Rank in order, from largest to smallest, the currents
The rank in order of currents from largest to smallest
Answer to Problem 1CQ
Solution:
The rank in order of currents from largest to smallest is
Explanation of Solution
Given Info:
Voltage =
Resistance=
Current =
Voltage =
Resistance=
Current =
Voltage =
Resistance=
Current =
Voltage =
Resistance=
Current =
Formula:
Ohm’s law =>
Applying eqn(1) to all the sets, we get
Calculation:
Substituting the given data in eqn(2)
⇒
Substituting the given data in eqn(3)
⇒
Substituting the given data in eqn(4)
⇒
Substituting the given data in eqn(5)
⇒
On comparing the above values, we get the required relation is
Conclusion:
The rank in order of currents from largest to smallest is
Want to see more full solutions like this?
Chapter 28 Solutions
Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)
Additional Science Textbook Solutions
College Physics: A Strategic Approach (3rd Edition)
Applied Physics (11th Edition)
The Cosmic Perspective (8th Edition)
College Physics
Physics (5th Edition)
Tutorials in Introductory Physics
- Four resistors are connected to a battery as shown in Figure P27.15. (a) Determine the potential difference across each resistor in terms of . (b) Determine the current in each resistor in terms of I. (c) What If? If R3 is increased, explain what happens to the current in each of the resistors. (d) In the limit that R3 , what are the new values of the current in each resistor in terms of I, the original current in the battery? Figure P27.15arrow_forwarda.Estimate the electrical resistance of the blood in a 50cm long, 3mm diameter artery. The resistivity of blood is 1.6 ohm-meter.Express your answer in cΩ, mΩ,μΩ, and nΩ. B. Suppose the energy for two doughnuts in Thermodynamics are totally converted into electric potential energy at point a, wherein a dust particle of 5 × 10-9 kg with 9nC charge is travelling from point a with 600 m/s to point b (where there is no electric potential energy). How fast does the dust particle is moving at point b?arrow_forwardIn the circuit pictured, the resistors have values of R1 = 170 Q, R, = 62 Q, and R3 = 130 Q, and the battery has an emf ɛ = 274 V. R R2 R3 A. How much current ibatt, in amperes, goes through the battery? B. What is the current i2, in amperes, through resistor R2?arrow_forward
- What is the current (in A) passing through resistor 3 in the circuit if V = 12 V, R1 = 18 Q, R2 = 6 Q, and R3 = 3 0? Give your answer as only the numerical value in the SI units specified. e is interpreted as x10^ for use with large or small values; 1.01e2 is interpreted as 1.01 x 102. R1 R2 R3arrow_forwardCan you solve the question below?arrow_forwardA battery is used to charge a capacitor through a resistor as shown. Show that half the energy supplied by the battery appears as internal energy in the resistor and half is stored in the capacitor.arrow_forward
- Three resistors (R₁= 102, R₂ = 42 and R3 = 82) connected to two batteries (of negligible internal resistan ce) as shown. R₁ 1002 www E₁ 20V www R₂ 4Ω What is the current through the resistor R₂? A. 1.63 A B. 0.26 A C. 1.9 A D. 0.58 A E. 0.83 A www E2 12V R3 802arrow_forwardFour resistors are connected to a battery as shown in the R,=2R figure. The current through the battery is I, the battery's electromotive force (emf) is E = 9.65 V, and the resistor values are R = R, R2 = 2R, R3 4R, and R = 3R. !! R, = R Find the voltages across each resistor. R,= 3R V = V V2 = V R, = 4R V3 = V V4 = V. wwarrow_forwardWhat is the time constant of the circuit shown in Figure OQ28.7? Each of the five resistors has resistance R. and each of the five capacitors has capacitance C. The internal resistance of the battery is negligible. (a) RC. (b) 5RC. (c) 10RC (d) 25RC (e) none of those answersarrow_forward
- can u help me? tnxarrow_forwardFour resistors are connected to a battery as shown in the R, = 2R figure. The current through the battery is I, the battery's electromotive force (emf) is E = 10.30 V, and the resistor values are R = R, R2 = 2R, R3 = 4R, and R4 = 3R. R, = R Find the voltages across each resistor. R, = 3R V = V V2 = V R, = 4R V3 = V V4 = V ww wwarrow_forwardV4arrow_forward
- Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningPhysics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning