
a)
Interpretation:
The type of interaction hold by double helical strand together has to be found.
Concept introduction: Hydrogen bond- Hydrogen bond is the non-covalent bond which consists of hydrogen atom. Hydrogen bond forms the reversible bond between different hydrophilic groups. When two sides chains are react they release water molecule. This is a weak bond.
Stacking interaction: Stacking interaction is the non-covalent interaction. These interactions are electrostatic and hydrophobic in nature. Stacking interaction depends on their dipole moments and
Inter-strand stacking interaction.
- a) Intra-strand stacking interaction.
For identify the stabilizing effects of base stacking, base pairs are consider more important instead of individual bases .This is the non-covalent and weak interaction consists of hydrogen atom and one donor and acceptor atoms.
b)
Interpretation:
The covalent bond interaction hold by double helical strand together is not good; the reason has to be found.
Concept introduction: Hydrogen bond- Hydrogen bond is the non-covalent bond which consists of hydrogen atom. Hydrogen bond forms the reversible bond between different hydrophilic groups. When two sides chains are react they release water molecule. This is a weak bond.
Stacking interaction: Stacking interaction is the non-covalent interaction. These interactions are electrostatic and hydrophobic in nature. Stacking interaction depends on their dipole moments and aromaticity of bases. Two types of interaction found in nucleic acid double strand:
Stacking interaction is the non-covalent interaction. These interactions are electrostatic and hydrophobic in nature. Stacking interaction depends on their dipole moments and aromaticity of bases. Two types of interaction found in nucleic acid double strand:
- a) Inter-strand stacking interaction.
- b) Intra-strand stacking interaction.
For identify the stabilizing effects of base stacking, base pairs are consider more important instead of individual bases .This is the non-covalent and weak interaction consists of hydrogen atom and one donor and acceptor atoms.

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Chapter 24 Solutions
Chemistry & Chemical Reactivity, Hybrid Edition (with OWLv2 24-Months Printed Access Card)
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- 2. (3 pts) Consider the unit cell for the spinel compound, CrFe204. How many total particles are in the unit cell? Also, show how the number of particles and their positions are consistent with the CrFe204 stoichiometry - this may or may not be reflected by the particle colors in the diagram. (HINT: In the diagram, the blue particle is in an interior position while each red particle is either in a corner or face position.)arrow_forwardFrom the following potentials, calculate the activity of Cl- in saturated KCl. E0 (calomel electrode)= 0.268 V E (calomel electrode, saturated KCl)= 0.241 Varrow_forwardCalculate the voltage of each of the following cells. a) Fe(s)/Fe2+ (1.55 x 10-2 M)//Cu2+ (6.55 x 10-3 M)/Cu(s) b) Pt, H2 (0.255 bar)/HCl (4.55 x 10-4 M), AgCl (sat'd)/Ag Fe2+ +2e- = Fe E0= -0.44 V Cu2+ + 2e- = Cu E0= 0.337 V Ag+ + e- = Ag E0= 0.799 V AgCl(s) + e- = Ag(s) + Cl- E0= 0.222 V 2H+ + 2e- = H2 E0= 0.000 Varrow_forward
- A solution contains 0.097 M Ce3+, 1.55x10-3 M Ce4+, 1.55x10-3 M Mn2+, 0.097 M MnO4-, and 1.00 M HClO4 (F= 9.649 x 104 C/mol). a) Write a balanced net reaction that can occur between species in this solution. b) Calculate deltaG0 and K for the reaction. c) Calculate E and deltaG for the conditions given. Ce4+ + e- = Ce3+ E0= 1.70 V MnO4- + 8H+ + 5e- = Mn2+ + 4H2O E0= 1.507 Varrow_forward1. Provide a step-by-step mechanism for formation of ALL STEREOISOMERS in the following reaction. Na HCO3 (Sodium bicarbonate, baking soda) is not soluble in CH2Cl2. The powder is a weak base used to neutralize strong acid (pKa < 0) produced by the reaction. Redraw the product to show the configuration(s) that form at C-2 and C-4. Br2 OH CH2Cl2 Na* HCO3 Br HO OH + Na Br +arrow_forward2. Specify the solvent and reagent(s) required to carry out each of the following FGI. If two reagent sets must be used for the FGI, specify the solvent and reagent(s) for each reagent set. If a reaction cannot be carried out with reagents (sets) class, write NP (not possible) in the solvent box for reagent set #1. Use the letter abbreviation for each solvent; use a number abbreviation for reagent(s). Solvents: CH2Cl2 (A); H₂O (B); Reagents: HBr (1); R₂BH (6); H2SO4 (2); CH3OH (C); Br₂ (3); CH3CO₂H (D) NaHCO3 (4); Hg(OAc)2 (5); H₂O2/HO (7); NaBH4 (8) Reagent Set #1 Reagent Set #2 FGI + enant OH Solvent Reagent(s) Solvent Reagent(s)arrow_forward
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