Concept explainers
(a)
Interpretation: To identify the heme degradation product (1) bilirubin, (2) biliverdin, (3) stercobilin, and (4) urobilin formed at the same time
Concept introduction: Hemoglobin is a heme protein present in the red blood cells. The protein part is called globin and the non-protein part is heme. Heme is the prosthetic group that contains 4 pyrrole groups bonded together and has an iron atom in the center. The structure of the heme group is:
The first step of degradation of heme involves opening of pyrrole ring with the release of the iron atom and production of biliverdin. The iron atom released becomes part of ferritin protein. Biliverdin produced is converted bilirubin in the spleen. Bilirubin is then transported to the liver where attachment of sugar residues to the propionate side chains of the bilirubin occurs to make it more soluble. Then more solubilized bilirubin is excreted in bile and finally to the small intestine. In the small intestine, it is converted into stercobilin for excretion in feces or urobilin for excretion in urine.
(b)
Interpretation: To identify the heme degradation product (1) bilirubin, (2) biliverdin, (3) stercobilin, and (4) urobilin associated with the condition called jaundice.
Concept introduction: Hemoglobin is a heme protein present in the red blood cells. The protein part is called globin and the non-protein part is heme. Heme is the prosthetic group that contains 4 pyrrole groups bonded together and has an iron atom in the center.
The structure of the heme group is:
The first step of degradation of heme involves opening of pyrrole ring with the release of the iron atom and production of biliverdin. The iron atom released becomes part of ferritin protein. Biliverdin produced is converted bilirubin in the spleen. Bilirubin is then transported to the liver where attachment of sugar residues to the propionate side chains of the bilirubin occurs to make it more soluble. Then more solubilized bilirubin is excreted in bile and finally to the small intestine. In the small intestine, it is converted into stercobilin for excretion in feces or urobilin for excretion in urine.
(c)
Interpretation: To identify the heme degradation product (1) bilirubin, (2) biliverdin, (3) stercobilin, and (4) urobilin for which molecular oxygen is used as a reactant.
Concept introduction: Hemoglobin is a heme protein present in the red blood cells. The protein part is called globin and the non-protein part is heme. Heme is the prosthetic group that contains 4 pyrrole groups bonded together and has an iron atom in the center.
The structure of the heme group is:
The first step of degradation of heme involves opening of pyrrole ring with the release of the iron atom and production of biliverdin. The iron atom released becomes part of ferritin protein. Biliverdin produced is converted bilirubin in the spleen. Bilirubin is then transported to the liver where attachment of sugar residues to the propionate side chains of the bilirubin occurs to make it more soluble. Then more solubilized bilirubin is excreted in bile and finally to the small intestine. In the small intestine, it is converted into stercobilin for excretion in feces or urobilin for excretion in urine.
(d)
Interpretation: To identify the heme degradation product (1) bilirubin, (2) biliverdin, (3) stercobilin, and (4) urobilin which is bile pigment and has a brownish color.
Concept introduction: Hemoglobin is a heme protein present in the red blood cells. The protein part is called globin and the non-protein part is heme. Heme is the prosthetic group that contains 4 pyrrole groups bonded together and has an iron atom in the center.
The structure of the heme group is:
The first step of degradation of heme involves opening of pyrrole ring with the release of the iron atom and production of biliverdin. The iron atom released becomes part of ferritin protein. Biliverdin produced is converted bilirubin in the spleen. Bilirubin is then transported to the liver where attachment of sugar residues to the propionate side chains of the bilirubin occurs to make it more soluble. Then more solubilized bilirubin is excreted in bile and finally to the small intestine. In the small intestine, it is converted into stercobilin for excretion in feces or urobilin for excretion in urine.
Bile pigments are the colored degradation product of tetrapyrrole carbon arrangement of heme portion of hemoglobin. These are excreted in bile and give characteristic color to urine and feces.
Want to see the full answer?
