DeGarmo's Materials and Processes in Manufacturing
12th Edition
ISBN: 9781118987674
Author: J. T. Black, Ronald A. Kohser
Publisher: WILEY
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Chapter 27, Problem 29RQ
To determine
The relation between the feed per stroke in shaping and feed per tooth in milling.
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A job has to be machined in shaping and the process parameters are given below:
Length of the job=120 mm
Speed of the motor=640 rpm
Cutting speed=248 m/min
Tool allowance before cutting =31.5 mm
Tool allowance after cutting=10 mm
Determine the cutting to return stroke ratio for the above operation and draw the arrangement of machining with tool head and allowances.
In orthogonal turning of a cylindrical tube of wall thickness 5 mm, the axial and the tangential
cutting forces were measured as 1259 N and 1601 N, respectively. The measured chip thickness
after machining was found to be 0.3 mm. The rake angle was 10° and the axial feed was 100
mm/min. the rotational speed of the spindle was 1000 rpm. Assuming the material to be
perfectly and Merchant's first solution, the shear strength of the material is closest to
The end of a large tubular workpart is to be faced on a NC vertical boring mill.
The part has an outside diameter of 38.0 in and an inside diameter of 24.0
in. If the facing operation is performed at a rotational speed of 40.0 rev/min,
feed of 0.015 in/rev, and depth of cut of 0.180 in, determine (a) the cutting
time to complete the facing operation and the cutting speeds and metal
removal rates at the beginning and end of the cut.
Chapter 27 Solutions
DeGarmo's Materials and Processes in Manufacturing
Ch. 27 - Why is sawing one of the most efficient of the...Ch. 27 - Explain why tooth spacing (pitch) is important in...Ch. 27 - What is the tooth gullet used for on a saw blade?Ch. 27 - Explain what is meant by the set of the teeth on a...Ch. 27 - How is tooth set related to saw kerf?Ch. 27 - Why can a bandsaw blade not be hardened throughout...Ch. 27 - What are the advantages of using circular saws?Ch. 27 - Why have bandsawing machines largely replaced...Ch. 27 - Explain how the hole in Figure 27.7 is made on a...Ch. 27 - How would you calculate or estimate Tm for a...
Ch. 27 - What is the disadvantage of using gravity to feed...Ch. 27 - What is unique about the broaching process...Ch. 27 - Can a thick saw blade be used as a broach? Why or...Ch. 27 - Broaching machines are simpler in a basic design...Ch. 27 - Why is broaching particularly well-suited for mass...Ch. 27 - In designing a broach, what would be the first...Ch. 27 - Why is it necessary to relate the design of a...Ch. 27 - What two methods can be utilized to reduce the...Ch. 27 - For a given job, how would a broach having...Ch. 27 - Why are the pitch and radius of the gullet between...Ch. 27 - Why are broaching speeds usually relatively low,...Ch. 27 - What are the advantages of shell-type broach...Ch. 27 - Why are most broaches made from alloy or...Ch. 27 - What are the advantages of TiN-coated broaching...Ch. 27 - For mass-production operations, which process is...Ch. 27 - What is the difference between the roughing teeth...Ch. 27 - The sides of a square, blind hole must be machined...Ch. 27 - The interior, flat surfaces of socket wrenches,...Ch. 27 - Prob. 29RQCh. 27 - What are some ways to improve the efficiency of a...Ch. 27 - To what extent is filing different from sawing?Ch. 27 - Prob. 32RQCh. 27 - Prob. 33RQCh. 27 - Prob. 34RQCh. 27 - A surface 12 in. long is to be machined with a...Ch. 27 - The pitch of the teeth on a simple surface broach...Ch. 27 - Estimate the (approximate maximum) horsepower...Ch. 27 - Estimate the approximate force acting in the...Ch. 27 - In cutting a 6-in.-long slot in a piece of AISI...Ch. 27 - The strength of a pull broach is determined by its...Ch. 27 - Suppose you want to shape a block of metal 7 in....Ch. 27 - Could you have saved any time in Problem 7 by...Ch. 27 - Derive the equation for shaping cutting speed.Ch. 27 - How many strokes per minute would be required to...Ch. 27 - How much time would be required to shape a flat...Ch. 27 - What is the metal removal rate in Problem 11 if...Ch. 27 - Suppose you decide to mill the flat surface...Ch. 27 - A planer has a 10-hp motor, and 75% of the motor...
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- A workpiece of 2000 mm length and 300 mm width was machined by a planning operation with the feed set at 0.3 mm/stroke. If the machine tool executes 10 double strokes/min, What is the planning time for a single pass?arrow_forwardPlate 200 mm x 90 mm is to be maintained on a shaper under following condition, v= 13.5 m/ min Feed is 0.57 mm/ double stroke, Approach and overtravel 20 mm each in longitudinal direction and 4 mm each in lateral direction. The ratio of cutting to the return speed is 0.83.Calculate the machining time in minutes?arrow_forwardLow carbon steel having a tensile strength = 300 MPa and a shear strength = 220 MPa is turned at a cutting speed = 2.5 m/s, feed = 0.20 mm/rev and depth of cut = 3.0 mm. The rake angle = 5° in the direction of chip flow. The resulting chip ratio = 0.45. Using the orthogonal model to approximate turning, determine the cutting force and feed force.arrow_forward
- Describe the principles from power input of the shaping machine to the output of the toolarrow_forwardIn a production turning operation, the workpart is 60 mm in diameter and 500 mm long. A feed of 0.75 mm/rev is used in the operation. If cutting speed-9 m/s, the tool must be changed every 4 workparts; But if cutting speed=5 m/s, the tool can be used to produce 50 pieces between tool changes. Determine the Taylor tool life equation for this job. (use the equations given below for solution) L Tm- 1,= Nf N AD, vT" = C %3| AD,L Tm fvarrow_forwardIn a production turning operation, the workpart is 60 mm in diameter and 500 mm long. A feed of 0.75 mm/rev is used in the operation. If cutting speed=9 m/s, the tool must be changed every 4 workparts; But if cutting speed=5 m/s, the tool can be used to produce 50 pieces between tool changes. Determine the Taylor tool life equation for this job. (use the equations given below for solution)arrow_forward
- In a production turning operation, the workpart is 60 mm in diameter and 500 mm long. A feed of 0.75 mm/rev is used in the operation. If cutting speed=9 m/s, the tool must be changed every 4 workparts; But if cutting speed=5 m/s, the tool can be used to produce 50 pieces between tool changes. Determine the Taylor tool life equation for this job. (use the equations given below for solution)arrow_forwardi need the answer quicklyarrow_forwardWhats the answer for this please ?arrow_forward
- Q.1 A turning operation uses a rotation speed = 150 rpm, feed = 0.38 mm/rev, and depth of cut = 5.00 mm. The diameter of the workpiece before cut is 50mm and it is length was 350mm. .Calculate the material removal ratearrow_forwardIn the lathe machine, the diameter of workpart 35mm is turned at 100 rpm, depth of cut 0.125 mm, length of continuous chip for one revolution of workpart = 60mm, length undeformed chip= 100.53mm, rake angle = 35°, coefficient of friction= 1.5 and resultant cutting force=215.5 N. Calculate: 1- Horizontal cutting force of the tool on the workpart and vertical cutting force required to hold the tool against the work. 2- The forces components applied against the chip by the tool. 3- Velocity of chip relative to the tool and workpart. 4- The percentage of total energy dissipated due to friction along the shear plane, and the friction at the tool-chip interface.arrow_forwardI need the answer as soon as possiblearrow_forward
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