Chapter 26, Problem 75PQ

A long thin wire is used in laser printers to charge the photoreceptor before exposure to light. This is done by applying a large potential difference between the wire and the photoreceptor.

1. a. Use Equation 26.23,

   $V\left(r\right)=\frac{\lambda }{2\pi {\epsilon }_0}\ln \frac{R}{r}$

   to determine a relationship between the electric potential V and the magnitude of the electric field E at a distance r from the center of the wire of radius R (r > R).

2. b. Determine the electric potential at a distance of 2.0 mm from the surface of a wire of radius R = 0.80 mm that will produce an electric field of 1.8 × 10⁶ V/m at that point.