Each of the given compounds should be classified based on whether it is aldose or ketose and the numbers of carbon atoms presented in it (example: aldopentose). Concept introduction: Carbohydrates are classified into two based on the presence of either aldehyde group or ketone group, that is aldose and ketose. Monosaccharides are simple sugars or carbohydrates. monosaccharides are classified on the basis of, Presents of aldehyde or ketone group such as aldo or keto. Number of carbon atoms presented in a carbohydrates, triose (3 carbon), tetrose (4 carbon), pentose (5 carbon), hexose (6 carbon) or heptose (7 carbon) (ose indicates the carbohydrates). To classify: the given compound (a) based on whether it is aldose or ketose and the numbers of carbon atoms presented in it.

Question

Want to see the full answer?

Answer 1

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 24.2, Problem 1CC

(a)

Interpretation Introduction

Interpretation:

Each of the given compounds should be classified based on whether it is aldose or ketose and the numbers of carbon atoms presented in it (example: aldopentose).

Concept introduction:

Carbohydrates are classified into two based on the presence of either aldehyde group or ketone group, that is aldose and ketose.

Monosaccharides are simple sugars or carbohydrates.

monosaccharides are classified on the basis of,

Presents of aldehyde or ketone group such as aldo or keto.

Number of carbon atoms presented in a carbohydrates, triose (3 carbon), tetrose (4 carbon), pentose (5 carbon), hexose (6 carbon) or heptose (7 carbon) (ose indicates the carbohydrates).

To classify: the given compound (a) based on whether it is aldose or ketose and the numbers of carbon atoms presented in it.

(b)

Interpretation Introduction

Interpretation:

Each of the given compounds should be classified based on whether it is aldose or ketose and the numbers of carbon atoms presented in it (example: aldopentose).

Concept introduction:

Carbohydrates are classified into two based on the presence of either aldehyde group or ketone group, that is aldose and ketose.

Monosaccharides are simple sugars or carbohydrates.

monosaccharides are classified on the basis of,

Presents of aldehyde or ketone group such as aldo or keto.

Number of carbon atoms presented in a carbohydrates, triose (3 carbon), tetrose (4 carbon), pentose (5 carbon), hexose (6 carbon) or heptose (7 carbon) (ose indicates the carbohydrates).

To classify: the given compound (b) based on whether it is aldose or ketose and the numbers of carbon atoms presented in it.

(c)

Interpretation Introduction

Interpretation:

Each of the given compounds should be classified based on whether it is aldose or ketose and the numbers of carbon atoms presented in it (example: aldopentose).

Concept introduction:

Carbohydrates are classified into two based on the presence of either aldehyde group or ketone group, that is aldose and ketose.

Monosaccharides are simple sugars or carbohydrates.

monosaccharides are classified on the basis of,

Presents of aldehyde or ketone group such as aldo or keto.

Number of carbon atoms presented in a carbohydrates, triose (3 carbon), tetrose (4 carbon), pentose (5 carbon), hexose (6 carbon) or heptose (7 carbon) (ose indicates the carbohydrates).

To classify: the given compound (c) based on whether it is aldose or ketose and the numbers of carbon atoms presented in it.

The given compound is Ketopentose.

(d)

Interpretation Introduction

Interpretation:

Each of the given compounds should be classified based on whether it is aldose or ketose and the numbers of carbon atoms presented in it (example: aldopentose).

Concept introduction:

Carbohydrates are classified into two based on the presence of either aldehyde group or ketone group, that is aldose and ketose.

Monosaccharides are simple sugars or carbohydrates.

monosaccharides are classified on the basis of,

Presents of aldehyde or ketone group such as aldo or keto.

Number of carbon atoms presented in a carbohydrates, triose (3 carbon), tetrose (4 carbon), pentose (5 carbon), hexose (6 carbon) or heptose (7 carbon) (ose indicates the carbohydrates).

To classify: the given compound (d) based on whether it is aldose or ketose and the numbers of carbon atoms presented in it.

