Physics for Scientists and Engineers, Vol. 1
6th Edition
ISBN: 9781429201322
Author: Paul A. Tipler, Gene Mosca
Publisher: Macmillan Higher Education
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
Chapter 25, Problem 30P
(a)
To determine
The the current in the laser beam.
(b)
To determine
The power of the laser beam.
(c)
To determine
The time period one cancontinuously operate the laser pointer before replacing the batteries.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
A resistor with resistance 28.5 Q is connected to the terminals of a voltage source.
(a) Calculate the current through the resistor when the voltage is set at 9.00 V.
A
(b) Calculate the power dissipated by the resistor when the voltage is set at 9.00 V.
W
(c) If the voltage is doubled, recalculate the power.
A battery has a terminal voltage of 6.0 V when no current flows. Its internalresistance is 1.0 Ω. A 5.0-Ω resistor is connected across the battery terminals.
(a) Calculate the current flowing through the resistor.
(b) What voltage would a voltmeter measure across the battery terminals with the 5.0-Ω resistor connected to the battery?
Te-Learning Portal
Courses -
Reports
e-Services ▼
Academic Departments -
ETC -
CIMS
Salim
During an experiment to verify Ohm's law, the voltage supplied and the current through a circuit are measured.
[Voltage is measured in Volt (V) and current in Ampere (A)].
ww
R
on
Battery
The measured value of the current is I = 3.1 ± 0.2 A and that of the voltage is V = 14 0.5 V. The resistance of
the circuit (in N) can be calculated using the formula, R = V/I,
Calculate the,
a) Resistance (in 2) =
b) Fractional uncertainty in the resistance =
c) Absolute uncertainty (in 2) in the resistance=
Chapter 25 Solutions
Physics for Scientists and Engineers, Vol. 1
Ch. 25 - Prob. 1PCh. 25 - Prob. 2PCh. 25 - Prob. 3PCh. 25 - Prob. 4PCh. 25 - Prob. 5PCh. 25 - Prob. 6PCh. 25 - Prob. 7PCh. 25 - Prob. 8PCh. 25 - Prob. 9PCh. 25 - Prob. 10P
Ch. 25 - Prob. 11PCh. 25 - Prob. 12PCh. 25 - Prob. 13PCh. 25 - Prob. 14PCh. 25 - Prob. 15PCh. 25 - Prob. 16PCh. 25 - Prob. 17PCh. 25 - Prob. 18PCh. 25 - Prob. 19PCh. 25 - Prob. 20PCh. 25 - Prob. 21PCh. 25 - Prob. 22PCh. 25 - Prob. 23PCh. 25 - Prob. 24PCh. 25 - Prob. 25PCh. 25 - Prob. 26PCh. 25 - Prob. 27PCh. 25 - Prob. 28PCh. 25 - Prob. 29PCh. 25 - Prob. 30PCh. 25 - Prob. 31PCh. 25 - Prob. 32PCh. 25 - Prob. 33PCh. 25 - Prob. 34PCh. 25 - Prob. 35PCh. 25 - Prob. 36PCh. 25 - Prob. 37PCh. 25 - Prob. 38PCh. 25 - Prob. 39PCh. 25 - Prob. 40PCh. 25 - Prob. 41PCh. 25 - Prob. 42PCh. 25 - Prob. 43PCh. 25 - Prob. 44PCh. 25 - Prob. 45PCh. 25 - Prob. 46PCh. 25 - Prob. 47PCh. 25 - Prob. 48PCh. 25 - Prob. 49PCh. 25 - Prob. 50PCh. 25 - Prob. 51PCh. 25 - Prob. 52PCh. 25 - Prob. 53PCh. 25 - Prob. 54PCh. 25 - Prob. 55PCh. 25 - Prob. 56PCh. 25 - Prob. 57PCh. 25 - Prob. 58PCh. 25 - Prob. 59PCh. 25 - Prob. 60PCh. 25 - Prob. 61PCh. 25 - Prob. 62PCh. 25 - Prob. 63PCh. 25 - Prob. 64PCh. 25 - Prob. 65PCh. 25 - Prob. 66PCh. 25 - Prob. 67PCh. 25 - Prob. 68PCh. 25 - Prob. 69PCh. 25 - Prob. 70PCh. 25 - Prob. 71PCh. 25 - Prob. 72PCh. 25 - Prob. 73PCh. 25 - Prob. 74PCh. 25 - Prob. 75PCh. 25 - Prob. 76PCh. 25 - Prob. 77PCh. 25 - Prob. 78PCh. 25 - Prob. 79PCh. 25 - Prob. 80PCh. 25 - Prob. 81PCh. 25 - Prob. 82PCh. 25 - Prob. 83PCh. 25 - Prob. 84PCh. 25 - Prob. 85PCh. 25 - Prob. 86PCh. 25 - Prob. 87PCh. 25 - Prob. 88PCh. 25 - Prob. 89PCh. 25 - Prob. 90PCh. 25 - Prob. 91PCh. 25 - Prob. 92PCh. 25 - Prob. 93PCh. 25 - Prob. 94PCh. 25 - Prob. 95PCh. 25 - Prob. 96PCh. 25 - Prob. 97PCh. 25 - Prob. 98PCh. 25 - Prob. 99PCh. 25 - Prob. 100PCh. 25 - Prob. 101PCh. 25 - Prob. 102PCh. 25 - Prob. 103PCh. 25 - Prob. 104PCh. 25 - Prob. 105PCh. 25 - Prob. 106PCh. 25 - Prob. 107PCh. 25 - Prob. 108PCh. 25 - Prob. 109PCh. 25 - Prob. 110PCh. 25 - Prob. 111PCh. 25 - Prob. 112PCh. 25 - Prob. 113PCh. 25 - Prob. 114PCh. 25 - Prob. 115PCh. 25 - Prob. 116PCh. 25 - Prob. 117PCh. 25 - Prob. 118PCh. 25 - Prob. 119PCh. 25 - Prob. 120P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- Resistors are commonly rated at 18W,14W,12W ,1 W and 2 W for use in electrical circuits. If a current of1 = 2.00 A is accidentally passed through a R=1.00 resistor rated at 1 W, what would be the most probable outcome? Is there anything that can be done to prevent such an accident?arrow_forwardIf the terminals of a battery with zero internal resistance are connected across two identical resistors in series, the total power delivered by the battery is 8.00 W. If the same battery is connected across the same resistors in parallel, what is the total power delivered by the battery? (a) 16.0 W (b) 32.0 W (c) 2.00 W (d) 4.00 W (e) none of those answersarrow_forward(a) Reduce the circuit to one mesh to find the current in the upper 1 Ohm resistor. (b) Use your answer in (a) to fond the current in the 24 Ohm resistor. 125 V 125 V 10 m K 202 www 10 www is 120 12402arrow_forward
