Physics for Scientists and Engineers, Vol. 1
6th Edition
ISBN: 9781429201322
Author: Paul A. Tipler, Gene Mosca
Publisher: Macmillan Higher Education
expand_more
expand_more
format_list_bulleted
Videos
Question
Chapter 25, Problem 58P
(a)
To determine
The resistance of the filament.
(b)
To determine
The diameter of the filament.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
A solar cell generates a potential difference of 0.17 V when a 520 0 resistor is connected across it, and a potential difference of 0.25
V when a 940 resistor is substituted. What are the (a) internal resistance and (b) emf of the solar cell? (c) The area of the cell is 2.5
cm? and the rate per unit area at which it receives energy from light is 5.1 mW/cm². What is the efficiency of the cell for converting
light energy to thermal energy in the 940 Q external resistor?
(a) Number
i
Units
(b) Number
i
Units
(c) Number
Units
>
>
The capacitance in the curcuit is C = 0.3μF, the total resistance is R=20kQ and the battery emf is 12 V. Determine the time is takes for the charge the capacitor could acquire, to reach 99% of max value.
A solar cell generates a potential difference of 0.17 V
when a 550 resistor is connected across it, and a
potential difference of 0.24 V when a 970 resistor
is substituted. What are the (a) internal resistance
and (b) emf of the solar cell? (c) The area of the cell is
1.2 cm² and the rate per unit area at which it receives
energy from light is 4.9 mW/cm². What is the
efficiency of the cell for converting light energy to
thermal energy in the 970 2 external resistor?
(a) Number
(b) Number
(c) Number
i
Units
Units
Units
Ω
V
per
Chapter 25 Solutions
Physics for Scientists and Engineers, Vol. 1
Ch. 25 - Prob. 1PCh. 25 - Prob. 2PCh. 25 - Prob. 3PCh. 25 - Prob. 4PCh. 25 - Prob. 5PCh. 25 - Prob. 6PCh. 25 - Prob. 7PCh. 25 - Prob. 8PCh. 25 - Prob. 9PCh. 25 - Prob. 10P
Ch. 25 - Prob. 11PCh. 25 - Prob. 12PCh. 25 - Prob. 13PCh. 25 - Prob. 14PCh. 25 - Prob. 15PCh. 25 - Prob. 16PCh. 25 - Prob. 17PCh. 25 - Prob. 18PCh. 25 - Prob. 19PCh. 25 - Prob. 20PCh. 25 - Prob. 21PCh. 25 - Prob. 22PCh. 25 - Prob. 23PCh. 25 - Prob. 24PCh. 25 - Prob. 25PCh. 25 - Prob. 26PCh. 25 - Prob. 27PCh. 25 - Prob. 28PCh. 25 - Prob. 29PCh. 25 - Prob. 30PCh. 25 - Prob. 31PCh. 25 - Prob. 32PCh. 25 - Prob. 33PCh. 25 - Prob. 34PCh. 25 - Prob. 35PCh. 25 - Prob. 36PCh. 25 - Prob. 37PCh. 25 - Prob. 38PCh. 25 - Prob. 39PCh. 25 - Prob. 40PCh. 25 - Prob. 41PCh. 25 - Prob. 42PCh. 25 - Prob. 43PCh. 25 - Prob. 44PCh. 25 - Prob. 45PCh. 25 - Prob. 46PCh. 25 - Prob. 47PCh. 25 - Prob. 48PCh. 25 - Prob. 49PCh. 25 - Prob. 50PCh. 25 - Prob. 51PCh. 25 - Prob. 52PCh. 25 - Prob. 53PCh. 25 - Prob. 54PCh. 25 - Prob. 55PCh. 25 - Prob. 56PCh. 25 - Prob. 57PCh. 25 - Prob. 58PCh. 25 - Prob. 59PCh. 25 - Prob. 60PCh. 25 - Prob. 61PCh. 25 - Prob. 62PCh. 25 - Prob. 63PCh. 25 - Prob. 64PCh. 25 - Prob. 65PCh. 25 - Prob. 66PCh. 25 - Prob. 67PCh. 25 - Prob. 68PCh. 25 - Prob. 69PCh. 25 - Prob. 70PCh. 25 - Prob. 71PCh. 25 - Prob. 72PCh. 25 - Prob. 73PCh. 25 - Prob. 74PCh. 25 - Prob. 75PCh. 25 - Prob. 76PCh. 25 - Prob. 77PCh. 25 - Prob. 78PCh. 25 - Prob. 79PCh. 25 - Prob. 80PCh. 25 - Prob. 81PCh. 25 - Prob. 82PCh. 25 - Prob. 83PCh. 25 - Prob. 84PCh. 25 - Prob. 85PCh. 25 - Prob. 86PCh. 25 - Prob. 87PCh. 25 - Prob. 88PCh. 25 - Prob. 89PCh. 25 - Prob. 90PCh. 25 - Prob. 91PCh. 25 - Prob. 92PCh. 25 - Prob. 93PCh. 25 - Prob. 94PCh. 25 - Prob. 95PCh. 25 - Prob. 96PCh. 25 - Prob. 97PCh. 25 - Prob. 98PCh. 25 - Prob. 99PCh. 25 - Prob. 100PCh. 25 - Prob. 101PCh. 25 - Prob. 102PCh. 25 - Prob. 103PCh. 25 - Prob. 104PCh. 25 - Prob. 105PCh. 25 - Prob. 106PCh. 25 - Prob. 107PCh. 25 - Prob. 108PCh. 25 - Prob. 109PCh. 25 - Prob. 110PCh. 25 - Prob. 111PCh. 25 - Prob. 112PCh. 25 - Prob. 113PCh. 25 - Prob. 114PCh. 25 - Prob. 115PCh. 25 - Prob. 116PCh. 25 - Prob. 117PCh. 25 - Prob. 118PCh. 25 - Prob. 119PCh. 25 - Prob. 120P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- Explain why R=R0(1 + a?T) for the temperature variation of the resistance R of an object is not as accurate as P=P0(1 + a?T) which gives the temperature variation of resistivity P.arrow_forwardPls answer thisarrow_forwardThe label on a portable radio recommends the use of rechargeable nickel-cadmium cells (NiCads), although they have a 1.25 V emf while alkaline cells have a 1.58 V emf. The radio has a 3.50 Ω resistance. Calculate the power delivered to the radio (in W) when using NiCad cells each having an internal resistance of 0.0380 Ω. Calculate the power delivered to the radio (in W) when using alkaline cells each having an internal resistance of 0.210 Ω. Does this difference seem significant, considering that the radio's effective resistance is lowered when its volume is turned up?arrow_forward