(e)

Interpretation Introduction

Interpretation:

Each of the given compounds should be classified based on whether it is aldose or ketose and the numbers of carbon atoms presented in it (example: aldopentose).

Concept introduction:

Carbohydrates are classified into two based on the presence of either aldehyde group or ketone group, that is aldose and ketose.

Monosaccharides are simple sugars or carbohydrates.

monosaccharides are classified on the basis of,

Presents of aldehyde or ketone group such as aldo or keto.

Number of carbon atoms presented in a carbohydrates, triose (3 carbon), tetrose (4 carbon), pentose (5 carbon), hexose (6 carbon) or heptose (7 carbon) (ose indicates the carbohydrates).

To classify: the given compound (e) based on whether it is aldose or ketose and the numbers of carbon atoms presented in it.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

What are the IUPAC Names of all the compounds in the picture?

1) a) Give the dominant Intermolecular Force (IMF) in a sample of each of the following compounds. Please show your work. (8) SF2, CH,OH, C₂H₂ b) Based on your answers given above, list the compounds in order of their Boiling Point from low to high. (8)

19.78 Write the products of the following sequences of reactions. Refer to your reaction road- maps to see how the combined reactions allow you to "navigate" between the different functional groups. Note that you will need your old Chapters 6-11 and Chapters 15-18 roadmaps along with your new Chapter 19 roadmap for these. (a) 1. BHS 2. H₂O₂ 3. H₂CrO4 4. SOCI₂ (b) 1. Cl₂/hv 2. KOLBU 3. H₂O, catalytic H₂SO4 4. H₂CrO4 Reaction Roadmap An alkene 5. EtOH 6.0.5 Equiv. NaOEt/EtOH 7. Mild H₂O An alkane 1.0 2. (CH3)₂S 3. H₂CrO (d) (c) 4. Excess EtOH, catalytic H₂SO OH 4. Mild H₂O* 5.0.5 Equiv. NaOEt/EtOH An alkene 6. Mild H₂O* A carboxylic acid 7. Mild H₂O* 1. SOC₁₂ 2. EtOH 3.0.5 Equiv. NaOEt/E:OH 5.1.0 Equiv. NaOEt 6. NH₂ (e) 1. 0.5 Equiv. NaOEt/EtOH 2. Mild H₂O* Br (f) i H An aldehyde 1. Catalytic NaOE/EtOH 2. H₂O*, heat 3. (CH,CH₂)₂Culi 4. Mild H₂O* 5.1.0 Equiv. LDA Br An ester 4. NaOH, H₂O 5. Mild H₂O* 6. Heat 7. MgBr 8. Mild H₂O* 7. Mild H₂O+

Answer 2

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 24.2, Problem 1CC

(a)

Interpretation Introduction

Interpretation:

Each of the given compounds should be classified based on whether it is aldose or ketose and the numbers of carbon atoms presented in it (example: aldopentose).

Concept introduction:

Carbohydrates are classified into two based on the presence of either aldehyde group or ketone group, that is aldose and ketose.

Monosaccharides are simple sugars or carbohydrates.

monosaccharides are classified on the basis of,

Presents of aldehyde or ketone group such as aldo or keto.

Number of carbon atoms presented in a carbohydrates, triose (3 carbon), tetrose (4 carbon), pentose (5 carbon), hexose (6 carbon) or heptose (7 carbon) (ose indicates the carbohydrates).

To classify: the given compound (a) based on whether it is aldose or ketose and the numbers of carbon atoms presented in it.

(b)

Interpretation Introduction

Interpretation:

Each of the given compounds should be classified based on whether it is aldose or ketose and the numbers of carbon atoms presented in it (example: aldopentose).

Concept introduction:

Carbohydrates are classified into two based on the presence of either aldehyde group or ketone group, that is aldose and ketose.

Monosaccharides are simple sugars or carbohydrates.

monosaccharides are classified on the basis of,

Presents of aldehyde or ketone group such as aldo or keto.