- (a) Suppose two resistors are connected in parallel with resistances Rị and R2 measured in Ohms (N). The total resistance R is given by 1 1 1 R R1 R2 Suppose R1 is increasing at a rate of 1/4 2/s and R2 is increasing at a rate of 1/16 N/s. At what rate is R changing when R1 = 1/2 N and R2 = 1/4 N. (b) Car A is traveling North at a rate of 60 mi/hr, car B is traveling West at a rate of 45 mi/hr. The cars are on straight roads approaching an intersection point. At what rate is the distance between the cars changing when Car A is 3 miles from the intersection and Car B is 4 miles from the intersection.arrow_forwardTwo resistors R1 and R2 may be connected either in series or in parallel across an ideal battery with emf e.We desire the rate of energy dissipation of the parallel combination to be five times that of the series combination. If R1 = 100 ohm, what are the (a) smaller and (b) larger of the two values of R2 that result in that dissipation rate?arrow_forward(a) When measuring the voltage across a resistor and the current through it, the voltmeter and the ammeter should be connected in respectively, to the resistor. series and series series and parallel O parallel and series O parallel and parallel (b) The resistances of an ideal voltmeter and ammeter should be infinity and zero infinity and infinity zero and infinity zero and zero respectively. Hint: Voltage is the measure of difference of the potential between two different points. Current is the measure of the flow of electrons.arrow_forward
- When a R = 88.7 Q resistor is connected across a 11.1 V battery, a current of 112.8 mA flows. What is the internal resistance of the battery and Terminal voltage of the battery? (1) E(MF) Rexternal external Rinterna (a) internal resistance of the battery(in 2) = (b) Terminal voltage of the battery in V = .--- Batteryarrow_forwardA capacitor of capacitance C = 2x 10^-6 is discharged through a resistor of resistance = 10^5 ohm. When will the energy stored in a capacitor reduce to one-third of its initial valuearrow_forwardWhen a R = 90.7 Q resistor is connected across a 12 V battery, a current of 124.2 mA flows. What is the internal resistance of the battery and Terminal voltage of the battery ? (a) internal resistance of the battery(in 2) = (b) Terminal voltage of the battery in V = %3Darrow_forward
- You buy a AA battery in the store, and it has an emf of 1.5 V and small amount of internal resistance. While this battery is fresh O its terminal voltage will be more than 1.5 V when it is used in a circuit. O its terminal voltage will be 1.5 V when it is used in a circuit. its terminal voltage will be less than 1.5 V when it is used in a circuit.arrow_forwardGiven two batteries: one with voltage Vand internal resistance r1; another with also voltage Vand internal resistance rɔ. Which of the following is true if we connect them in series facing the opposite direction? O No voltage will remain, while the total internal resistance will be r1 + r2. O The total voltage will be -V, while the total internal resistance will be r1 + r2. O The total voltage will be -2V, while the total internal resistance will be r1 + r2. O The answer can be found on the other choices.arrow_forwardI would like help with (a) - (c). In the figure the ideal batteries have emfs E1 = 16 V and E2 = 11.0 V and the resistors have resistances R1 = 5.3 Ω and R2 = 8.4 Ω. What are (a) the current, the energy dissipation rate in (b) resistor 1 and (c) resistor 2, and the energy transfer rate in (d) battery 1 and (e) battery 2? Is energy being supplied or absorbed by (f) battery 1 and (g) battery 2?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
College PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
College Physics
Physics
ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
College Physics
Physics
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning
Ohm's law Explained; Author: ALL ABOUT ELECTRONICS;https://www.youtube.com/watch?v=PV8CMZZKrB4;License: Standard YouTube License, CC-BY