EBK MANUFACTURING ENGINEERING & TECHNOL
7th Edition
ISBN: 8220100793431
Author: KALPAKJIAN
Publisher: PEARSON
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Textbook Question
Chapter 24, Problem 6RQ
What is the difference between feed and feed per tooth? Can they ever be the same?
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Q1\ a) The operation of drilling is to be done with a 25.4 mm ( diameter) twist drill in a brass
workpiece. The hole is a blind-hole with the point angle = 118°, and a depth of 50 mm . The speed
of 25 m/min, feed of 0.25 mm/rev. Calculate: (1) the time of cutting to complete the drilling
operation, and (2) metal removal rate during the operation.
Identify and explain the method of milling process in which the stresses on the teeth is maximum at the end of the cut with neat diagram.
A 0.4-inch diameter bit is used in a vertical or vertical drill that operates at 300 rpm. If the feed is 0.005 in / rev, what is the MRR? What is the MRR if the drill diameter is doubled? What is the power required in the drill if the material is an annealed AISI 1080?
Chapter 24 Solutions
EBK MANUFACTURING ENGINEERING & TECHNOL
Ch. 24 - Explain why milling is such a versatile machining...Ch. 24 - Describe a milling machine. How is it different...Ch. 24 - Describe the different types of cutters used in...Ch. 24 - Define the following: face milling, peripheral...Ch. 24 - Can threads be machined on a mill? Explain.Ch. 24 - What is the difference between feed and feed per...Ch. 24 - Explain the relative characteristics of climb...Ch. 24 - Describe the geometric features of a broach and...Ch. 24 - What is a pull broach? A push broach?Ch. 24 - Why is sawing a commonly used process? Why do some...
Ch. 24 - What advantages do bed-type milling machines have...Ch. 24 - Explain why the axis of a hob is tilted with...Ch. 24 - What is a shell mill? Why is it used?Ch. 24 - Why is it difficult to saw thin sheet metals?Ch. 24 - Of the processes depicted in Fig. 24.2, which is...Ch. 24 - Describe the tool motion during gear shaping.Ch. 24 - When is filing necessary?Ch. 24 - Would you consider the machining processes...Ch. 24 - Why is end milling such an important versatile...Ch. 24 - List and explain factors that contribute to poor...Ch. 24 - Explain why broaching crankshaft bearings is an...Ch. 24 - Several guidelines are presented in this chapter...Ch. 24 - What are the advantages of helical teeth over...Ch. 24 - Explain why hacksaws are not as productive as band...Ch. 24 - What similarities and differences are there in...Ch. 24 - Why do machined gears have to be subjected to...Ch. 24 - How would you reduce the surface roughness shown...Ch. 24 - Why are machines such as the one shown in Fig....Ch. 24 - Comment on your observations concerning the...Ch. 24 - Explain how contour cutting could be started in a...Ch. 24 - Prob. 32QLPCh. 24 - Describe the parts and conditions under which...Ch. 24 - Explain the reason that it is difficult to use...Ch. 24 - Would you recommend broaching a keyway on a gear...Ch. 24 - Prob. 37QTPCh. 24 - A slab-milling operation is being performed at a...Ch. 24 - Show that the distance lc in slab milling is...Ch. 24 - Prob. 40QTPCh. 24 - Calculate the chip depth of cut, tc, and the...Ch. 24 - Estimate the time required to face mill a...Ch. 24 - A 12-in.-long, 1-in.-thick plate is being cut on a...Ch. 24 - A single-thread hob is used to cut 40 teeth on a...Ch. 24 - Assume that m the face-milling operation shown in...Ch. 24 - A slab-milling operation will take place on a part...Ch. 24 - Prob. 47QTPCh. 24 - In describing the broaching operations and the...Ch. 24 - The parts shown in Fig. 24.1 are to be machined...Ch. 24 - Would you prefer to machine the part in Fig. 24....Ch. 24 - Prob. 51SDPCh. 24 - Suggest methods whereby milling cutters of various...Ch. 24 - Prepare a comprehensive table of the process...Ch. 24 - Prob. 55SDPCh. 24 - Make a list of all the processes that can be used...
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- How did you find out the angle was 90 and how can you find that for other problems?arrow_forwardThe outline of the part in the Figure below is to be profile milled using a 20- mm diameter end mill with two teeth. The part is 10 mm thick. The cutting speed = 125 m/min and feed = 0.10 mm/tooth. The part is also to be drilled with a drill size of 10 mm corresponds to T01 with a cutting speed =75 mm/min and feed = 0.08 mm/rev. The two holes pass completely through the part. 30 rad. 125.75 10 dia., 2 holes Write the part program (G & M code program) for the required machining processes. Use absolute programming with the lower left 25 corner of the part as the origin in the x-y axis system. 150 (All dimensions are in mm.) 25 50 75 35 deg.arrow_forwardWhats the answer for this please ?arrow_forward
- Please need within 30 min Thank you.arrow_forwardIn a production turning operation, the workpart is 60 mm in diameter and 500 mm long. A feed of 0.75 mm/rev is used in the operation. If cutting speed=9 m/s, the tool must be changed every 4 workparts; But if cutting speed=5 m/s, the tool can be used to produce 50 pieces between tool changes. Determine the Taylor tool life equation for this job. (use the equations given below for solution)arrow_forwardPuanlar) 16 The outside diameter of a cylinder made of titanium alloy is to be turned. The starting diameter is 400 mm and the length is 1100 mm. The feed is 0.35 mm/rev and the depth of cut is 2.5 mm. The cut will be made with a cemented carbide cutting tool whose Taylor tool life parameters are: n= 0.24 and C=450. Units for the Taylor equation are min for tool life and m/min for cutting speed. Compute the cutting speed that will allow the tool life to be just equal to the cutting time for this part. V vT" = C. %3D Ce Tm 1. %3D 19 fv 25 31 37 43 49 187.9 m/min b) 325.8 m /min 275.8 m/min d) 226.6 m/minarrow_forward
- Please answer all partsarrow_forwardA 12" through hole is to be drilled in a 1 inch thick steel plate. A standard twist drill having a nose angle of 120 degrees is to be used. The drill press is set to operate at a cutting speed of 20 feet per minute and a feed of 0.010 ipr. What is the machining time required to drill the hole?arrow_forwardWhich of the following is the example of cutting shaping process? O Pressing O Forging O Knurling O Drawingarrow_forward
- In a production turning operation, the workpart is 60 mm in diameter and 500 mm long. A feed of 0.75 mm/rev is used in the operation. If cutting speed=9 m/s, the tool must be changed every 4 workparts; But if cutting speed=5 m/s, the tool can be used to produce 50 pieces between tool changes. Determine the Taylor tool life equation for this job. (use the equations given below for solution)arrow_forwardIn a production turning operation, the workpart is 60 mm in diameter and 500 mm long. A feed of 0.75 mm/rev is used in the operation. If cutting speed-9 m/s, the tool must be changed every 4 workparts; But if cutting speed=5 m/s, the tool can be used to produce 50 pieces between tool changes. Determine the Taylor tool life equation for this job. (use the equations given below for solution) L Tm- 1,= Nf N AD, vT" = C %3| AD,L Tm fvarrow_forwardRead the sentences given below and Identify the correct statement. Sentence 1. The advantage of a self-centred chuck is that it is easy to work with. Sentence 2. The advantage of an independent chuck is that the work can be centred to high precision. Sentence 1 and 2 are true Sentence 1 is true None of the sentences are true Sentence 2 is truearrow_forward
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