Number of carbon atoms presented in a carbohydrates, triose (3 carbon), tetrose (4 carbon), pentose (5 carbon), hexose (6 carbon) or heptose (7 carbon) (ose indicates the carbohydrates).

To classify: the given compound (b) based on whether it is aldose or ketose and the numbers of carbon atoms presented in it.

(c)

Interpretation Introduction

Interpretation:

Each of the given compounds should be classified based on whether it is aldose or ketose and the numbers of carbon atoms presented in it (example: aldopentose).

Concept introduction:

Carbohydrates are classified into two based on the presence of either aldehyde group or ketone group, that is aldose and ketose.

Monosaccharides are simple sugars or carbohydrates.

monosaccharides are classified on the basis of,

Presents of aldehyde or ketone group such as aldo or keto.

Number of carbon atoms presented in a carbohydrates, triose (3 carbon), tetrose (4 carbon), pentose (5 carbon), hexose (6 carbon) or heptose (7 carbon) (ose indicates the carbohydrates).

To classify: the given compound (c) based on whether it is aldose or ketose and the numbers of carbon atoms presented in it.

The given compound is Ketopentose.

(d)

Interpretation Introduction

Interpretation:

Each of the given compounds should be classified based on whether it is aldose or ketose and the numbers of carbon atoms presented in it (example: aldopentose).

Concept introduction:

Carbohydrates are classified into two based on the presence of either aldehyde group or ketone group, that is aldose and ketose.

Monosaccharides are simple sugars or carbohydrates.

monosaccharides are classified on the basis of,

Presents of aldehyde or ketone group such as aldo or keto.

Number of carbon atoms presented in a carbohydrates, triose (3 carbon), tetrose (4 carbon), pentose (5 carbon), hexose (6 carbon) or heptose (7 carbon) (ose indicates the carbohydrates).

To classify: the given compound (d) based on whether it is aldose or ketose and the numbers of carbon atoms presented in it.

(e)

Interpretation Introduction

Interpretation:

Each of the given compounds should be classified based on whether it is aldose or ketose and the numbers of carbon atoms presented in it (example: aldopentose).

Concept introduction:

Carbohydrates are classified into two based on the presence of either aldehyde group or ketone group, that is aldose and ketose.

Monosaccharides are simple sugars or carbohydrates.

monosaccharides are classified on the basis of,

Presents of aldehyde or ketone group such as aldo or keto.

Number of carbon atoms presented in a carbohydrates, triose (3 carbon), tetrose (4 carbon), pentose (5 carbon), hexose (6 carbon) or heptose (7 carbon) (ose indicates the carbohydrates).

To classify: the given compound (e) based on whether it is aldose or ketose and the numbers of carbon atoms presented in it.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 24.2, Problem 1CC

(a)

Interpretation Introduction

Interpretation:

Each of the given compounds should be classified based on whether it is aldose or ketose and the numbers of carbon atoms presented in it (example: aldopentose).

Concept introduction:

Carbohydrates are classified into two based on the presence of either aldehyde group or ketone group, that is aldose and ketose.

Monosaccharides are simple sugars or carbohydrates.

monosaccharides are classified on the basis of,

Presents of aldehyde or ketone group such as aldo or keto.

Number of carbon atoms presented in a carbohydrates, triose (3 carbon), tetrose (4 carbon), pentose (5 carbon), hexose (6 carbon) or heptose (7 carbon) (ose indicates the carbohydrates).

To classify: the given compound (a) based on whether it is aldose or ketose and the numbers of carbon atoms presented in it.

(b)

Interpretation Introduction

Interpretation:

Each of the given compounds should be classified based on whether it is aldose or ketose and the numbers of carbon atoms presented in it (example: aldopentose).

Concept introduction:

Carbohydrates are classified into two based on the presence of either aldehyde group or ketone group, that is aldose and ketose.

