Make Sense? During the winter, you program your home thermostat so that at midnight, the temperature is 55 ∘ . This temperature is maintained until 6 a.m. Then the house begins to warm up so that by 9 a.m. the temperature is 65 ∘ . At 6 p.m. the house begins to cool. By 9 p.m. the temperature is again 55 ∘ . The graph illustrates home temperature, f (l), as a function of house after midnight, t. In Exercises 137-140, determine whether each statement makes sense or does not make sense, and explain your reasoning. If the statement makes sense, graph the new function on the domain (0.24). If the statement does not make sense, correct the function in the statement and graph the corrected function on the domain (0.24). I decided to change the heating schedule to start one hour later than before, so I reprogrammed the thermostat to y = f ( t + 1 )
Make Sense? During the winter, you program your home thermostat so that at midnight, the temperature is 55 ∘ . This temperature is maintained until 6 a.m. Then the house begins to warm up so that by 9 a.m. the temperature is 65 ∘ . At 6 p.m. the house begins to cool. By 9 p.m. the temperature is again 55 ∘ . The graph illustrates home temperature, f (l), as a function of house after midnight, t. In Exercises 137-140, determine whether each statement makes sense or does not make sense, and explain your reasoning. If the statement makes sense, graph the new function on the domain (0.24). If the statement does not make sense, correct the function in the statement and graph the corrected function on the domain (0.24). I decided to change the heating schedule to start one hour later than before, so I reprogrammed the thermostat to y = f ( t + 1 )
Solution Summary: The author analyzes whether the statement, "I decided to change the heating schedule to start one hour later than before, so I reprogrammed the thermostat to y=f(t+1)"
Make Sense?During the winter, you program your home thermostat so that at midnight, the temperature is
55
∘
. This temperature is maintained until 6 a.m. Then the house begins to warm up so that by 9 a.m. the temperature is
65
∘
. At 6 p.m. the house begins to cool. By 9 p.m. the temperature is again
55
∘
. The graph illustrates home temperature, f (l), as a function of house after midnight, t.
In Exercises 137-140, determine whether each statement makes sense or does not make sense, and explain your reasoning. If the statement makes sense, graph the new function on the domain (0.24). If the statement does not make sense, correct the function in the statement and graph the corrected function on the domain (0.24).
I decided to change the heating schedule to start one hour later than before, so I reprogrammed the thermostat to
y
=
f
(
t
+
1
)
10-2
Let A =
02-4
and b =
4
Denote the columns of A by a₁, a2, a3, and let W = Span {a1, a2, a̸3}.
-4 6
5
- 35
a. Is b in {a1, a2, a3}? How many vectors are in {a₁, a₂, a3}?
b. Is b in W? How many vectors are in W?
c. Show that a2 is in W. [Hint: Row operations are unnecessary.]
a. Is b in {a₁, a2, a3}? Select the correct choice below and, if necessary, fill in the answer box(es) to complete your
choice.
○ A. No, b is not in {a₁, a2, 3} since it cannot be generated by a linear combination of a₁, a2, and a3.
B. No, b is not in (a1, a2, a3}
since b is not equal to a₁, a2, or a3.
C. Yes, b is in (a1, a2, a3} since b = a
(Type a whole number.)
D. Yes, b is in (a1, a2, 3} since, although b is not equal to a₁, a2, or a3, it can be expressed as a linear
combination of them. In particular, b =
+
+
☐ az.
(Simplify your answers.)
14
14
4. The graph shows the printing rate of Printer A. Printer B can
print at a rate of 25 pages per minute. How does the printing
rate for Printer B compare to the printing rate for Printer A?
The printing rate for Printer B is
than the rate
for Printer A because the rate of 25 pages per minute
is
than the rate of
for Printer A.
pages per minute
RIJOUT
40
fy
Printer Rat
Number of Pages
8N WA
10
30
20
Printer A
0
0
246
Time (min)
X
OR
16 f(x) =
Ef 16
χ
по
x²-2 410 | y = (x+2) + 4
Y-INT: y = 0
X-INT: X=0
VA: x=2
OA: y=x+2
0
X-INT: X=-2
X-INT: y = 2
VA
0
2
whole.
2-2
4
y - (x+2) = 27-270
+
xxx> 2
क्
above OA
(x+2) OA
x-2/x²+0x+0
2
x-2x
2x+O
2x-4
4
X<-1000 4/4/2<0 below Of
y
VA
X=2
X-2
OA
y=x+2
-2
2
(0,0)
2
χ
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