(a)
Interpretation:
Polycarbophil is a dietary fiber supplement. It is the calcium salt of a
Concept introduction:
Polycarbophil is synthesized from copolymerization of acrylic acid and divinyl glycol. A molecule of divinylglycol is incorporated in a poly(acrylic acid) structure which leads to forming the radical and due to which, the second growth of the poly(acrylic acid) takes place which results in the formation of the
(b)
Interpretation:
Polycarbophil is a dietary fiber supplement. It is thecalcium salt of a copolymer of acrylic acid and divinylglycol, a cross-linking agent. In the stomach, the calcium ions exchange for protons and, in the higher pH of the intestine, the polymer absorbs
Concept introduction:
Polycarbophil is synthesized from copolymerization of acrylic acid and divinyl glycol. A molecule of divinylglycol is incorporated in a poly(acrylic acid) structure which leads to forming the radical, and due to which, the second growth of the poly(acrylic acid) takes place which results in the formation of the cross-linked polymer. The cross-linked polymer is water-insoluble.
(c)
Interpretation:
It is to be explained why polycarbophil effective at providing bulk in the intestine and what will occur on a molecular level to polycarbophil.
Concept introduction:
Polycarbophil is synthesized from copolymerization of acrylic acid and divinyl glycol. A molecule of divinylglycol is incorporated in a poly(acrylic acid) structure which leads to forming the radical, and due to which, the second growth of the poly(acrylic acid) takes place which results in the formation of the cross-linked polymer. The cross-linked polymer is water-insoluble. In
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Chapter 26 Solutions
EBK ORGANIC CHEMISTRY: PRINCIPLES AND M
- Q2: Draw the molecules based on the provided nomenclatures below: (2R,3S)-2-chloro-3-methylpentane: (2S, 2R)-2-hydroxyl-3,6-dimethylheptane:arrow_forwardQ3: Describes the relationship (identical, constitutional isomers, enantiomers or diastereomers) of each pair of compounds below. ག H CH3 OH OH CH3 H3C OH OH OH ////////// C CH3 CH3 CH3 CH3 H3C CH 3 C/III..... Physics & Astronomy www.physics.northweste COOH H нош..... H 2 OH HO CH3 HOOC H CH3 CH3 CH3 Br. H H Br and H H H Harrow_forwardQ1: For each molecule, assign each stereocenter as R or S. Circle the meso compounds. Label each compound as chiral or achiral. OH HO CI Br H CI CI Br CI CI Xf x f g Br D OH Br Br H₂N R. IN Ill I -N S OMe D II H CO₂H 1/111 DuckDuckGarrow_forward
- These are synthesis questions. You need to show how the starting material can be converted into the product(s) shown. You may use any reactions we have learned. Show all the reagents you need. Show each molecule synthesized along the way and be sure to pay attention to the regiochemistry and stereochemistry preferences for each reaction. If a racemic molecule is made along the way, you need to draw both enantiomers and label the mixture as "racemic". All of the carbon atoms of the products must come from the starting material! ? H Harrow_forwardQ5: Draw every stereoisomer for 1-bromo-2-chloro-1,2-difluorocyclopentane. Clearly show stereochemistry by drawing the wedge-and-dashed bonds. Describe the relationship between each pair of the stereoisomers you have drawn.arrow_forwardClassify each pair of molecules according to whether or not they can participate in hydrogen bonding with one another. Participate in hydrogen bonding CH3COCH3 and CH3COCH2CH3 H2O and (CH3CH2)2CO CH3COCH3 and CH₂ CHO Answer Bank Do not participate in hydrogen bonding CH3CH2OH and HCHO CH3COCH2CH3 and CH3OHarrow_forward
- Nonearrow_forwardGiven the standard enthalpies of formation for the following substances, determine the reaction enthalpy for the following reaction. 4A (g) + 2B (g) → 2C (g) + 7D (g) AHrxn =?kJ Substance AH in kJ/mol A (g) - 20.42 B (g) + 32.18 C (g) - 72.51 D (g) - 17.87arrow_forwardDetermine ASran for Zn(s) + 2HCl(aq) = ZnCl2(aq) + H2(aq) given the following information: Standard Entropy Values of Various Substance Substance So (J/mol • K) 60.9 Zn(s) HCl(aq) 56.5 130.58 H2(g) Zn2+(aq) -106.5 55.10 CI (aq)arrow_forward
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