Monosaccharides are simple sugars or carbohydrates.

monosaccharides are classified on the basis of,

Presents of aldehyde or ketone group such as aldo or keto.

Number of carbon atoms presented in a carbohydrates, triose (3 carbon), tetrose (4 carbon), pentose (5 carbon), hexose (6 carbon) or heptose (7 carbon) (ose indicates the carbohydrates).

To classify: the given compound (b) based on whether it is aldose or ketose and the numbers of carbon atoms presented in it.

(c)

Interpretation Introduction

Interpretation:

Each of the given compounds should be classified based on whether it is aldose or ketose and the numbers of carbon atoms presented in it (example: aldopentose).

Concept introduction:

Carbohydrates are classified into two based on the presence of either aldehyde group or ketone group, that is aldose and ketose.

Monosaccharides are simple sugars or carbohydrates.

monosaccharides are classified on the basis of,

Presents of aldehyde or ketone group such as aldo or keto.

Number of carbon atoms presented in a carbohydrates, triose (3 carbon), tetrose (4 carbon), pentose (5 carbon), hexose (6 carbon) or heptose (7 carbon) (ose indicates the carbohydrates).

To classify: the given compound (c) based on whether it is aldose or ketose and the numbers of carbon atoms presented in it.

The given compound is Ketopentose.

(d)

Interpretation Introduction

Interpretation:

Each of the given compounds should be classified based on whether it is aldose or ketose and the numbers of carbon atoms presented in it (example: aldopentose).

Concept introduction:

Carbohydrates are classified into two based on the presence of either aldehyde group or ketone group, that is aldose and ketose.

Monosaccharides are simple sugars or carbohydrates.

monosaccharides are classified on the basis of,

Presents of aldehyde or ketone group such as aldo or keto.

Number of carbon atoms presented in a carbohydrates, triose (3 carbon), tetrose (4 carbon), pentose (5 carbon), hexose (6 carbon) or heptose (7 carbon) (ose indicates the carbohydrates).

To classify: the given compound (d) based on whether it is aldose or ketose and the numbers of carbon atoms presented in it.

(e)

Interpretation Introduction

Interpretation:

Each of the given compounds should be classified based on whether it is aldose or ketose and the numbers of carbon atoms presented in it (example: aldopentose).

Concept introduction:

Carbohydrates are classified into two based on the presence of either aldehyde group or ketone group, that is aldose and ketose.

Monosaccharides are simple sugars or carbohydrates.

monosaccharides are classified on the basis of,

Presents of aldehyde or ketone group such as aldo or keto.

Number of carbon atoms presented in a carbohydrates, triose (3 carbon), tetrose (4 carbon), pentose (5 carbon), hexose (6 carbon) or heptose (7 carbon) (ose indicates the carbohydrates).

To classify: the given compound (e) based on whether it is aldose or ketose and the numbers of carbon atoms presented in it.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 24.2, Problem 1CC

(a)

Interpretation Introduction

Interpretation:

Each of the given compounds should be classified based on whether it is aldose or ketose and the numbers of carbon atoms presented in it (example: aldopentose).

Concept introduction:

Carbohydrates are classified into two based on the presence of either aldehyde group or ketone group, that is aldose and ketose.

Monosaccharides are simple sugars or carbohydrates.

monosaccharides are classified on the basis of,

Presents of aldehyde or ketone group such as aldo or keto.

Number of carbon atoms presented in a carbohydrates, triose (3 carbon), tetrose (4 carbon), pentose (5 carbon), hexose (6 carbon) or heptose (7 carbon) (ose indicates the carbohydrates).

To classify: the given compound (a) based on whether it is aldose or ketose and the numbers of carbon atoms presented in it.

(b)

Interpretation Introduction

Interpretation:

Each of the given compounds should be classified based on whether it is aldose or ketose and the numbers of carbon atoms presented in it (example: aldopentose).

Concept introduction:

Carbohydrates are classified into two based on the presence of either aldehyde group or ketone group, that is aldose and ketose.

