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Fundamentals of General, Organic, and Biological Chemistry, Books a la Carte Plus Mastering Chemistry with Pearson eText -- Access Card Package (8th Edition)
8th Edition
ISBN: 9780134261256
Author: John McMurray, David S. Ballantine, Carl A. Hoeger, Virginia E. Peterson
Publisher: PEARSON
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Question
Chapter 28, Problem 28.17UKC
Interpretation Introduction
Interpretation:
The step in which the signal gets amplified and the way in which amplification takes place have to be described briefly.
Concept Introduction:
- Hormones: Hormones are chemical messengers which are secreted by the cell in endocrine system and are transported along the blood to stimulate the target cells having the corresponding receptors.
- There are three proteins which are involved in the releasing of a hormone signal. They are receptor, G protein and an enzyme.
- cAMP is a cyclic
nucleotide and it is a second messenger which is synthesized from ATP by the action of the enzyme adenylyl cyclase. Chemically cAMP is a 3’,5’- adenosine monophosphate. - Enzymes are proteins that increase the
rate of reaction by lowering the energy of activation and so they are known as “biological catalysts”. - Secondary messengers are short lived intracellular signaling molecules. Elevated concentration of these types of messengers leads to rapid alteration in the activity of one or more cellular enzymes.
Expert Solution & Answer
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Chapter 28 Solutions
Fundamentals of General, Organic, and Biological Chemistry, Books a la Carte Plus Mastering Chemistry with Pearson eText -- Access Card Package (8th Edition)
Ch. 28.1 - While thinking about how a messenger molecule and...Ch. 28.2 - Prob. 28.2PCh. 28.2 - Prob. 28.3PCh. 28.2 - Prob. 28.4PCh. 28.3 - Prob. 28.5PCh. 28.3 - Prob. 28.6KCPCh. 28.4 - Prob. 28.7PCh. 28.4 - Look at the structure of thyroxine shown earlier...Ch. 28.4 - Prob. 28.1CIAPCh. 28.4 - Prob. 28.2CIAP
Ch. 28.4 - Prob. 28.9PCh. 28.5 - Prob. 25.10PCh. 28.6 - Prob. 28.11PCh. 28.6 - Prob. 28.12PCh. 28.6 - Prob. 28.13KCPCh. 28.7 - Identify the functional groups present in THC. Is...Ch. 28.7 - Prob. 28.15KCPCh. 28 - Prob. 28.16UKCCh. 28 - Prob. 28.17UKCCh. 28 - Prob. 28.18UKCCh. 28 - Prob. 28.19UKCCh. 28 - Prob. 28.20UKCCh. 28 - Prob. 28.21UKCCh. 28 - Prob. 28.22APCh. 28 - Prob. 28.23APCh. 28 - Prob. 28.24APCh. 28 - Prob. 28.25APCh. 28 - Prob. 28.26APCh. 28 - Prob. 28.27APCh. 28 - Prob. 28.28APCh. 28 - Prob. 28.29APCh. 28 - Prob. 28.30APCh. 28 - Prob. 28.31APCh. 28 - Prob. 28.32APCh. 28 - Prob. 28.34APCh. 28 - Prob. 28.35APCh. 28 - Prob. 28.36APCh. 28 - Prob. 28.37APCh. 28 - How does epinephrine reach its target tissues?Ch. 28 - Prob. 28.39APCh. 28 - Prob. 28.40APCh. 28 - Prob. 28.41APCh. 28 - Prob. 28.42APCh. 28 - What enzyme catalyzes hydrolysis of the second...Ch. 28 - Prob. 28.44APCh. 28 - Prob. 28.45APCh. 28 - Prob. 28.46APCh. 28 - Prob. 28.47APCh. 28 - Prob. 28.48APCh. 28 - Prob. 28.49APCh. 28 - Prob. 28.50APCh. 28 - Prob. 28.51APCh. 28 - Prob. 28.52APCh. 28 - Prob. 28.53APCh. 28 - Prob. 28.54APCh. 28 - Prob. 28.55APCh. 28 - Prob. 28.56APCh. 28 - Prob. 28.57APCh. 28 - Prob. 28.58APCh. 28 - Prob. 28.59APCh. 28 - Prob. 28.60APCh. 28 - Prob. 28.62APCh. 28 - Prob. 28.63APCh. 28 - Prob. 28.64APCh. 28 - Prob. 28.65APCh. 28 - Prob. 28.66APCh. 28 - Prob. 28.67APCh. 28 - Prob. 28.68APCh. 28 - Prob. 28.69APCh. 28 - Prob. 28.70APCh. 28 - Prob. 28.71APCh. 28 - Prob. 28.72APCh. 28 - Prob. 28.73APCh. 28 - Prob. 28.74APCh. 28 - Prob. 28.75APCh. 28 - Prob. 28.76APCh. 28 - Why do we have brain receptors that respond to...Ch. 28 - Prob. 28.78APCh. 28 - Prob. 28.79APCh. 28 - Prob. 28.80APCh. 28 - Prob. 28.81APCh. 28 - Prob. 28.82APCh. 28 - Prob. 28.83CPCh. 28 - Prob. 28.84CPCh. 28 - Prob. 28.85CPCh. 28 - Prob. 28.86CPCh. 28 - Prob. 28.87CPCh. 28 - Prob. 28.88CPCh. 28 - Prob. 28.89CPCh. 28 - Prob. 28.90CPCh. 28 - Prob. 28.91CPCh. 28 - Prob. 28.92CPCh. 28 - Prob. 28.93CPCh. 28 - Prob. 28.94GPCh. 28 - Prob. 28.95GP
