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Concept explainers
Interpretation:
The names of the given structures areto be determined.
Concept introduction:
The longest chain is termed as the parent chain, which is then numbered from the end that the substituted carbons get a lower number. The name and number of substituents are then prefixed to the name of the parent chain.
In chemical nomenclature, the
The parent chain is the longest continuous chain of carbon atoms.
The parent chain is numbered from the end that is closest to the substituent.
If the same substituent occurs more than once, the location of each point on which the substituent occurs is given.
If there are two or more different substituents they are listed in alphabetical order using the base name
The name of the
For naming, the parent chain, which is the most substituted longest possible carbon chain in the given structure, has to be chosen.
This chain is then numbered from one end in such a way that the
Thereafter, the name is written including the name and number of substituents. The substituents are written with their number in alphabetical order followed by the name of parent chain and then the functional group as a suffix.
The suffix –olis used for the alcohol group.
The suffix –al is used for the
The suffix –one is used for the
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Chapter 25 Solutions
Chemistry
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- Identify the molecule as having a(n) E, Z, cis, or trans configuration. CH3 H₁₂C ○ E ○ z ○ cis transarrow_forwardIdentify the molecule as having a(n) E, Z, cis, or trans configuration. H₂C- CH3 О Е ○ cis ○ transarrow_forwardThe decomposition of dinitrogen pentoxide according to the equation: 50°C 2 N2O5(g) 4 NO2(g) + O2(g) follows first-order kinetics with a rate constant of 0.0065 s-1. If the initial concentration of N2O5 is 0.275 M, determine: the final concentration of N2O5 after 180 seconds. ...arrow_forward
- Don't used hand raitingarrow_forwardCS2(g) →CS(g) + S(g) The rate law is Rate = k[CS2] where k = 1.6 × 10−6 s−¹. S What is the concentration of CS2 after 5 hours if the initial concentration is 0.25 M?arrow_forwardCS2(g) → CS(g) + S(g) The rate law is Rate = k [CS2] where k = 1.6 × 10-6 s−1. S Calculate the half-life.arrow_forward
- The following is a first order reaction where the rate constant, k, is 6.29 x 10-3 min-*** What is the half-life? C2H4 C2H2 + H2arrow_forwardControl Chart Drawing Assignment The table below provides the number of alignment errors observed during the final inspection of a certain model of airplane. Calculate the central, upper, and lower control limits for the c-chart and draw the chart precisely on the graph sheet provided (based on 3-sigma limits). Your chart should include a line for each of the control limits (UCL, CL, and LCL) and the points for each observation. Number the x-axis 1 through 25 and evenly space the numbering for the y-axis. Connect the points by drawing a line as well. Label each line drawn. Airplane Number Number of alignment errors 201 7 202 6 203 6 204 7 205 4 206 7 207 8 208 12 209 9 210 9 211 8 212 5 213 5 214 9 215 8 216 15 217 6 218 4 219 13 220 7 221 8 222 15 223 6 224 6 225 10arrow_forwardCollagen is used to date artifacts. It has a rate constant = 1.20 x 10-4 /years. What is the half life of collagen?arrow_forward
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