Monosaccharides are simple sugars or carbohydrates.

monosaccharides are classified on the basis of,

Presents of aldehyde or ketone group such as aldo or keto.

Number of carbon atoms presented in a carbohydrates, triose (3 carbon), tetrose (4 carbon), pentose (5 carbon), hexose (6 carbon) or heptose (7 carbon) (ose indicates the carbohydrates).

To classify: the given compound (b) based on whether it is aldose or ketose and the numbers of carbon atoms presented in it.

(c)

Interpretation Introduction

Interpretation:

Each of the given compounds should be classified based on whether it is aldose or ketose and the numbers of carbon atoms presented in it (example: aldopentose).

Concept introduction:

Carbohydrates are classified into two based on the presence of either aldehyde group or ketone group, that is aldose and ketose.

Monosaccharides are simple sugars or carbohydrates.

monosaccharides are classified on the basis of,

Presents of aldehyde or ketone group such as aldo or keto.

Number of carbon atoms presented in a carbohydrates, triose (3 carbon), tetrose (4 carbon), pentose (5 carbon), hexose (6 carbon) or heptose (7 carbon) (ose indicates the carbohydrates).

To classify: the given compound (c) based on whether it is aldose or ketose and the numbers of carbon atoms presented in it.

The given compound is Ketopentose.

(d)

Interpretation Introduction

Interpretation:

Each of the given compounds should be classified based on whether it is aldose or ketose and the numbers of carbon atoms presented in it (example: aldopentose).

Concept introduction:

Carbohydrates are classified into two based on the presence of either aldehyde group or ketone group, that is aldose and ketose.

Monosaccharides are simple sugars or carbohydrates.

monosaccharides are classified on the basis of,

Presents of aldehyde or ketone group such as aldo or keto.

Number of carbon atoms presented in a carbohydrates, triose (3 carbon), tetrose (4 carbon), pentose (5 carbon), hexose (6 carbon) or heptose (7 carbon) (ose indicates the carbohydrates).

To classify: the given compound (d) based on whether it is aldose or ketose and the numbers of carbon atoms presented in it.

(e)

Interpretation Introduction

Interpretation:

Each of the given compounds should be classified based on whether it is aldose or ketose and the numbers of carbon atoms presented in it (example: aldopentose).

Concept introduction:

Carbohydrates are classified into two based on the presence of either aldehyde group or ketone group, that is aldose and ketose.

Monosaccharides are simple sugars or carbohydrates.

monosaccharides are classified on the basis of,

Presents of aldehyde or ketone group such as aldo or keto.

Number of carbon atoms presented in a carbohydrates, triose (3 carbon), tetrose (4 carbon), pentose (5 carbon), hexose (6 carbon) or heptose (7 carbon) (ose indicates the carbohydrates).

To classify: the given compound (e) based on whether it is aldose or ketose and the numbers of carbon atoms presented in it.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 24.2, Problem 1CC

(a)

Interpretation Introduction

Interpretation:

Each of the given compounds should be classified based on whether it is aldose or ketose and the numbers of carbon atoms presented in it (example: aldopentose).

Concept introduction:

Carbohydrates are classified into two based on the presence of either aldehyde group or ketone group, that is aldose and ketose.

Monosaccharides are simple sugars or carbohydrates.

monosaccharides are classified on the basis of,

Presents of aldehyde or ketone group such as aldo or keto.

Number of carbon atoms presented in a carbohydrates, triose (3 carbon), tetrose (4 carbon), pentose (5 carbon), hexose (6 carbon) or heptose (7 carbon) (ose indicates the carbohydrates).

To classify: the given compound (a) based on whether it is aldose or ketose and the numbers of carbon atoms presented in it.

(b)

Interpretation Introduction

Interpretation:

Each of the given compounds should be classified based on whether it is aldose or ketose and the numbers of carbon atoms presented in it (example: aldopentose).