Check out a sample textbook solutionChapter 26 Solutions
Study Guide with Selected Solutions for Stoker's General, Organic, and Biological Chemistry, 7th
- Show work with explanation needed. Don't give Ai generated solutionarrow_forward7. Calculate the following for a 1.50 M Ca(OH)2 solution. a. The concentration of hydroxide, [OH-] b. The concentration of hydronium, [H3O+] c. The pOH d. The pHarrow_forwardA first order reaction is 46.0% complete at the end of 59.0 minutes. What is the value of k? What is the half-life for this reaction? HOW DO WE GET THERE? The integrated rate law will be used to determine the value of k. In [A] [A]。 = = -kt What is the value of [A] [A]。 when the reaction is 46.0% complete?arrow_forward
- 3. Provide the missing compounds or reagents. 1. H,NNH КОН 4 EN MN. 1. HBUCK = 8 хно Panely prowseful kanti-chuprccant fad, winddively, can lead to the crading of deduc din-willed, tica, The that chemooices in redimi Грин. " like (for alongan Ridovi MN نيا . 2. Cl -BuO 1. NUH 2.A A -BuOK THE CF,00,H Ex 5)arrow_forward2. Write a complete mechanism for the reaction shown below. NaOCH LOCH₁ O₂N NO2 CH₂OH, 20 °C O₂N NO2arrow_forward4. Propose a synthesis of the target molecules from the respective starting materials. a) b) LUCH C Br OHarrow_forward
- The following mechanism for the gas phase reaction of H2 and ICI that is consistent with the observed rate law is: step 1 step 2 slow: H2(g) +ICI(g) → HCl(g) + HI(g) fast: ICI(g) + HI(g) → HCl(g) + |2(g) (1) What is the equation for the overall reaction? Use the smallest integer coefficients possible. If a box is not needed, leave it blank. + → + (2) Which species acts as a catalyst? Enter formula. If none, leave box blank: (3) Which species acts as a reaction intermediate? Enter formula. If none, leave box blank: (4) Complete the rate law for the overall reaction that is consistent with this mechanism. (Use the form k[A][B]"..., where '1' is understood (so don't write it) for m, n etc.) Rate =arrow_forwardPlease correct answer and don't use hand rating and don't use Ai solutionarrow_forward1. For each of the following statements, indicate whether they are true of false. ⚫ the terms primary, secondary and tertiary have different meanings when applied to amines than they do when applied to alcohols. • a tertiary amine is one that is bonded to a tertiary carbon atom (one with three C atoms bonded to it). • simple five-membered heteroaromatic compounds (e.g. pyrrole) are typically more electron rich than benzene. ⚫ simple six-membered heteroaromatic compounds (e.g. pyridine) are typically more electron rich than benzene. • pyrrole is very weakly basic because protonation anywhere on the ring disrupts the aromaticity. • thiophene is more reactive than benzene toward electrophilic aromatic substitution. • pyridine is more reactive than nitrobenzene toward electrophilic aromatic substitution. • the lone pair on the nitrogen atom of pyridine is part of the pi system.arrow_forward
- The following reactions are NOT ordered in the way in which they occur. Reaction 1 PhO-OPh Reaction 2 Ph-O -CH₂ heat 2 *OPh Pho -CH2 Reaction 3 Ph-O ⚫OPh + -CH₂ Reaction 4 Pho Pho + H₂C OPh + CHOPh H₂C -CH₂ Reactions 1 and 3 Reaction 2 O Reaction 3 ○ Reactions 3 and 4 ○ Reactions 1 and 2 Reaction 4 ○ Reaction 1arrow_forwardSelect all possible products from the following reaction: NaOH H₂O a) b) ОН HO O HO HO e) ОН f) O HO g) h) + OHarrow_forward3. Draw diagrams to represent the conjugation in these molecules. Draw two types of diagram: a. Show curly arrows linking at least two different ways of representing the molecule b. Indicate with dotted lines and partial charges (where necessary) the partial double bond (and charge) distribution H₂N* H₂N -NH2arrow_forward
- Introduction to General, Organic and BiochemistryChemistryISBN:9781285869759Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar TorresPublisher:Cengage LearningChemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage LearningGeneral, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage Learning
- Organic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,Chemistry In FocusChemistryISBN:9781305084476Author:Tro, Nivaldo J., Neu, Don.Publisher:Cengage Learning