EBK MANUFACTURING ENGINEERING & TECHNOL
7th Edition
ISBN: 8220100793431
Author: KALPAKJIAN
Publisher: PEARSON
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Chapter 24, Problem 33QLP
Describe the parts and conditions under which broaching would be the preferred method of machining.
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1. In a production turning operation, the cylindrical workpiece is 425 mm long and 190 mm
in diameter, Feed 0.30 mm/rev. What cutting speed must be used to achieve a machining
time of 7.0 min?
Determine the total machining time for a workpiece 30mm in diameter and the
required length is 145 mm. Other data:
Material: 38mm dia. X 149 mm
Depth of cut (turning): 4mm
Depth of cut (facing): 2mm
Feed
: 0.05 mm/rev
: 35 SMPM
Cutting speed
Make a figure and explain how shear plane angle effect the power requirements in the machining. How can you reduce the power requirements during machining in orthogonal cutting?
plzz do it in 45 minutes
Chapter 24 Solutions
EBK MANUFACTURING ENGINEERING & TECHNOL
Ch. 24 - Explain why milling is such a versatile machining...Ch. 24 - Describe a milling machine. How is it different...Ch. 24 - Describe the different types of cutters used in...Ch. 24 - Define the following: face milling, peripheral...Ch. 24 - Can threads be machined on a mill? Explain.Ch. 24 - What is the difference between feed and feed per...Ch. 24 - Explain the relative characteristics of climb...Ch. 24 - Describe the geometric features of a broach and...Ch. 24 - What is a pull broach? A push broach?Ch. 24 - Why is sawing a commonly used process? Why do some...
Ch. 24 - What advantages do bed-type milling machines have...Ch. 24 - Explain why the axis of a hob is tilted with...Ch. 24 - What is a shell mill? Why is it used?Ch. 24 - Why is it difficult to saw thin sheet metals?Ch. 24 - Of the processes depicted in Fig. 24.2, which is...Ch. 24 - Describe the tool motion during gear shaping.Ch. 24 - When is filing necessary?Ch. 24 - Would you consider the machining processes...Ch. 24 - Why is end milling such an important versatile...Ch. 24 - List and explain factors that contribute to poor...Ch. 24 - Explain why broaching crankshaft bearings is an...Ch. 24 - Several guidelines are presented in this chapter...Ch. 24 - What are the advantages of helical teeth over...Ch. 24 - Explain why hacksaws are not as productive as band...Ch. 24 - What similarities and differences are there in...Ch. 24 - Why do machined gears have to be subjected to...Ch. 24 - How would you reduce the surface roughness shown...Ch. 24 - Why are machines such as the one shown in Fig....Ch. 24 - Comment on your observations concerning the...Ch. 24 - Explain how contour cutting could be started in a...Ch. 24 - Prob. 32QLPCh. 24 - Describe the parts and conditions under which...Ch. 24 - Explain the reason that it is difficult to use...Ch. 24 - Would you recommend broaching a keyway on a gear...Ch. 24 - Prob. 37QTPCh. 24 - A slab-milling operation is being performed at a...Ch. 24 - Show that the distance lc in slab milling is...Ch. 24 - Prob. 40QTPCh. 24 - Calculate the chip depth of cut, tc, and the...Ch. 24 - Estimate the time required to face mill a...Ch. 24 - A 12-in.-long, 1-in.-thick plate is being cut on a...Ch. 24 - A single-thread hob is used to cut 40 teeth on a...Ch. 24 - Assume that m the face-milling operation shown in...Ch. 24 - A slab-milling operation will take place on a part...Ch. 24 - Prob. 47QTPCh. 24 - In describing the broaching operations and the...Ch. 24 - The parts shown in Fig. 24.1 are to be machined...Ch. 24 - Would you prefer to machine the part in Fig. 24....Ch. 24 - Prob. 51SDPCh. 24 - Suggest methods whereby milling cutters of various...Ch. 24 - Prepare a comprehensive table of the process...Ch. 24 - Prob. 55SDPCh. 24 - Make a list of all the processes that can be used...
