
Concept explainers
(a)
Interpretation:
The structure of (R)-1-bromo-1-chloroethane should be drawn.
Concept introduction:
Enantiomers are optical isomers, which can rotate the plane polarized light clockwise or anticlockwise. These molecules must have at least one chiral C atom, i.e., the carbon atom bonded with four different groups. They are assigned by R and S configuration.
The R/S naming follows the Cahn-Ingold-Prelog Rules for naming the enantiomer as R or S-enantiomer. According to Cahn-Ingold-Prelog rules, assign the numbers from 1 to 4 to the groups bonded with chiral C atom on the basis of their molar mass. The essential condition is that the 4th group or atom must be below the plane. If the movement from 1(2(3 group is clockwise, then it will be R-configuration, and if it is anticlockwise, then it will be S-configuration.
If the 4th number group is in plane, then follow the following steps:
- Swap the 4th group with the group with the group present below the plane.
- Assign R/S configuration with clockwise or anticlockwise movement.
- Flip the configuration to get the real configuration.
If the 4th number group is in above the plane shown by wedge line, then follow the following steps:
- Swap the 4 group with the group with the group present below the plane.
- Assign R/S configuration with clockwise or anticlockwise movement.
(b)
Interpretation:
The structure of (E)-2-bromopent-2-eneshould be drawn.
Concept introduction:
The E-configuration stands for anti-configuration, whereas, Z-configuration stands for same side configuration.
The determination of configuration is done on the basis of the
(c)
Interpretation:
The structure of (Z)-1-chloro-3-ethylhept-3-ene should be drawn.
Concept introduction:
Alkenes are unsaturated hydrocarbons with double covalent bond between carbon-carbon atoms. On the basis of groups bonded with the double bonded carbon atoms, alkenes can be classified as E and Z-configuration.
The E-configuration stands for anti-configuration, whereas, Z-configuration stands for same side configuration.
The determination of configuration is done on the basis of the atomic/molecular mass of the atoms/groups attached to double bonded carbon atoms. If both higher atomic/molecular mass atom/groups are placed at the same side, then it is said to be Z-configuration and in E-configuration, these groups will be at anti-position.
(d)
Interpretation:
The structure of (R)-2-hydroxypropanoic acidshould be drawn.
Concept introduction:
Enantiomers are optical isomers, which can rotate the plane polarized light clockwise or anticlockwise. These molecules must have at least one chiral C atom, i.e., the carbon atom bonded with four different groups. They are assigned by R and S configuration.
The R/S naming follows the Cahn-Ingold-Prelog Rules for naming the enantiomer as R or S-enantiomer. According to Cahn-Ingold-Prelog rules, assign the numbers from 1 to 4 to the groups bonded with chiral C atom on the basis of their molar mass. The essential condition is that the 4th group or atom must be below the plane. If the movement from 1(2(3 group is clockwise, then it will be R-configuration, and if it is anticlockwise, then it will be S-configuration.
If the 4th number group is in plane, then follow the following steps:
- Swap the 4th group with the group with the group present below the plane.
- Assign R/S configuration with clockwise or anticlockwise movement.
- Flip the configuration to get the real configuration.
If the 4th number group is in above the plane shown by wedge line, then follow the following steps:
- Swap the 4 group with the group with the group present below the plane.
- Assign R/S configuration with clockwise or anticlockwise movement.
(e)
Interpretation:
The structure of (S)-2-aminopropanoate anionshould be drawn.
Concept introduction:
Enantiomers are optical isomers, which can rotate the plane polarized light clockwise or anticlockwise. These molecules must have at least one chiral C atom, i.e., the carbon atom bonded with four different groups. They are assigned by R and S configuration.
The R/S naming follows the Cahn-Ingold-Prelog Rules for naming the enantiomer as R or S-enantiomer. According to Cahn-Ingold-Prelog rules, assign the numbers from 1 to 4 to the groups bonded with chiral C atom on the basis of their molar mass. The essential condition is that the 4th group or atom must be below the plane. If the movement from 1(2(3 group is clockwise, then it will be R-configuration, and if it is anticlockwise, then it will be S-configuration.
If the 4th number group is in plane, then follow the following steps:
- Swap the 4th group with the group with the group present below the plane.
- Assign R/S configuration with clockwise or anticlockwise movement.
- Flip the configuration to get the real configuration.
If the 4th number group is in above the plane shown by wedge line, then follow the following steps:
- Swap the 4 group with the group with the group present below the plane.