Concept introduction:

Carbohydrates are classified into two based on the presence of either aldehyde group or ketone group, that is aldose and ketose.

Monosaccharides are simple sugars or carbohydrates.

monosaccharides are classified on the basis of,

Presents of aldehyde or ketone group such as aldo or keto.

Number of carbon atoms presented in a carbohydrates, triose (3 carbon), tetrose (4 carbon), pentose (5 carbon), hexose (6 carbon) or heptose (7 carbon) (ose indicates the carbohydrates).

To classify: the given compound (b) based on whether it is aldose or ketose and the numbers of carbon atoms presented in it.

(c)

Interpretation Introduction

Interpretation:

Each of the given compounds should be classified based on whether it is aldose or ketose and the numbers of carbon atoms presented in it (example: aldopentose).

Concept introduction:

Carbohydrates are classified into two based on the presence of either aldehyde group or ketone group, that is aldose and ketose.

Monosaccharides are simple sugars or carbohydrates.

monosaccharides are classified on the basis of,

Presents of aldehyde or ketone group such as aldo or keto.

Number of carbon atoms presented in a carbohydrates, triose (3 carbon), tetrose (4 carbon), pentose (5 carbon), hexose (6 carbon) or heptose (7 carbon) (ose indicates the carbohydrates).

To classify: the given compound (c) based on whether it is aldose or ketose and the numbers of carbon atoms presented in it.

The given compound is Ketopentose.

(d)

Interpretation Introduction

Interpretation:

Each of the given compounds should be classified based on whether it is aldose or ketose and the numbers of carbon atoms presented in it (example: aldopentose).

Concept introduction:

Carbohydrates are classified into two based on the presence of either aldehyde group or ketone group, that is aldose and ketose.

Monosaccharides are simple sugars or carbohydrates.

monosaccharides are classified on the basis of,

Presents of aldehyde or ketone group such as aldo or keto.

Number of carbon atoms presented in a carbohydrates, triose (3 carbon), tetrose (4 carbon), pentose (5 carbon), hexose (6 carbon) or heptose (7 carbon) (ose indicates the carbohydrates).

To classify: the given compound (d) based on whether it is aldose or ketose and the numbers of carbon atoms presented in it.

(e)

Interpretation Introduction

Interpretation:

Each of the given compounds should be classified based on whether it is aldose or ketose and the numbers of carbon atoms presented in it (example: aldopentose).

Concept introduction:

Carbohydrates are classified into two based on the presence of either aldehyde group or ketone group, that is aldose and ketose.

Monosaccharides are simple sugars or carbohydrates.

monosaccharides are classified on the basis of,

Presents of aldehyde or ketone group such as aldo or keto.

Number of carbon atoms presented in a carbohydrates, triose (3 carbon), tetrose (4 carbon), pentose (5 carbon), hexose (6 carbon) or heptose (7 carbon) (ose indicates the carbohydrates).

To classify: the given compound (e) based on whether it is aldose or ketose and the numbers of carbon atoms presented in it.

Answer 6

Chapter 24.2, Problem 1CC

(a)

Interpretation Introduction

Interpretation:

Each of the given compounds should be classified based on whether it is aldose or ketose and the numbers of carbon atoms presented in it (example: aldopentose).

Concept introduction:

Carbohydrates are classified into two based on the presence of either aldehyde group or ketone group, that is aldose and ketose.

Monosaccharides are simple sugars or carbohydrates.

monosaccharides are classified on the basis of,

Presents of aldehyde or ketone group such as aldo or keto.

Number of carbon atoms presented in a carbohydrates, triose (3 carbon), tetrose (4 carbon), pentose (5 carbon), hexose (6 carbon) or heptose (7 carbon) (ose indicates the carbohydrates).

To classify: the given compound (a) based on whether it is aldose or ketose and the numbers of carbon atoms presented in it.

