Physics For Scientists And Engineers With Modern Physics, 9th Edition, The Ohio State University
9th Edition
ISBN: 9781305372337
Author: Raymond A. Serway | John W. Jewett
Publisher: Cengage Learning
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Chapter 25, Problem 45P
(a)
To determine
The units of
(b)
To determine
The electric potential at
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Three point-like charges are placed at the corners of an equilateral triangle as shown in the figure. Each side of the triangle has a length of 20.0 cm, and the point (A) is located half way between q1 and q2 along the side. Find the magnitude of the electric field at point (A). Let q1=-1.30 µC, q2=-4.20µC, and q3= +4.30 µC.
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Chapter 25 Solutions
Physics For Scientists And Engineers With Modern Physics, 9th Edition, The Ohio State University
Ch. 25.1 - two points and are located within a region in...Ch. 25.2 - QUICK QUIZ 24.2 The labeled points in Figure 24.4...Ch. 25.3 - In Figure 24.8b, take q2, to be a negative source...Ch. 25.4 - In a certain region of space, the electric...Ch. 25 - Prob. 1OQCh. 25 - Prob. 2OQCh. 25 - Prob. 3OQCh. 25 - Prob. 4OQCh. 25 - Prob. 5OQCh. 25 - Prob. 6OQ
Ch. 25 - Prob. 7OQCh. 25 - Prob. 8OQCh. 25 - Prob. 9OQCh. 25 - Prob. 10OQCh. 25 - Prob. 11OQCh. 25 - Prob. 12OQCh. 25 - Prob. 13OQCh. 25 - Prob. 14OQCh. 25 - Prob. 15OQCh. 25 - Prob. 1CQCh. 25 - Prob. 2CQCh. 25 - When charged particles are separated by an...Ch. 25 - Prob. 4CQCh. 25 - Prob. 5CQCh. 25 - Prob. 6CQCh. 25 - Oppositely charged parallel plates are separated...Ch. 25 - Prob. 2PCh. 25 - Prob. 3PCh. 25 - How much work is done (by a battery, generator, or...Ch. 25 - Prob. 5PCh. 25 - Starting with the definition of work, prove that...Ch. 25 - Prob. 7PCh. 25 - (a) Find the electric potential difference Ve...Ch. 25 - Prob. 9PCh. 25 - Prob. 10PCh. 25 - Prob. 11PCh. 25 - Prob. 12PCh. 25 - Prob. 13PCh. 25 - Prob. 14PCh. 25 - Prob. 15PCh. 25 - Two point charges Q1 = +5.00 nC and Q2 = 3.00 nC...Ch. 25 - Prob. 17PCh. 25 - Prob. 18PCh. 25 - Given two particles with 2.00-C charges as shown...Ch. 25 - Prob. 20PCh. 25 - Four point charges each having charge Q are...Ch. 25 - Prob. 22PCh. 25 - Prob. 23PCh. 25 - Show that the amount of work required to assemble...Ch. 25 - Prob. 25PCh. 25 - Prob. 26PCh. 25 - Prob. 27PCh. 25 - Prob. 28PCh. 25 - Prob. 29PCh. 25 - Prob. 30PCh. 25 - Prob. 31PCh. 25 - Prob. 32PCh. 25 - How much work is required to assemble eight...Ch. 25 - Four identical particles, each having charge q and...Ch. 25 - Prob. 35PCh. 25 - Prob. 36PCh. 25 - Prob. 37PCh. 25 - Prob. 38PCh. 25 - Prob. 39PCh. 25 - Prob. 40PCh. 25 - Prob. 41PCh. 25 - Prob. 42PCh. 25 - Prob. 43PCh. 25 - Prob. 44PCh. 25 - Prob. 45PCh. 25 - Prob. 46PCh. 25 - Prob. 47PCh. 25 - The electric field magnitude on the surface of an...Ch. 25 - Prob. 49PCh. 25 - Prob. 50PCh. 25 - Prob. 51PCh. 25 - Prob. 52PCh. 25 - Prob. 53APCh. 25 - Prob. 54APCh. 25 - Prob. 55APCh. 25 - Prob. 56APCh. 25 - Prob. 57APCh. 25 - Prob. 58APCh. 25 - Prob. 59APCh. 25 - Prob. 60APCh. 25 - Prob. 61APCh. 25 - Prob. 62APCh. 25 - Prob. 63APCh. 25 - Prob. 64APCh. 25 - Prob. 65APCh. 25 - Prob. 66APCh. 25 - Prob. 67APCh. 25 - Prob. 68APCh. 25 - Review. Two parallel plates having charges of...Ch. 25 - When an uncharged conducting sphere of radius a is...Ch. 25 - Prob. 71CPCh. 25 - Prob. 72CPCh. 25 - Prob. 73CPCh. 25 - Prob. 74CPCh. 25 - Prob. 75CPCh. 25 - Prob. 76CPCh. 25 - Prob. 77CP
