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Match the division problem on the left with the correct quotient on the left. Note that the denominators of the reminders are omitted and replaced with R. 1) (k3-10k²+k+1) ÷ (k − 1) 2) (k4-4k-28k45k+26)+(k+7) 3) (20k+222-7k+7)+(5k-2) 4) (3+63-15k +32k-25)+(k+4) 5) (317k 13) ÷ (k+4) - 6) (k-k+8k+5)+(k+1) 7) (4-12k+6) + (k-3) 8) (3k+4k3 + 15k + 10) ÷ (3k+4) A) 3k3-6k29k - 4 B) 4k2 + 6 R 7 C)²-9k-8- R D) 4k2+6x+1+ E) 10 Elk³-5-12 R 9 F) k² - 4k R 9 R G) k3-3k2-7k+4 H) k³-k²+8 - 3 R - R 9 R

Match the division problem on the left with the correct quotient on the left. Note that the denominators of the reminders are omitted and replaced with R. 1) (k3-10k²+k+1) ÷ (k − 1) 2) (k4-4k-28k45k+26)+(k+7) 3) (20k+222-7k+7)+(5k-2) 4) (3+63-15k +32k-25)+(k+4) 5) (317k 13) ÷ (k+4) - 6) (k-k+8k+5)+(k+1) 7) (4-12k+6) + (k-3) 8) (3k+4k3 + 15k + 10) ÷ (3k+4) A) 3k3-6k29k - 4 B) 4k2 + 6 R 7 C)²-9k-8- R D) 4k2+6x+1+ E) 10 Elk³-5-12 R 9 F) k² - 4k R 9 R G) k3-3k2-7k+4 H) k³-k²+8 - 3 R - R 9 R

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter8: Polynomials
Section8.3: Multiplying Polynomials
Problem 54PFA
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Match the division problem on the left with the correct quotient on the left. Note that the denominators of the reminders are omitted and replaced with R. 1) (k3-10k²+k+1) ÷ (k − 1) 2) (k4-4k-28k45k+26)+(k+7) 3) (20k+222-7k+7)+(5k-2) 4) (3+63-15k +32k-25)+(k+4) 5) (317k 13) ÷ (k+4) - 6) (k-k+8k+5)+(k+1) 7) (4-12k+6) + (k-3) 8) (3k+4k3 + 15k + 10) ÷ (3k+4) A) 3k3-6k29k - 4 B) 4k2 + 6 R 7 C)²-9k-8- R D) 4k2+6x+1+ E) 10 Elk³-5-12 R 9 F) k² - 4k R 9 R G) k3-3k2-7k+4 H) k³-k²+8 - 3 R - R 9 R
Transcribed Image Text:Match the division problem on the left with the correct quotient on the left. Note that the denominators of the reminders are omitted and replaced with R. 1) (k3-10k²+k+1) ÷ (k − 1) 2) (k4-4k-28k45k+26)+(k+7) 3) (20k+222-7k+7)+(5k-2) 4) (3+63-15k +32k-25)+(k+4) 5) (317k 13) ÷ (k+4) - 6) (k-k+8k+5)+(k+1) 7) (4-12k+6) + (k-3) 8) (3k+4k3 + 15k + 10) ÷ (3k+4) A) 3k3-6k29k - 4 B) 4k2 + 6 R 7 C)²-9k-8- R D) 4k2+6x+1+ E) 10 Elk³-5-12 R 9 F) k² - 4k R 9 R G) k3-3k2-7k+4 H) k³-k²+8 - 3 R - R 9 R
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