Answer 7

Chapter 24.2, Problem 1CC

(a)

Interpretation Introduction

Interpretation:

Each of the given compounds should be classified based on whether it is aldose or ketose and the numbers of carbon atoms presented in it (example: aldopentose).

Concept introduction:

Carbohydrates are classified into two based on the presence of either aldehyde group or ketone group, that is aldose and ketose.

Monosaccharides are simple sugars or carbohydrates.

monosaccharides are classified on the basis of,

Presents of aldehyde or ketone group such as aldo or keto.

Number of carbon atoms presented in a carbohydrates, triose (3 carbon), tetrose (4 carbon), pentose (5 carbon), hexose (6 carbon) or heptose (7 carbon) (ose indicates the carbohydrates).

To classify: the given compound (a) based on whether it is aldose or ketose and the numbers of carbon atoms presented in it.

Answer 8

(b)

Interpretation Introduction

Interpretation:

Each of the given compounds should be classified based on whether it is aldose or ketose and the numbers of carbon atoms presented in it (example: aldopentose).

Concept introduction:

Carbohydrates are classified into two based on the presence of either aldehyde group or ketone group, that is aldose and ketose.

Monosaccharides are simple sugars or carbohydrates.

monosaccharides are classified on the basis of,

Presents of aldehyde or ketone group such as aldo or keto.

Number of carbon atoms presented in a carbohydrates, triose (3 carbon), tetrose (4 carbon), pentose (5 carbon), hexose (6 carbon) or heptose (7 carbon) (ose indicates the carbohydrates).

To classify: the given compound (b) based on whether it is aldose or ketose and the numbers of carbon atoms presented in it.

Answer 9

(b)

Interpretation Introduction

Interpretation:

Each of the given compounds should be classified based on whether it is aldose or ketose and the numbers of carbon atoms presented in it (example: aldopentose).

Concept introduction:

Carbohydrates are classified into two based on the presence of either aldehyde group or ketone group, that is aldose and ketose.

Monosaccharides are simple sugars or carbohydrates.

monosaccharides are classified on the basis of,

Presents of aldehyde or ketone group such as aldo or keto.

Number of carbon atoms presented in a carbohydrates, triose (3 carbon), tetrose (4 carbon), pentose (5 carbon), hexose (6 carbon) or heptose (7 carbon) (ose indicates the carbohydrates).

To classify: the given compound (b) based on whether it is aldose or ketose and the numbers of carbon atoms presented in it.

Answer 10

(c)

Interpretation Introduction

Interpretation:

Each of the given compounds should be classified based on whether it is aldose or ketose and the numbers of carbon atoms presented in it (example: aldopentose).

Concept introduction:

Carbohydrates are classified into two based on the presence of either aldehyde group or ketone group, that is aldose and ketose.

Monosaccharides are simple sugars or carbohydrates.

monosaccharides are classified on the basis of,

Presents of aldehyde or ketone group such as aldo or keto.

Number of carbon atoms presented in a carbohydrates, triose (3 carbon), tetrose (4 carbon), pentose (5 carbon), hexose (6 carbon) or heptose (7 carbon) (ose indicates the carbohydrates).

To classify: the given compound (c) based on whether it is aldose or ketose and the numbers of carbon atoms presented in it.

The given compound is Ketopentose.

Answer 11

(c)

Interpretation Introduction

Interpretation:

Each of the given compounds should be classified based on whether it is aldose or ketose and the numbers of carbon atoms presented in it (example: aldopentose).

Concept introduction:

Carbohydrates are classified into two based on the presence of either aldehyde group or ketone group, that is aldose and ketose.

Monosaccharides are simple sugars or carbohydrates.

monosaccharides are classified on the basis of,

Presents of aldehyde or ketone group such as aldo or keto.

Number of carbon atoms presented in a carbohydrates, triose (3 carbon), tetrose (4 carbon), pentose (5 carbon), hexose (6 carbon) or heptose (7 carbon) (ose indicates the carbohydrates).