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- Find the total capacitance in micro farads of the combination of capacitors shown in the figure below. HF 5.0 µF 3.5 µF №8.0 μLE 1.5 µF Ι 0.75 μF 15 μFarrow_forwardthe answer is not 0.39 or 0.386arrow_forwardFind the total capacitance in micro farads of the combination of capacitors shown in the figure below. 2.01 0.30 µF 2.5 µF 10 μF × HFarrow_forward
- I do not understand the process to answer the second part of question b. Please help me understand how to get there!arrow_forwardRank the six combinations of electric charges on the basis of the electric force acting on 91. Define forces pointing to the right as positive and forces pointing to the left as negative. Rank in increasing order by placing the most negative on the left and the most positive on the right. To rank items as equivalent, overlap them. ▸ View Available Hint(s) [most negative 91 = +1nC 92 = +1nC 91 = -1nC 93 = +1nC 92- +1nC 93 = +1nC -1nC 92- -1nC 93- -1nC 91= +1nC 92 = +1nC 93=-1nC 91 +1nC 92=-1nC 93=-1nC 91 = +1nC 2 = −1nC 93 = +1nC The correct ranking cannot be determined. Reset Help most positivearrow_forwardPart A Find the x-component of the electric field at the origin, point O. Express your answer in newtons per coulomb to three significant figures, keeping in mind that an x component that points to the right is positive. ▸ View Available Hint(s) Eoz = Η ΑΣΦ ? N/C Submit Part B Now, assume that charge q2 is negative; q2 = -6 nC, as shown in (Figure 2). What is the x-component of the net electric field at the origin, point O? Express your answer in newtons per coulomb to three significant figures, keeping in mind that an x component that points to the right is positive. ▸ View Available Hint(s) Eoz= Η ΑΣΦ ? N/Carrow_forward
- 1. A charge of -25 μC is distributed uniformly throughout a spherical volume of radius 11.5 cm. Determine the electric field due to this charge at a distance of (a) 2 cm, (b) 4.6 cm, and (c) 25 cm from the center of the sphere. (a) = = (b) E = (c)Ẻ = = NC NC NCarrow_forward1. A long silver rod of radius 3.5 cm has a charge of -3.9 ис on its surface. Here ŕ is a unit vector ст directed perpendicularly away from the axis of the rod as shown in the figure. (a) Find the electric field at a point 5 cm from the center of the rod (an outside point). E = N C (b) Find the electric field at a point 1.8 cm from the center of the rod (an inside point) E=0 Think & Prepare N C 1. Is there a symmetry in the charge distribution? What kind of symmetry? 2. The problem gives the charge per unit length 1. How do you figure out the surface charge density σ from a?arrow_forward1. Determine the electric flux through each surface whose cross-section is shown below. 55 S₂ -29 S5 SA S3 + 9 Enter your answer in terms of q and ε Φ (a) s₁ (b) s₂ = -29 (C) Φ զ Ερ (d) SA = (e) $5 (f) Sa $6 = II ✓ -29 S6 +39arrow_forward
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