OQ Ch. 28 - Prob. 2OQ Ch. 28 - Prob. 3OQ Ch. 28 - Prob. 4OQ Ch. 28 - Prob. 5OQ Ch. 28 - Prob. 6OQ Ch. 28 - Prob. 7OQ Ch. 28 - Prob. 8OQ Ch. 28 - Prob. 9OQ Ch. 28 - Prob. 10OQ Ch. 28 - Prob. 11OQ Ch. 28 - Prob. 12OQ Ch. 28 - Prob. 13OQ Ch. 28 - Prob. 14OQ Ch. 28 - Prob. 15OQ Ch. 28 - Prob. 16OQ Ch. 28 - Prob. 17OQ Ch. 28 - Prob. 18OQ Ch. 28 - Prob. 1CQ Ch. 28 - Prob. 2CQ Ch. 28 - Prob. 3CQ Ch. 28 - Prob. 4CQ Ch. 28 - Prob. 5CQ Ch. 28 - Prob. 6CQ Ch. 28 - Prob. 7CQ Ch. 28 - Prob. 8CQ Ch. 28 - Prob. 9CQ Ch. 28 - Prob. 10CQ Ch. 28 - Prob. 11CQ Ch. 28 - Prob. 12CQ Ch. 28 - Prob. 13CQ Ch. 28 - Prob. 14CQ Ch. 28 - Prob. 15CQ Ch. 28 - Prob. 16CQ Ch. 28 - Prob. 17CQ Ch. 28 - Prob. 18CQ Ch. 28 - Prob. 19CQ Ch. 28 - Prob. 20CQ Ch. 28 - Prob. 1P Ch. 28 - Prob. 2P Ch. 28 - Prob. 3P Ch. 28 - Prob. 4P Ch. 28 - Prob. 6P Ch. 28 - Prob. 7P Ch. 28 - Prob. 8P Ch. 28 - Prob. 9P Ch. 28 - Prob. 10P Ch. 28 - Prob. 11P Ch. 28 - Prob. 13P Ch. 28 - Prob. 14P Ch. 28 - Prob. 15P Ch. 28 - Prob. 16P Ch. 28 - Prob. 17P Ch. 28 - Prob. 18P Ch. 28 - Prob. 19P Ch. 28 - Prob. 20P Ch. 28 - Prob. 21P Ch. 28 - Prob. 22P Ch. 28 - Prob. 23P Ch. 28 - Prob. 24P Ch. 28 - Prob. 25P Ch. 28 - Prob. 26P Ch. 28 - Prob. 27P Ch. 28 - Prob. 29P Ch. 28 - Prob. 30P Ch. 28 - Prob. 31P Ch. 28 - Prob. 32P Ch. 28 - Prob. 33P Ch. 28 - Prob. 34P Ch. 28 - Prob. 35P Ch. 28 - Prob. 36P Ch. 28 - Prob. 37P Ch. 28 - Prob. 38P Ch. 28 - Prob. 39P Ch. 28 - Prob. 40P Ch. 28 - Prob. 41P Ch. 28 - Prob. 42P Ch. 28 - Prob. 43P Ch. 28 - Prob. 44P Ch. 28 - Prob. 45P Ch. 28 - Prob. 46P Ch. 28 - Prob. 47P Ch. 28 - Prob. 48P Ch. 28 - Prob. 49P Ch. 28 - Prob. 50P Ch. 28 - Prob. 51P Ch. 28 - Prob. 52P Ch. 28 - Prob. 53P Ch. 28 - Prob. 54P Ch. 28 - Prob. 55P Ch. 28 - Prob. 56P Ch. 28 - Prob. 57P Ch. 28 - Prob. 58P Ch. 28 - Prob. 59P Ch. 28 - Prob. 60P Ch. 28 - Prob. 61P Ch. 28 - Prob. 62P Ch. 28 - Prob. 63P Ch. 28 - Prob. 64P Ch. 28 - Prob. 65P Ch. 28 - Prob. 66P Ch. 28 - Prob. 67P Ch. 28 - Prob. 68P Ch. 28 - Prob. 69P Ch. 28 - Prob. 70P Ch. 28 - Prob. 71P Ch. 28 - Prob. 72P Ch. 28 - Prob. 73P Ch. 28 - Prob. 74P

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

The work function of the metal.

Solution Summary: The author explains the work function of the metal. The kinetic energy of ejected photo electron is given by k_max=hclamb

Concept explainers

The work function of the metal.

Want to see the full answer?

Chapter 28 Solutions