Chapter 25, Problem 25.36P

Interpretation Introduction

(a)

Interpretation:

For the given reaction there are two possible radical addition steps. The curved arrow notation and product for both radical additions are to be drawn and more stable product is to be predicted.

Concept introduction:

One atom of a double or triple bond forms a bond to a free radical, and the other atom of the double or triple bond gains an unpaired electron to form a radical, in a radical addition step. A single-barbed arrow is used to show the movement of a single electron in an elementary step. The order for radical stability is ${\text{3}}^{\text{o}}{\text{ > 2}}^{\text{o}}{\text{ > 1}}^{\text{o}}$.

Interpretation Introduction

(b)

Interpretation:

For the given reaction there are two possible radical addition steps. The curved arrow notation and product for both radical additions are to be drawn and more stable product is to be predicted. A single-barbed arrow is used to show the movement of a single electron in an elementary step.

Concept introduction:

One atom of a double or triple bond forms a bond to a free radical, and the other atom of the double or triple bond gains an unpaired electron to form a radical, in a radical addition step. A single-barbed arrow is used to show the movement of a single electron in an elementary step. The order for radical stability is ${\text{3}}^{\text{o}}{\text{ > 2}}^{\text{o}}{\text{ > 1}}^{\text{o}}$. Radical adjacent to $\text{π}$ bond is more stable.