Explanation The number of photons that enter the eye is, n = E E γ (I) Here, n is the number of photons that enter the eye, E is the energy entering the eye in each second, E γ is the energy of a single photon. Write the expression for the energy of a single photon. E γ = h c λ (II) Here, h is the Planck’s constant, c is the speed of light, λ is the wavelength. Write the expression for the energy entering the eye in each second. E γ = P Δ t (III) Here, P is the power, Δ t is the change in time. Write the expression for the power. P = I A (IV) Here, I is the current, A is the area. Use equation (IV) in equation (III),and substitute ( π d 2 4 ) for A . E = I ( π d 2 4 ) Δ t (V) Conclusion: Substitute 4.00 × 10 − 11 W / m 2 for I , 8.50 mm for d , 1.00 s for Δ t in equation (V) to find E . E = ( 4.00 × 10 − 11 W / m 2 ) ( π 4 ( 8.50 mm × 1 m 10 3 mm ) 2 ) ( 1

Principles of Physics: A Calculus-Based Text

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Author: Raymond A. Serway, John W. Jewett

Publisher: Cengage Learning

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Chapter 28 Solutions

Principles of Physics: A Calculus-Based Text

Ch. 28.1 - Prob. 28.1QQ Ch. 28.2 - Prob. 28.2QQ Ch. 28.2 - Prob. 28.3QQ Ch. 28.2 - Prob. 28.4QQ Ch. 28.5 - Prob. 28.5QQ Ch. 28.5 - Prob. 28.6QQ Ch. 28.6 - Prob. 28.7QQ Ch. 28.10 - Prob. 28.8QQ Ch. 28.10 - Prob. 28.9QQ Ch. 28.13 - Prob. 28.10QQ

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