Chapter 24.3, Problem 21PP

Interpretation Introduction

Interpretation:

An artifact is bombarded with neutrons and product should be the cadmium-110, then target and unstable isotopes in this process needs to be explained.

Concept introduction:.

The nuclear reaction and transmutations are examples of radioactive decay. In this process, one element is converted into other by spontaneous emission of radiation. The transmutation can takes place when a stable nucleus is bombarded with alpha, beta and gamma radiations.

Answer to Problem 21PP

In this process T is silver-109 and I is silver-110.

Explanation of Solution

According to the given figure

$\begin{array}{l}\text{n+T=I}\\ {\text{I=β+}}_{\text{48}}^{\text{110}}\text{Cd}\end{array}$

Here, T represents target and I represent unstable isotope.

Balancing the second equation gives:

${}_{\text{47}}^{\text{110}}{\text{Ag=β+}}_{\text{48}}^{\text{110}}\text{Cd}$

The first equation is then:

${\text{n+T=}}_{\text{47}}^{\text{110}}\text{Ag}$.......(1)

Balancing equation (1).

${\text{n+}}_{\text{47}}^{\text{109}}{\text{Ag=}}_{\text{47}}^{\text{110}}\text{Ag}$

Hence, the T is silver-109 and I is silver-110.

Conclusion

T is silver-109 and I is silver-110.