(a)
Interpretation:
Haworth projection for given compounds should be drawn.
Concept introduction:
The Haworth projection: A Haworth projection is a three-dimensional representation of monosaccharides and the structural formula is inscription as a cyclic structures.
In Haworth projection, oxygen atom is placed in back right corner,
Furanose: A five-member closed chain form of a monosaccharide.
Pyranose: A six-member cyclic form of a monosaccharide.
To find: Haworth projection for given molecule
(b)
Interpretation:
Haworth projection for given compounds should be drawn.
Concept introduction:
The Haworth projection: A Haworth projection is a three-dimensional representation of monosaccharides and the structural formula is inscription as a cyclic structures.
In Haworth projection, oxygen atom is placed in back right corner,
Furanose: A five-member closed chain form of a monosaccharide.
Pyranose: A six-member cyclic form of a monosaccharide.
To find: Haworth projection for given molecule
(c)
Interpretation:
Haworth projection for given compounds should be drawn.
Concept introduction:
The Haworth projection: A Haworth projection is a three-dimensional representation of monosaccharides and the structural formula is inscription as a cyclic structures.
In Haworth projection, oxygen atom is placed in back right corner,
Furanose: A five-member closed chain form of a monosaccharide.
Pyranose: A six-member cyclic form of a monosaccharide.
To find: Haworth projection for given molecule
(d)
Interpretation:
Haworth projection for given compounds should be drawn.
Concept introduction:
The Haworth projection: A Haworth projection is a three-dimensional representation of monosaccharides and the structural formula is inscription as a cyclic structures.
In Haworth projection, oxygen atom is placed in back right corner,
Furanose: A five-member closed chain form of a monosaccharide.
Pyranose: A six-member cyclic form of a monosaccharide.
To find: Haworth projection for given molecule
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Chapter 24 Solutions
Organic Chemistry
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