MICROBIOLOGY: EVOLV.SCI.-W/ACCESS>CI<
MICROBIOLOGY: EVOLV.SCI.-W/ACCESS>CI<
4th Edition
ISBN: 9780393622805
Author: SLONCZEWSKI
Publisher: Norton custom
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Chapter 27.3, Problem 2TQ
Summary Introduction

To review:

The cells containing both rpsL+ and rpsLR genes are resistant to streptomycin or are sensitive.

Introduction:

The growth of bacteria is inhibited by antibiotics that target protein biosynthesis. Streptomycin interacts with the small subunit of the ribosome. The ribosomal protein S12 is an essential protein that causes it to be resistant to the error-promoting antibiotic streptomycin. The rpsL genes in most of the bacteria prohibit the isolation of streptomycin-resistant mutants.

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Anwser these Discussion Questions: Part One Why were the plants kept in the dark prior to the experiment? Why is this important? Why is it important to boil the leaf? Explain why it was necessary to use boiling alcohol? What is the purpose of the iodine? Part Two What was the purpose of keeping the leaf in the dark and then covering it with a cardboard cut-out? What conclusions can you draw from this part of the lab? Part Three 7. In this experiment what was the purpose of adding the soda lime? 8. Why was a sealed bag placed around each plant? 9. What happened in the control plants? 10. What was the result on photosynthesis? Part Four 11. Why was a variegated leaf used in this experiment? !2. What conclusions can you draw about starch production in a variegated leaf?
How did the color differences between the two bacterial species you used in this experiment help you determine if the streak plate method you performed was successful?
series of two-point crosses were carried out among six loci (a, b, c, d, e and f), producing the following recombination frequencies. According to the data below, the genes can be placed into how many different linkage groups? Loci a and b Percent Recombination 50 a and c 14 a and d 10 a and e 50 a and f 50 b and c 50 b and d 50 b and e 35 b and f 20 c and d 5 c and e 50 c and f 50 d and e 50 d and f 50 18 e and f Selected Answer: n6 Draw genetic maps for the linkage groups for the data in question #5. Please use the format given below to indicate the genetic distances. Z e.g. Linkage group 1=P____5 mu__Q____12 mu R 38 mu 5 Linkage group 2-X_____3 mu__Y_4 mu sanight
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