- Assign R/S configuration with clockwise or anticlockwise movement.

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Chapter 26 Solutions
EBK GENERAL CHEMISTRY
- 111 Carbonyl Chem Choosing reagants for a Wittig reaction What would be the best choices for the missing reagents 1 and 3 in this synthesis? 1. PPh3 3 1 2 2. n-BuLi • Draw the missing reagents in the drawing area below. You can draw them in any arrangement you like. Do not draw the missing reagent 2. If you draw 1 correctly, we'll know what it is. • Note: if one of your reagents needs to contain a halogen, use bromine. Explanation Check Click and drag to start drawing a structure. × ©2025 McGraw Hill LLC. All Rights Reserved. Terms of Usearrow_forwardA student proposes the transformation below in one step of an organic synthesis. There may be one or more reactants missing from the left-hand side, but there are no products missing from the right-hand side. There may also be catalysts, small inorganic reagents, and other important reaction conditions missing from the arrow. • Is the student's transformation possible? If not, check the box under the drawing area. . If the student's transformation is possible, then complete the reaction by adding any missing reactants to the left-hand side, and adding required catalysts, inorganic reagents, or other important reaction conditions above and below the arrow. • You do not need to balance the reaction, but be sure every important organic reactant or product is shown. + T X O O лет-ле HO OH HO OH This transformation can't be done in one step.arrow_forwardDetermine the structures of the missing organic molecules in the following reaction: X+H₂O H* H+ Y OH OH Note: Molecules that share the same letter have the exact same structure. In the drawing area below, draw the skeletal ("line") structures of the missing organic molecules X and Y. You may draw the structures in any arrangement that you like, so long as they aren't touching. Click and drag to start drawing a structure. X Sarrow_forward
- Predict the major products of this organic reaction. If there aren't any products, because nothing will happen, check the box under the drawing area instead. No reaction. HO. O :☐ + G Na O.H Click and drag to start drawing a structure. XS xs H₂Oarrow_forwardWhat are the angles a and b in the actual molecule of which this is a Lewis structure? H H C H- a -H b H Note for advanced students: give the ideal angles, and don't worry about small differences from the ideal groups may have slightly different sizes. a = b = 0 °arrow_forwardWhat are the angles a and b in the actual molecule of which this is a Lewis structure? :0: HCOH a Note for advanced students: give the ideal angles, and don't worry about small differences from the ideal that might be caused by the fact that different electron groups may have slightly different sizes. a = 0 b=0° Sarrow_forward
- Determine the structures of the missing organic molecules in the following reaction: + H₂O +H OH O OH +H OH X Note: Molecules that share the same letter have the exact same structure. In the drawing area below, draw the skeletal ("line") structure of the missing organic molecule X. Click and drag to start drawing a structure.arrow_forwardIdentify the missing organic reactant in the following reaction: x + x O OH H* + ☑- X H+ O O Х Note: This chemical equation only focuses on the important organic molecules in the reaction. Additional inorganic or small-molecule reactants or products (like H₂O) are not shown. In the drawing area below, draw the skeletal ("line") structure of the missing organic reactant X. Click and drag to start drawing a structure. Carrow_forwardCH3O OH OH O hemiacetal O acetal O neither O 0 O hemiacetal acetal neither OH hemiacetal O acetal O neither CH2 O-CH2-CH3 CH3-C-OH O hemiacetal O acetal CH3-CH2-CH2-0-c-O-CH2-CH2-CH3 O neither HO-CH2 ? 000 Ar Barrow_forward
- What would be the best choices for the missing reagents 1 and 3 in this synthesis? 1. PPh3 2 2. n-BuLi 3 Draw the missing reagents in the drawing area below. You can draw them in any arrangement you like. • Do not draw the missing reagent 2. If you draw 1 correctly, we'll know what it is. • Note: if one of your reagents needs to contain a halogen, use bromine. Explanation Check Click and drag to start drawing a structure.arrow_forwardPredict the products of this organic reaction: NaBH3CN + NH2 ? H+ Click and drag to start drawing a structure. ×arrow_forwardPredict the organic products that form in the reaction below: + OH +H H+ ➤ ☑ X - Y Note: You may assume you have an excess of either reactant if the reaction requires more than one of those molecules to form the products. In the drawing area below, draw the skeletal ("line") structures of the missing organic products X and Y. You may draw the structures in any arrangement that you like, so long as they aren't touching. Click and drag to start drawing a structure. Garrow_forward
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