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- Problem 15 of 15 Submit Using the following reaction data points, construct Lineweaver-Burk plots for an enzyme with and without an inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Using the information from this plot, determine the type of inhibitor present. 1 mM-1 1 s mM -1 [S]' V' with 10 μg per 20 54 10 36 20 5 27 2.5 23 1.25 20 Answer: |||arrow_forward12:33 CO Problem 4 of 15 4G 54% Done On the following Lineweaver-Burk -1 plot, identify the by dragging the Km point to the appropriate value. 1/V 40 35- 30- 25 20 15 10- T Км -15 10 -5 0 5 ||| 10 15 №20 25 25 30 1/[S] Г powered by desmosarrow_forward1:30 5G 47% Problem 10 of 15 Submit Using the following reaction data points, construct a Lineweaver-Burk plot for an enzyme with and without a competitive inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. 1 -1 1 mM [S]' s mM¹ with 10 mg pe 20 V' 54 10 36 > ст 5 27 2.5 23 1.25 20 Answer: |||arrow_forward
- Problem 14 of 15 Submit Using the following reaction data points, construct Lineweaver-Burk plots for an enzyme with and without an inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Using the information from this plot, determine the type of inhibitor present. 1 mM-1 1 s mM -1 [S]' V' with 10 μg per 20 54 10 36 20 5 27 2.5 23 1.25 20 Answer: |||arrow_forward12:36 CO Problem 9 of 15 4G. 53% Submit Using the following reaction data points, construct a Lineweaver-Burk plot by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Based on the plot, determine the value of the catalytic efficiency (specificity constant) given that the enzyme concentration in this experiment is 5.0 μ.Μ. 1 [S] ¨‚ μM-1 1 V sμM-1 100.0 0.100 75.0 0.080 50.0 0.060 15.0 0.030 10.0 0.025 5.0 0.020 Answer: ||| O Гarrow_forwardProblem 11 of 15 Submit Using the following reaction data points, construct a Lineweaver-Burk plot for an enzyme with and without a noncompetitive inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. 1 -1 1 mM [S]' 20 V' s mM¹ with 10 μg per 54 10 36 > ст 5 27 2.5 23 1.25 20 Answer: |||arrow_forward
- Problem 13 of 15 Submit Using the following reaction data points, construct Lineweaver-Burk plots for an enzyme with and without an inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Using the information from this plot, determine the type of inhibitor present. 1 mM-1 1 s mM -1 [S]' V' with 10 μg per 20 54 10 36 20 5 27 2.5 23 1.25 20 Answer: |||arrow_forward12:33 CO Problem 8 of 15 4G. 53% Submit Using the following reaction data points, construct a Lineweaver-Burk plot by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Based on the plot, determine the value of kcat given that the enzyme concentration in this experiment is 5.0 μM. 1 [S] , мм -1 1 V₁ s μM 1 100.0 0.100 75.0 0.080 50.0 0.060 15.0 0.030 10.0 0.025 5.0 0.020 Answer: ||| Гarrow_forward1:33 5G. 46% Problem 12 of 15 Submit Using the following reaction data points, construct a Lineweaver-Burk plot for an enzyme with and without an uncompetitive inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. 1 -1 1 mM [S]' 20 V' s mM¹ with 10 μg per 54 10 36 > ст 5 27 2.5 23 1.25 20 Answer: |||arrow_forward
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