To classify: the given compound (c) based on whether it is aldose or ketose and the numbers of carbon atoms presented in it.

The given compound is Ketopentose.

Answer 12

(d)

Interpretation Introduction

Interpretation:

Each of the given compounds should be classified based on whether it is aldose or ketose and the numbers of carbon atoms presented in it (example: aldopentose).

Concept introduction:

Carbohydrates are classified into two based on the presence of either aldehyde group or ketone group, that is aldose and ketose.

Monosaccharides are simple sugars or carbohydrates.

monosaccharides are classified on the basis of,

Presents of aldehyde or ketone group such as aldo or keto.

Number of carbon atoms presented in a carbohydrates, triose (3 carbon), tetrose (4 carbon), pentose (5 carbon), hexose (6 carbon) or heptose (7 carbon) (ose indicates the carbohydrates).

To classify: the given compound (d) based on whether it is aldose or ketose and the numbers of carbon atoms presented in it.

Answer 13

(d)

Interpretation Introduction

Interpretation:

Each of the given compounds should be classified based on whether it is aldose or ketose and the numbers of carbon atoms presented in it (example: aldopentose).

Concept introduction:

Carbohydrates are classified into two based on the presence of either aldehyde group or ketone group, that is aldose and ketose.

Monosaccharides are simple sugars or carbohydrates.

monosaccharides are classified on the basis of,

Presents of aldehyde or ketone group such as aldo or keto.

Number of carbon atoms presented in a carbohydrates, triose (3 carbon), tetrose (4 carbon), pentose (5 carbon), hexose (6 carbon) or heptose (7 carbon) (ose indicates the carbohydrates).

To classify: the given compound (d) based on whether it is aldose or ketose and the numbers of carbon atoms presented in it.

Answer 14

(e)

Interpretation Introduction

Interpretation:

Each of the given compounds should be classified based on whether it is aldose or ketose and the numbers of carbon atoms presented in it (example: aldopentose).

Concept introduction:

Carbohydrates are classified into two based on the presence of either aldehyde group or ketone group, that is aldose and ketose.

Monosaccharides are simple sugars or carbohydrates.

monosaccharides are classified on the basis of,

Presents of aldehyde or ketone group such as aldo or keto.

Number of carbon atoms presented in a carbohydrates, triose (3 carbon), tetrose (4 carbon), pentose (5 carbon), hexose (6 carbon) or heptose (7 carbon) (ose indicates the carbohydrates).

To classify: the given compound (e) based on whether it is aldose or ketose and the numbers of carbon atoms presented in it.

Answer 15

(e)

Interpretation Introduction

Interpretation:

Each of the given compounds should be classified based on whether it is aldose or ketose and the numbers of carbon atoms presented in it (example: aldopentose).

Concept introduction:

Carbohydrates are classified into two based on the presence of either aldehyde group or ketone group, that is aldose and ketose.

Monosaccharides are simple sugars or carbohydrates.

monosaccharides are classified on the basis of,

Presents of aldehyde or ketone group such as aldo or keto.

Number of carbon atoms presented in a carbohydrates, triose (3 carbon), tetrose (4 carbon), pentose (5 carbon), hexose (6 carbon) or heptose (7 carbon) (ose indicates the carbohydrates).

To classify: the given compound (e) based on whether it is aldose or ketose and the numbers of carbon atoms presented in it.

Answer 16

Expert Solution & Answer

Answer 17

Expert Solution & Answer

Answer 18

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 19

Ch. 24.2 - Prob. 1CC Ch. 24.2 - Prob. 2CC Ch. 24.2 - Prob. 3CC Ch. 24.2 - Prob. 4CC Ch. 24.2 - Prob. 5CC Ch. 24.2 - Prob. 6CC Ch. 24.4 - Prob. 7CC Ch. 24.4 - Prob. 8CC Ch. 24.5 - Prob. 1LTS Ch. 24.5 - Prob. 9PTS

Want to see the full answer?

Chapter 24 Solutions