- A battery has an emf of 15.0 V. A load is connected and the terminal voltage of the battery is found to be 11.6 V. If the power delivered is 20.0 W estimate the resistance of the load.arrow_forwardA standard flashlight battery can deliver about 4.9 W·h of energy before it runs down. (a) If a battery costs 80 cents, what is the cost in dollars of operating a 100 W lamp for 9.0 h using batteries? (b) What is the cost in dollars if power is provided at the rate of 6.0 cents per kilowatt-hour?arrow_forwardA standard flashlight battery can deliver about 1.7 W⚫h of energy before it runs down. (a) If a battery costs 80 cents, what is the cost in dollars of operating a 100 W lamp for 7.6 h using batteries? (b) What is the cost in dollars if power is provided at the rate of 6.0 cents per kilowatt-hour? (a) Number i Units (b) Number i Unitsarrow_forward
- An immersion heater has a resistance of 5.0 ohms while drawing a current of 3.0 ampheres. What is the total electrical energy delivered to the heater during 4.0 minutes of operation?arrow_forwardA 215-KV power transmission line carrying 500 A is hung from grounded metal towers by ceramic insulators, each having a 1.10 x 10 resistance. (a) What is the resistance to ground of 50 of these insulators? (Assume the insulators are connected in parallel.) 2.267 Q (b) Calculate the power dissipated by 50 of them. X What is the voltage across the effective resistance? How can you find the power from the voltage and the resistance? W (c) What fraction of the power carried by the line is this? P x Protal What is the total power carried by the line?arrow_forwardA 20.70 V battery is used to supply current to a 25 k resistor. Assume the voltage drop across any wires used for connections is negligible. (a) What is the current (in mA) through the resistor? 8.28e-7 X mA (b) What is the power dissipated by the resistor (in mW)? 0.0 X mW (c) What is the power input from the battery (in mW), assuming all the electrical power is dissipated by the resistor? mW (d) What happens to the energy dissipated by the resistor? The energy dissipated by the resistor is converted to elastic potential energy. The energy dissipated by the resistor is converted to electric potential energy. The energy dissipated by the resistor is converted to heat. The energy dissipated by the resistor is converted to gravitational potential energy.arrow_forward
- In the figure R1= R2= 10.04 Q, and the ideal battery has emf = 12.15 V. (a) What value of R3 maximizes the rate at which the battery supplies energy and (b) what is that maximum rate? R1 Ry Rs (a) Number i Units (b) Number i Units Warrow_forwardA 5.0 A current is set up in a circuit for 6.0 min by a rechargeable battery with a 6.0 V emf. By how much is the chemical energy of the battery reduced?arrow_forwardA solar cell generates a potential difference of 0.10 V when a 500ohm resistor is connected across it, and a potential difference of 0.15 V when a 1000 ohm resistor is substituted.What are the (a) internal resistance and (b) emf of the solar cell? (c) The area of the cell is 5.0 cm2, and the rate per unit area at which it receives energy from light is 2.0 mW/cm2.What is the efficiency of the cell for converting light energy to thermal energy in the 1000 ohm external resistor?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
College PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning
College PhysicsPhysicsISBN:9781938168000Author:Paul Peter Urone, Roger HinrichsPublisher:OpenStax College
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
College Physics
Physics
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
College Physics
Physics
ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning
College Physics
Physics
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:OpenStax College
How To Solve Any Resistors In Series and Parallel Combination Circuit Problems in Physics; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=eFlJy0cPbsY;License: Standard YouTube License, CC-BY