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- Electroforming is an example of secondary machining process. Select one: True Falsearrow_forward0. In a single point turning operation with a cemented carbide and steel combination having a Taylor exponent of 0.25, if the cutting speed is halved, then tool life will becomearrow_forwardProblem 2. (Determining Cutting Speeds in Machining Economics) A turning operation is performed with HSS tooling on mild steel, with Taylor tool life parameters n = 0.12, C = 60 m/min. Work part length = 450 mm and diameter = 80 mm. Feed = 0.20 mm/rev. Handling time per piece = 4.0 min, and tool change time = 1.5 min. Cost of machine and operator = $27/hr, and tooling cost = $2 per cutting edge. Find the a. cutting speed for maximum production rate = 44.997m/min. b. cutting speed for minimum cost = 38.143m/min. Problem 3. (Production Rate and Cost in Machining Economics) For the two cutting speeds computed in problem 2, determine: a. the hourly production rate and b. the cost per piece. Need help with problem 3 already done problem 2arrow_forward
- Problem 2. (Determining Cutting Speeds in Machining Economics) A turning operation is performed with HSS tooling on mild steel, with Taylor tool life parameters n = 0.12, C = 60 m/min. Work part length = 450 mm and diameter = 80 mm. Feed = 0.20 mm/rev. Handling time per piece = 4.0 min, and tool change time = 1.5 min. Cost of machine and operator = $27/hr, and tooling cost = $2 per cutting edge. Find the a. cutting speed for maximum production rate and b. cutting speed for minimum cost Problem 3. (Production Rate and Cost in Machining Economics) For the two cutting speeds computed in problem 2, determine: the hourly production rate and a. b. the cost per piece.arrow_forwardWhats the answer for this please ?arrow_forwardwhat are the three basic parameters (cutting variables) in the machining process? how to calculate themarrow_forward
- 1. What are the factors that affect the machining quality (including machining accuracy and surface quality)?arrow_forwardMake a figure and explain how shear plane angle effect the power requirements in the machining. How can you reduce the power requirements during machining in orthogonal cutting?arrow_forward(b). A hole of 30 mm diameter and 75 mm depth is to be drilled. The suggested feed is 1.3 mm per rev and the cutting speed is 62 m/ min. assuming tool approach and tool overtravel as 6 mm, determine: i. spindle rpm ii. feed speed iii. cutting time iv. material removal ratearrow_forward
- Q3). A block of 190mm length and 100mm width is to be machined in shaping process. The permissible cutting speed is 30m/min. maximum quick return ratio is 3:2 at the design value of stroke of 400mm. Calculate the time of machining of the block, assuming total depth of cut to be 8mm, L=1₂+1+1, 40+190+20=250mm, B=ba+b+bo=10+100+10=120mm?arrow_forwardIn turning of stales steel alloy, 1100 mm length and 400 mm diameter, the Feed was 0.35 mm/rev, and depth of cut = 2.5 mm. The tool used in this cutting is cemented carbide tool where Taylor tool life parameters are n = 0.24 and C = 450 (tool life (min) and cutting speed (m/min). Compute the cutting speed that will allow the tool life to be 10% longer than the machining time for this part.arrow_forwardWhich of the following is one of the disadvantages of machining methods? 1-Variety of machinable part material 2-Variety of piece shapes and special geometric fomms 3-High dimensional accuracy and surface quality (Aşağıdakilerden hangisi talaşlı imalat yöntemlerinin dezavantajlarındand ir? 1-İşlenebilen parça malzemesinin çeşitliliği 2-Parça şekillerinin ve özel geometrik formların çeşitliliği 3-Yüksek boyutsal doğruluk ve yüzey kalitesi ) 16 - O A) Only 3 (Yalnız 3) B) Only 1 (Yalnız 1) ) None (Hiçbiri) O D All (Heps i) O E Only 2((Yalnz 2)arrow_forward
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